## Java beginner here getting non zero numbers

I just want to ask why the `temp`

in my method `NonZeros`

does not change its elements even though I explicitly assign each element of `temp`

whenever the source has a nonzero element. Here's my work.

package nonzeros; public class NonZeros { public static void main(String[] args) { int [] B = {0,1,2,3,2}; int [] newone = NonZeros(B); for(int q = 0; q < newone.length; q++){ System.out.println(newone[q]); } } public static int[] NonZeros(int [] A){ int [] temp = new int[4]; for(int i = 0; i < A.length;i++){ if(A[i] != 0){ int j = 0; temp[j] = A[i]; j++; } } return temp; } }

Here's the result: run: 2 0 0 0

However, the result should be: 1 2 3 2

Step one, count the non zero values. Step two, create the new array. Step three, fill it with non-zero values like

public static int[] NonZeros(int[] A) { int count = 0; for (int i = 0; i < A.length; i++) { if (A[i] != 0) { count++; } } int[] temp = new int[count]; int p = 0; for (int i = 0; i < A.length; i++) { if (A[i] != 0) { temp[p++] = A[i]; } } return temp; }

Alternatively, use a lambda and filter like

public static int[] NonZeros(int[] A) { return Arrays.stream(A).filter(i -> i != 0).toArray(); }

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You declare `int j=0;`

*inside* the loop, so all assignments go to the same place.

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You need to move the `j`

index outside of the loop:

public static int[] NonZeros(int [] A){ int [] temp = new int[4]; int j = 0; for (int i=0; i < A.length; i++) { if (A[i] != 0) { temp[j] = A[i]; j++; } } return temp; }

The reason why your current output happens to be `[2, 0, 0, 0]`

is that the final element in the input array is 2, and gets written to the first entry in the output array. In fact, currently *all* values are being written to the first entry of the output array.

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The scope of the "j" variable that you are defining is the if block that contains it because you are declaring it inside the condition which results in you overwriting the first element in your temp array each time you find a non-zero number in the source while the rest of your temp elements remain unchanged. The solution is to move the declaration of "j" to the body of the method just before the loop, that is:

public static int[] NonZeros(int [] A){ int [] temp = new int[4]; int j = 0; for(int i = 0; i < A.length;i++){ if(A[i] != 0){ temp[j] = A[i]; j++; } } return temp; }

**Find the numbers from 1 to N that contains exactly k non-zero digits ,** A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and The Java.lang.Integer.numberOfTrailingZeros() is the method which returns the total number of zero(0) bits following the lowest-order (ie.Rightmost or least significant “1” bit)one-bit in the two’s complement binary representation of the specified integer value or we can say that it is the function which converts int value to Binary then considers the lowest one bit and return no. of

**2 Examples to Add Zeros at the Beginning of a Number in Java ,** Earlier we have learned about formatting floating point numbers in Java and that 4 denotes length of formatted String, this will ensure that right number of zero You can play with this code by changing each of these meta data to get a feel of it. Here is a screenshot of how this method add zeros at front of various input Java is following known math facts. 1.0 / 0.0 is infinity, but the others are indeterminate forms, which Java represents as NaN (not a number).

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