Appending values to dictionary from list with for loops

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I am attempting to append values to a dictionaries that list elements. I am trying to pull these values from a list, however they are only returning the same value in every dictionary.

Here is my code:

# Use a for loop to create a list of dictionaries with the associated information.
providers = ["Level3", "Verisign", "Google", "Quad9", "DNS.WATCH",
             "Comodo Secure DNS", "OpenDNS Home", "Norton ConnectSafe",
             "GreenTeamDNS", "SafeDNS", "OpenNIC", "SmartViper", "Dyn",
             "FreeDNS", "Alternate DNS", "Yandex.DNS", "UncensoredDNS",
             "Hurricane Electric", "puntCAT", "Neustar", "Cloudflare",
             "Fourth Estate"]

ips = ["209.244.0.3", "64.6.64.6", "8.8.8.8", "9.9.9.9", "84.200.69.80",
       "8.26.56.26", "208.67.222.222", "199.85.126.10", "81.218.119.11",
       "195.46.39.39", "69.195.152.204", "208.76.50.50", "216.146.35.35",
       "37.235.1.174", "198.101.242.72", "77.88.8.8", "91.239.100.100",
       "74.82.42.42", "109.69.8.51", "156.154.70.1", "1.1.1.1", "45.77.165.194"]

#Use a for loop to create a dictionary mapping the provider names to their IPs.

dic = {k:v for k,v in zip(providers, ips)}

print(dic["Hurricane Electric"])
#Print Hurricane Electric's IPs using the dictionary.

#Use a for loop to create a list of dictionaries with the associated information.

#create dictionary within list_of_dicts

list_of_dicts = [{} for isp in providers]
print(list_of_dicts)

for dicts in list_of_dicts:
    #append k:v
    #loop through lists to pull values
    for k,v in dic.items():
        dicts["provider"] = [k]
print(list_of_dicts)

Here is my output:

74.82.42.42
[{}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {}]
[{'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}, {'provider': ['Neustar']}]

Expected output:

[{'provider_name': 'Level3'}, {'primary_server': '209.244.0.3'}, ...]

I think this does what you want:

# Use a for loop to create a list of dictionaries with the associated information.
providers = ["Level3", "Verisign", "Google", "Quad9", "DNS.WATCH",
             "Comodo Secure DNS", "OpenDNS Home", "Norton ConnectSafe",
             "GreenTeamDNS", "SafeDNS", "OpenNIC", "SmartViper", "Dyn",
             "FreeDNS", "Alternate DNS", "Yandex.DNS", "UncensoredDNS",
             "Hurricane Electric", "puntCAT", "Neustar", "Cloudflare",
             "Fourth Estate"]

ips = ["209.244.0.3", "64.6.64.6", "8.8.8.8", "9.9.9.9", "84.200.69.80",
       "8.26.56.26", "208.67.222.222", "199.85.126.10", "81.218.119.11",
       "195.46.39.39", "69.195.152.204", "208.76.50.50", "216.146.35.35",
       "37.235.1.174", "198.101.242.72", "77.88.8.8", "91.239.100.100",
       "74.82.42.42", "109.69.8.51", "156.154.70.1", "1.1.1.1", "45.77.165.194"]

#Use a for loop to create a dictionary mapping the provider names to their IPs.

#create dictionary within list_of_dicts

list_of_dicts = []
for k, v in zip(providers, ips):
    list_of_dicts.extend([{'provider': k}, {'primary_server': v}])

print(list_of_dicts)

Output:

[{'provider': 'Level3'}, {'primary_server': '209.244.0.3'}, {'provider': 'Verisign'}, {'primary_server': '64.6.64.6'}, {'provider': 'Google'}, {'primary_server': '8.8.8.8'}, {'provider': 'Quad9'}, {'primary_server': '9.9.9.9'}, {'provider': 'DNS.WATCH'}, {'primary_server': '84.200.69.80'}, {'provider': 'Comodo Secure DNS'}, {'primary_server': '8.26.56.26'}, {'provider': 'OpenDNS Home'}, {'primary_server': '208.67.222.222'}, {'provider': 'Norton ConnectSafe'}, {'primary_server': '199.85.126.10'}, {'provider': 'GreenTeamDNS'}, {'primary_server': '81.218.119.11'}, {'provider': 'SafeDNS'}, {'primary_server': '195.46.39.39'}, {'provider': 'OpenNIC'}, {'primary_server': '69.195.152.204'}, {'provider': 'SmartViper'}, {'primary_server': '208.76.50.50'}, {'provider': 'Dyn'}, {'primary_server': '216.146.35.35'}, {'provider': 'FreeDNS'}, {'primary_server': '37.235.1.174'}, {'provider': 'Alternate DNS'}, {'primary_server': '198.101.242.72'}, {'provider': 'Yandex.DNS'}, {'primary_server': '77.88.8.8'}, {'provider': 'UncensoredDNS'}, {'primary_server': '91.239.100.100'}, {'provider': 'Hurricane Electric'}, {'primary_server': '74.82.42.42'}, {'provider': 'puntCAT'}, {'primary_server': '109.69.8.51'}, {'provider': 'Neustar'}, {'primary_server': '156.154.70.1'}, {'provider': 'Cloudflare'}, {'primary_server': '1.1.1.1'}, {'provider': 'Fourth Estate'}, {'primary_server': '45.77.165.194'}]

I think the results would be easier to work with if you created a single dictionary for each provider that had separate keys for each field.

In other words something like:

[{'provider': 'Level3', 'primary_server': '209.244.0.3'},
 {'provider': 'Verisign', 'primary_server': '64.6.64.6'},
 {'provider': 'Google', 'primary_server': '8.8.8.8'},
 {'provider': 'Quad9', 'primary_server': '9.9.9.9'},
 {'provider': 'DNS.WATCH'}, 'primary_server': '84.200.69.80'},
 {'provider': 'Comodo Secure DNS', 'primary_server': '8.26.56.26'},
 ...etc
]

Or, depending on what you're going to do, perhaps a single dictionary containing all of them like this:

{'Level3': '209.244.0.3',
 'Verisign': '64.6.64.6',
 'Google': '8.8.8.8',
 'Quad9': '9.9.9.9',
 'DNS.WATCH': '84.200.69.80',
 'Comodo Secure DNS': '8.26.56.26',
 ...etc
}

Python Dictionaries, The main differentiating factor between a list and a dictionary would be, that index we use keys to access the elements of a dictionary (or values to access keys, in a dictionary can be accessed just like lists in python, i.e, using the for loop. Appending values from dictionaries to a single list Hi I have a function in a while loop which generates a dictionary, e.g. {1:1} in each loop until a given number of loops have been performed.

providers = ["Level3", "Verisign", "Google", "Quad9", "DNS.WATCH",
             "Comodo Secure DNS", "OpenDNS Home", "Norton ConnectSafe",
             "GreenTeamDNS", "SafeDNS", "OpenNIC", "SmartViper", "Dyn",
             "FreeDNS", "Alternate DNS", "Yandex.DNS", "UncensoredDNS",
             "Hurricane Electric", "puntCAT", "Neustar", "Cloudflare",
             "Fourth Estate"]
ips = ["209.244.0.3", "64.6.64.6", "8.8.8.8", "9.9.9.9", "84.200.69.80",
       "8.26.56.26", "208.67.222.222", "199.85.126.10", "81.218.119.11",
       "195.46.39.39", "69.195.152.204", "208.76.50.50", "216.146.35.35",
       "37.235.1.174", "198.101.242.72", "77.88.8.8", "91.239.100.100",
       "74.82.42.42", "109.69.8.51", "156.154.70.1", "1.1.1.1", "45.77.165.194"]
dic = [{i[0]:i[1]} for i in zip(providers,ips)]

Now dic is [{'Level3': '209.244.0.3'}, {'Verisign': '64.6.64.6'}, {'Google': '8.8.8.8'}, ...]

Python Dictionary with For Loop, The first example I am going to cover is expanding a dictionary into a list of We need to iterate all over fruits keys and build a list repeating the key N=value times​. the for loop for fruit, quantity in fruits.items(): # Append the list to the main list  In this blog post I'll show how to add items to lists and dictionaries, when using loops, and across tasks. Normally when trying to add a new item to the variable, while in the loop, or between tasks, Ansible will ovewrite the values, keeping the result of the last iteration.

Maybe, this will help:

dic = [{k:v} for k,v in zip(providers,ips)]

Python : How to add / append key value pairs in dictionary using dict , It accepts in iterable sequence of key value pairs that can be single key value pair or list of tuples or an another dictionary. For each entry in  In this article we will discuss how to add or append new key value pairs in a dictionary and also how to update value of existing keys. Python dictionary provides a member function update() i.e.

Iterating by index, without zip. I also suggest to return a single dict like:

res = {}
for i in range(len(providers)):
  res[providers[i]] = ips[i]

#=> {'Level3': '209.244.0.3', 'Verisign': '64.6.64.6',  ....

Where you can get ip easily as:

print(res['Hurricane Electric']) #=> 74.82.42.42


Or, alternatively:

res_alt = []
for i in range(len(providers)):
  res_alt.append({'provider_name':providers[i], 'primary_server': ips[i]})

print(res_alt)
#=> [{'provider_name': 'Level3', 'primary_server': '209.244.0.3'}, {'provider_name': 'Verisign', 'primary_server': '64.6.64.6'}, ...

Python, While working with dictionary, we can have a case in which we need to iterate through the lists, which are in the It is just the shorthand to the conventional nested loops. we iterate for each key's list and store the result. res.append(​value). Method #2 : Using from_iterable() + product() + items() The combination of above functions can be used to perform this particular task. The from_iterable() can be used to reduce inner loop and items function is used to extract key value pairs in the dictionary.

Python Dictionary, Check out what is a dictionary in Python, how to create, append, update, and as a list or a set which has a single value field, the dictionary type stores a key Similar to the lists, you can use a “for in” loop to traverse through a dictionary. Sort when values are None or empty strings python. python,list,sorting,null. If you want the None and '' values to appear last, you can have your key function return a tuple, so the list is sorted by the natural order of that tuple. The tuple has the form (is_none, is_empty, value); this way, the tuple for a None value will be

5. Data Structures, Extend the list by appending all the items from the iterable. Equivalent to Remove the first item from the list whose value is equal to x. Note that this creates (or overwrites) a variable named x that still exists after the loop completes​. The dict() constructor builds dictionaries directly from sequences of key-value pairs: >>> It sounds as if you are trying to setup a list of lists as each value in the dictionary. Your initial value for each drug in the dict is []. So assuming that you have list1 that you want to append to the list for 'MORPHINE' you should do: drug_dictionary['MORPHINE'].append(list1)

Lesson 6, The values in a dictionary aren't numbered - tare similar to what their name suggests - a dictionary. To add a value to a list, you use the 'append()' function. By using for in dictionary, it loops through all the keys in dictionary and for each key select the value and prints it. ''' Iterate over the dictionary using for loop ''' for key in wordFrequency: value = wordFrequency[key] print(key, " :: ", value)

Comments
  • What is the expected output?
  • So you're output should be a list that contains dictionary records with a single key:value ?