Is there a way to let biggest value on X (out of X, Y, Z) decide value on V in R?

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I have a dataset (ft.mutate.topics) with five variables (four numeric are ft_technical, ft_performative, ft_procedural and ft_moral). The fifth is "topic_lab" and I would like for it to take on the name (as a character) related to the variable with the highest value of the four other.

The below produces a dataset similar to mine.

Data <- data.frame(
X = sample(1:10),
Y = sample(1:10),
Z = sample(1:10))

The I would like for a variable - V - to take on either "X", "Y", og "Z" for each observation corresponding to which of these three variables, that takes on the highest value - as an example for X, this is similar again:

if (Data$X > Data$Y & Data$X > Data$Z) Data$label <- "X"

Warning message:
In if (Data$X > Data$Y & Data$X > Data$Z) Data$label <- "X": 
the condition has length > 1 and only the first element will be used    

In relation to my initial example I have tried the following with a combination of if-commands:

if (ft.mutate.topics$ft_technical > ft.mutate.topics$ft_performative &
    ft.mutate.topics$ft_technical > ft.mutate.topics$ft_procedural &
    ft.mutate.topics$ft_technical > ft.mutate.topics$ft_moral)
  ft.mutate.topics$topic_lab = "technical"

if (ft.mutate.topics$ft_performative > ft.mutate.topics$ft_technical &
    ft.mutate.topics$ft_performative > ft.mutate.topics$ft_procedural &
    ft.mutate.topics$ft_performative > ft.mutate.topics$ft_moral)
  ft.mutate.topics$topic_lab = "performative"

if (ft.mutate.topics$ft_procedural > ft.mutate.topics$ft_performative &
    ft.mutate.topics$ft_procedural > ft.mutate.topics$ft_technical &
    ft.mutate.topics$ft_procedural > ft.mutate.topics$ft_moral)
  ft.mutate.topics$topic_lab = "procedural"

if (ft.mutate.topics$ft_moral > ft.mutate.topics$ft_performative &
    ft.mutate.topics$ft_moral > ft.mutate.topics$ft_procedural &
    ft.mutate.topics$ft_moral > ft.mutate.topics$ft_technical)
  ft.mutate.topics$topic_lab = "moral"

It says: "the condition has length > 1 and only the first element will be used" and substitutes the whole variable with "performative" because it is has the highest value in row 1. Anybody know what is up?

Thank you!

This seems simple. I will use a made up dataset, to adapt to yours should be easy.

nms <- sub("^ft_", "", names(ft))
ft$topic.lab <- apply(ft, 1, function(x) nms[which.max(x)])


This is a simulated dataset.

n <- 20
ft <- data.frame(ft_X = rnorm(n, 0, 2),
                 ft_Y = rnorm(n, 0, 3),
                 ft_Z = rnorm(n, 0, 4))

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You can use max.col to get the column index for the maximum. You then subset the names of the dataframe with this.

Data$V <- names(Data)[max.col(Data)]

This defaults to splitting ties at random.

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Here's a possible approach using apply and which.max :

# create a fake input with random data
DF <- data.frame(ft_technical=sample(1:10,10),

# add the columns using apply and which.max
mx <- DF[,c('ft_technical','ft_performative','ft_procedural','ft_moral')]
DF$topic_lab <- c('technical','performative','procedural','moral')[apply(mx,1,which.max)]

Output :

> DF
   ft_technical ft_performative ft_procedural ft_moral    topic_lab
1             3              10             9       10 performative
2             8               5             7        9        moral
3             4               6             6        6 performative
4             7               9            10        8   procedural
5             6               1             4        1    technical
6             1               7             8        3   procedural
7            10               8             3        4    technical
8             9               4             2        7    technical
9             2               3             1        5        moral
10            5               2             5        2    technical

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Chapter 2 R basics, You have options of where to live and want to determine the safety of each A more explicit way to ask R to show us the value stored in a is using print like this: You can find out what the function expects and what it does by reviewing the So by not using the names, it assumes the arguments are x followed by base :. It’s often the case that I want to write an R script that loops over multiple datasets, or different subsets of a large dataset, running the same procedure over them: generating plots, or fitting a model, perhaps. I set the script running and turn to another task, only to come back later and find the [] Related posts:R annoyances Your Data is Never the Right Shape Survive R

  • Any statement will evaluate to many TRUE and FALSEs. Perhaps you need all(your long statement)?
  • It worked! Thank you - will be looking into the apply-family for sure!