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Suppose I have a list:

row = [u'28d07ef48e40', u'373ac79f615f', u'a3ec4faddbec', u'c0195f9568c6', u'cc4ebc7b826c', u'ccdfdb826c', u'cc4fa826c', u'cc4eeesb826c', u'ccfesb826c']

my print is

fw.write("%s %s <%s> [%s] %s %s (%s) %s: %s" %(str(row[0]),str(row[1]),str(row[2]),str(row[3]),str(row[4]),str(row[5]),str(row[6]),str(row[7]),str(row[8])))

How can I simplify this python print?

Depending on your Python version, you can:

For Python 3.6 and later use new format-strings, which are the most-recommended approach:

row = [u'28d07ef48e40', u'373ac79f615f', u'a3ec4faddbec', u'c0195f9568c6', u'cc4ebc7b826c', u'ccdfdb826c', u'cc4fa826c', u'cc4eeesb826c', u'ccfesb826c']

fw.write(f'{row[0]} {row[1]} [{row[2]}] ...')

For lower versions of Python 3, you can use str.format(), which is recommended over %-formatting:

fw.write('{} {} <{}> [{}] {} {} ({}) {}: {}'.format(row[0], row[1], row[2], ...)

For Python 2 you continue with %-formatting, but you dont need to call str() on arguments - it is done automatically:

fw.write("%s %s <%s> [%s] %s %s (%s) %s: %s" % tuple(row))

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The format string is in it's simplest form. What you can "simplify" is the conversion to string:

"%s %s <%s> [%s] %s %s (%s) %s: %s".format(map(str, row))

map(str, row) will call str() on all elements n row, and returns a list in 2.7, and iterator in 3.7.

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The *row operator will pack the list

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Comments
  • Duplicate of stackoverflow.com/questions/899103/…
  • First step would be to remove the unnecessary str() calls.
  • Also, *row will save you row[0],row[1],row[2]...
  • You are not specifying that you are writing to a file. What you are doing is not printing. Why do you need some entries of the list in brackets and others not? What is the real goal here?
  • You're missing an f in front of your Python 3.6 string. Edited for you
  • @ycx sorry, I occasionally have overwritten your edit and thus deprived your +2, but then upvoted one of your good answers for you to get scored
  • str() is not needed there.