Python:how to extract date using regex

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I would like to extract dates that is only in the specific format "Month day, year".If it is in any other format, I will skip it. I used the below regex function but only the month is being displayed not the day and year. Can some one point out what is wrong

>>> date_pattern="(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May?|June?
|July?|Aug(?:ust)?|Sep(?:t(?:ember)?)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?\
s+\d{2},\s+\d{4})"

s = "the date is November 15, 2009"
print(re.findall(date_pattern,s))

Output expected : November 15, 2009

Output of the above code : "November"

Or use re.search with group(0):

>>> date_pattern='(Jan(uary)?|Feb(ruary)?|Mar(ch)?|Apr(il)?|May|Jun(e)?|Jul(y)?|Aug(ust)?|Sep(tember)?|Oct(ober)?|Nov(ember)?|Dec(ember)?)\s+\d{1,2},\s+\d{4}'
>>> s = "the date is November 15, 2009"
>>> re.search(date_pattern,s).group(0)
'November 15, 2009'
>>> 

Visit the regex101 i created for it.

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How to extract date from a string in Python?, You need to know the format of date that can be there in the string in order to extract it. You can simply use a regular expression to extract the  In this post you will see how to extract any date with python regular expression: * Regex Matching Date 10/10/2015 * Regex Matching Date 10-10-15 * Regex Matching Date 1 NOV 2010 * Regular expression Matching Date 10 March 2015 The list of the matched formats: * 10/10/2015 * 10-10-15 * 1 NOV 2010 * 10 March 2015 You can watch a short video on this article here: python regular expression

You missed out the closing parenthesis in your regex pattern. It should come after December to complete the non-capturing group.

(?:Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|June|July|Aug(?:ust)?|Sep(?:t(?:ember)?)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)\s+\d{2},\s+\d{4}

Edit: Actually, it's the positioning of your parenthesis that is incorrect. Instead of being at the end of the pattern, it should come after the December alternative because that is your non-capturing group for month names.

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Parse through text and extract dates in uniform format, I usually use dateutil parser, which works for all your current test cases as is: from dateutil.parser import parse test_cases = ['04/30/2009',  You need to know the format of date that can be there in the string in order to extract it. You can simply use a regular expression to extract the date and "datetime.datetime.strptime" to parse the date. For example, If you have the date in a string in the format YYYY-MM-DD, you can use the following code to extract and parse this date,

Python Regular Expression (RegEx). Extract Dates from Strings in , Python Modules Python Dates Python Math Python JSON Python RegEx Python PIP Python Try. A date in Python is not a data type of its own, but we can import a module named datetime to work with dates as date objects. The method is called strftime() , and takes one parameter, format , to specify the format of the  Extract all lines containing substring, using regex. The program below is similar to the above program, but using the re regular expressions module. The errors and line numbers are stored as tuples, e.g., (linenum, line). The tuple is created by the additional enclosing parentheses in the errors.append() statement. The elements of the tuple are

Python Dates, You haven't made the requirements so I am assuming that the dates are in dd-​mm-yyyy [code]import re import datetime Python has a couple of packages to extract dates from a string which you could use, rather than using regex. First, you​'ll  Regular Expression– Regular expression is a sequence of character(s) mainly used to find and replace patterns in a string or file. So we can say that the task of searching and extracting is so common that Python has a very powerful library called regular expressions that handles many of these tasks quite elegantly.

Comments
  • Does Python offer any API which can parse date strings? That might be an easier option than using regex.
  • The last closing parenthesis is misplaced, move it from the end after Dec(?:ember)? --> Dec(?:ember)?)
  • Why are you using capture groups? It is very less efficient than non capture groups