How to group a bunch of string's elements
I have a string like:
and I am trying to make a list of list of those which are the same. This is my code:
List =  ls =  for el in input: if el == 'Hotel_Rooms: ': pass else: if el !=',': ls.extend(el) else: List.append(ls) print List
But the result is so weird. Could you please lemme know how can I improve my code?
Try to use collections.Counter, as follows:
from collections import Counter text= "Hotel_Rooms: R15,R11,R5,R4,R8,R2,R15,R3,R6,R1,R6,R5,R3,R2,R4,R1,R2,R5,R1,R4,R3,R6,R8,R4,R3,R1,R5,R6,R2" C = Counter(text.split('Hotel_Rooms: ').split(',')) print [[k,]*v for k,v in C.items()]
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You can also do
from itertools import groupby string = "Hotel_Rooms: R15,R11,R5,R4,R8,R2,R15,R3,R6,R1,R6,R5,R3,R2,R4,R1,R2,R5,R1,R4,R3,R6,R8,R4,R3,R1,R5,R6,R2" # convert string to sorted list vals = sorted([x.strip() for x in string.split(':').split(',')]) print([list(g) for k,g in groupby(vals)]) [['R1', 'R1', 'R1', 'R1'], ['R11'], ['R15', 'R15'], ['R2', 'R2', 'R2', 'R2'], ['R3', 'R3', 'R3', 'R3'], ['R4', 'R4', 'R4', 'R4'], ['R5', 'R5', 'R5', 'R5'], ['R6', 'R6', 'R6', 'R6'], ['R8', 'R8']]
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Your code currently just iterates through the input string and separates commas from other characters into different lists. I don't think thats what you want. It seems like you want to group similar rooms. You can use a
collections.defaultdict() for this:
from collections import defaultdict s = "Hotel_Rooms: R15,R11,R5,R4,R8,R2,R15,R3,R6,R1,R6,R5,R3,R2,R4,R1,R2,R5,R1,R4,R3,R6,R8,R4,R3,R1,R5,R6,R2" # Split rooms from 'Hotel_Rooms' _, rooms = s.split(':') # Group rooms into dictionary room_dict = defaultdict(list) for room in rooms.strip().split(','): room_dict[room].append(room) print(list(room_dict.values())) # [['R15', 'R15'], ['R11'], ['R5', 'R5', 'R5', 'R5'], ['R4', 'R4', 'R4', 'R4'], ['R8', 'R8'], ['R2', 'R2', 'R2', 'R2'], ['R3', 'R3', 'R3', 'R3'], ['R6', 'R6', 'R6', 'R6'], ['R1', 'R1', 'R1', 'R1']]
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