Given a string how to randomly transpose 2 of their letters?

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Given a string:

s = 'The quick brown fox jumps over the lazy dog'

How can I randomly select a token, swap two letters from that token and return the string with the modified token? For example (*):

The quick brown fxo jumps over the lazy dog

In the above example the token fox was selected randomly and two characters were swapped.

So far I tried to:

def swap_letters(string):
    s = list(string)
    s[0], s[len(s)-1] = s[len(s)-1].upper(), s[0].lower()
    string = ''.join(s)
    return string    


def foo(a_string):
    a_string_lis = a_string.split()
    token = random.choice(a_string_lis)
    return swap_letters(token)

However, I am getting more than 2 letters transposed and I dont know how to keep the order of the tokens inside the strings. Any idea of how to get (*) in a more pythonic way?


You could do something like this:

import random
random.seed(42)

s = 'The quick brown fox jumps over the lazy dog'


def transpose(text, number=2):

    # select random token
    tokens = text.split()
    token_pos = random.choice(range(len(tokens)))

    # select random positions in token
    positions = random.sample(range(len(tokens[token_pos])), number)

    # swap the positions
    l = list(tokens[token_pos])
    for first, second in zip(positions[::2], positions[1::2]):
        l[first], l[second] = l[second], l[first]

    # replace original tokens with swapped
    tokens[token_pos] = ''.join(l)

    # return text with the swapped token
    return ' '.join(tokens)


result = transpose(s)
print(result)

Output

The iuqck brown fox jumps over the lazy dog

UPDATE

For strings of length 1 the above code fails, something like this should fix it:

def transpose(text, number=2):

    # select random token
    tokens = text.split()
    positions = list(i for i, e in enumerate(tokens) if len(e) > 1)

    if positions:

        token_pos = random.choice(positions)

        # select random positions in token
        positions = random.sample(range(len(tokens[token_pos])), number)

        # swap the positions
        l = list(tokens[token_pos])
        for first, second in zip(positions[::2], positions[1::2]):
            l[first], l[second] = l[second], l[first]

        # replace original tokens with swapped
        tokens[token_pos] = ''.join(l)

    # return text with the swapped token
    return ' '.join(tokens)

Given a string how to randomly transpose 2 of their letters?, transposition cipher tutorial. Given a string: s = 'The quick brown fox jumps over the lazy dog'. How can I randomly select a token, swap two letters from that token​  Print characters and their frequencies in order of occurrence Given a string str containing only lowercase characters. The problem is to print the characters along with their frequency in the order of their occurrence and in the given format explained in the examples below.


You can just use str.replace method:

def swap_letters(string):
    s = list(string)
    s[0], s[len(s)-1] = s[len(s)-1], s[0]
    string = ''.join(s)
    return string

def foo(a_string):
    a_string_lis = a_string.split()
    token = random.choice(a_string_lis)
    return a_string.replace(token, swap_letters(token))

Python Programming in Context, However, if the encryption algorithm randomly scrambles the letters, the task of 3.4 Transposition Cipher 3.4.1 Encrypting Using Transposition One way to If we create one string out of the even-numbered characters and another out of If the counter is odd, we concatenate the character to our odd 1 2 3 4 5 6 7 8 9 10. Swapping Characters of a String in Java As we know that Object of String in Java are immutable (i.e. we cannot perform any changes once its created). To do modifications on string stored in a String object, we copy it to a character array, StringBuffer, etc and do modifications on the copy object.


    def swap_letters(string,pos,string1):
        s = list(string)
        s[len(s)-1], s[len(s)-2] = s[len(s)-2], s[len(s)-1].lower()
        string = ''.join(s)
        string1[pos[0]]=string
        s1= ' '.join(string1)
        return s1    
    def foo(a_string):
        a_string_lis = a_string.split()
        print(a_string_lis)
        token = random.choice(a_string_lis)
        pos=[i for i in range(len(a_string_lis)) if a_string_lis[i]==token]
        return swap_letters(token,pos,a_string_lis)
    s='The quick brown fox jumps over the lazy dog'
    print(foo(s))

Proceedings of the International Conference on Data Engineering , From the initial matrix, we generate a transposed matrix and from the matrix, we require the knowledge of “spacing of characters”, i.e., given by variable 'n'. It is easy to calculate 'n' if we know what is the actual length of the input string, from text for transposition because (1) key 1 size is variable (2) key 1 is randomly  Given all alphabets in a character array, print a string of random characters of given size. We will use rand() function to print random characters. It returns random integer values. This number is generated by an algorithm that returns a sequence of apparently non-related numbers each time it is called.


How about this:

from random import choice, sample


s = 'The quick brown fox jumps over the lazy dog'

tokenize = s.split()
token = choice([x for x in tokenize if len(x)>2])  # choose a random word from phrase with at least 2 letters
chosen = sample(token, k=2)                        # choose two random letters word
d = dict(zip(chosen, chosen[::-1]))

new_token = ''
for letter in token:
  if letter in d:
    new_token += d[letter]
    del d[letter]
  else:
    new_token += letter

s = ' '.join([word if word != token else new_token for word in tokenize])

which produces:

print(s)  # -> The quick brown fox jumps over the lyza dog
#                                                  ||

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