Calculate Time Difference Between Two Consecutive Rows

Calculate Time Difference Between Two Consecutive Rows

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I have a table like this:

RecordID     TransDate
1            05-Oct-16 9:33:32 AM
2            05-Oct-16 9:33:37 AM
3            05-Oct-16 9:33:41 AM
4            05-Oct-16 9:33:46 AM
5            05-Oct-16 9:33:46 AM

I need to get the difference between consecutive TransDate values. I am using SQL Server 2014, and am aware of a way to use the LAG functions to do this, but I don't know how to do it.

I need this output:

RecordID     TransDate              Diff
1            05-Oct-16 9:33:32 AM   0:00:00
2            05-Oct-16 9:33:37 AM   0:00:05
3            05-Oct-16 9:33:41 AM   0:00:04
4            05-Oct-16 9:33:46 AM   0:00:05
5            05-Oct-16 9:33:46 AM   0:00:00

Any ideas?

Thanks in advance!


How about this:

select recordid, transdate,
       cast( (transdate - lag(transdate) over (order by transdate)) as time) as diff
from t;

In other words, you can subtract two datetime values and cast the result as a time. You can then format the result however you like.

Time Difference Between Two Consecutive Rows, You can use a window function (aka "Analytic Function") to access values in the rows outside of the "current" row. If you do that, it is mandatory  i need simple SQL to calculate the time diff between Two Consecutive Rows anyone can help Stack Exchange Network Stack Exchange network consists of 177 Q&A communities including Stack Overflow , the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.


A non Lag/lead approach...

select T1.recordId, T1.TransDate, datediff(ss, T1.TransDate, T2.Transdate) as Diff
from Table1 T1
left join Table1 T2
on T1.Recordid = T2.RecordId +1

Calculate date difference of 2 consecutive rows of a column, I need to get the duration each proc as taken in each day (or a particular time period) which means I have take the difference of 2 consecutive  How calculate the time difference between two consecutive rows. Ask Question Asked 5 years, 1 month ago. Calculate Average between two dates of different rows.


Maybe a bit hacky:

SELECT RecordId / 2 AS id, min(TransDate) AS TransDate, max(TransDate) - min(TransDate) AS Diff GROUP BY RecordId / 2

Untested, because I have no SQL Server available right now.

Solved: How to calculate time difference among consecutive , Solved: Hello I have a table with transactional data so, each row is a transactions. I need to calculate the time difference between two  I need to get the duration each proc as taken in each day (or a particular time period) which means I have take the difference of 2 consecutive rows of Timestamp column and filter by Stage value of START and END. There are 2 ways of getting this done. Method – 1: Add an ID column to add row number


Tried creating a cursor to get the date difference.

--- Query to get date difference between two rows 

declare @table table (olddate datetime, newdate datetime)
create table #table (olddate datetime, newdate datetime)

DECLARE db_cursor CURSOR FOR 

  SELECT  CONVERT(date,[utl_recycle_date] ) as RecycleDate
  FROM XYZ
  WHERE account_number = '6900' AND match_status = 'F' 
  AND [utl_recycle_date] IS NOT NULL
  AND [utl_recycle_date] > '11/01/2018'
  GROUP BY DATEDIFF(DAY, CONVERT(date,[utl_recycle_date] ), CONVERT(date, GETDATE())),CONVERT(date,[utl_recycle_date] )
  ORDER BY 1

DECLARE @RecycleDate datetime 
DECLARE @NewDate datetime 

OPEN db_cursor 

FETCH next FROM db_cursor INTO @RecycleDate 

WHILE @@FETCH_STATUS = 0 
  BEGIN 

      FETCH next FROM db_cursor INTO @NewDate

      insert INTO #table (olddate, newdate) values (cast(@RecycleDate as date), cast(@NewDate as date))
      set @RecycleDate = @NewDate

  END 

CLOSE db_cursor 

DEALLOCATE db_cursor 

select 
olddate, newdate,
CASE 
  WHEN DATEDIFF(DAY, olddate, newdate) = 0 THEN 1 
  WHEN DATEDIFF(DAY, olddate, newdate) > 0 THEN DATEDIFF(DAY, olddate, newdate)
  END AS RecyclerFrequency  

FROM #table

drop table #table

How to get difference between consecutive rows in BigQuery , Learn how to find difference between two consecutive rows in BigQuery. Through this article you can now easily understand how one can  If I understand you correctly, you should be able to use the formula below to create a measure(not column) to calculate difference in your scenario. measure = CALCULATE ( MAX ( 'table1'[votes achieved] ), ALLSELECTED ( 'table1' ) ) - MAX ( 'table1'[votes achieved] ) Note: You'll need to replace 'table1' with your real table name. Regards


How to calculate difference between 2 consecutive rows within , I have a table named ShowSchedule. Attribs are as follows,. ShowID INT PRIMARY KEY. ShowDate DATE. ShowTime TIME. NameofShow  The Time Duration Calculator will calculate the time that has elapsed/difference between two dates with time.


How to calculate difference of values in a successive rows?, Calculate date difference of 2 consecutive rows of a column, Calculate date Time Difference Between Two Consecutive Rows, You can use a window function  Difference = VAR Prev = CALCULATE ( SUM ( Table1[Values] ), ALLEXCEPT ( Table1, Table1[MC Code], Table1[Type] ), PREVIOUSMONTH ( Table1[CurrentDate] ) ) RETURN IF ( ISBLANK ( Prev ), BLANK (), Table1[Values] - Prev )


Calculate Row Difference between two consecutive r, May 2020 Community Highlights. It's time for another PBI Community recap! Read more. PreviousNext. spinner. I calculate difference between consecutive rows and columns? Hi, I want to display the differences between value for the following data 47018/how-calculate-difference-between-consecutive-rows-columns