## How to make a 2D list with every element(list) is created by union of two other lists?

I have two lists:

D1=[["a "," "," "," "," "," "],["b "," ","o"," "," "," "],["c ","x"," "," "," "," "],["d "," "," "," "," "," "],["e "," "," "," "," "," "]] D2=[["a "," ","o"," ","x"," "], ["b "," "," "," "," "," "],["c "," "," "," "," "," "],["d "," "," "," "," "," "],["e "," "," "," "," "," "]] D=[]

I want to make a list `D`

so,`D[i]=D1[i] + D2[i]`

,for example the first element(list) looks like this:

D=[["a "," "," "," "," "," ","a "," ","o"," ","x"," "],...]

Please help me I am new in python

Try this:

D = [i+j for i,j in zip(D1,D2)]

if lengths are different it will cut the rest and go forward to the minimum of `D1`

, `D2`

. if you want the opposite, use `zip_longest`

, like this:

from itertools import zip_longest D = [i+j for i,j in zip_longest(D1,D2)]

But both will work if `D1`

and `D2`

have the same length.

**Python,** How to make a 2D list with every element(list) is created by union of two other lists? intersection of two lists python union of two lists python python union of multiple Union of a list means, we must take all the elements from list A and list B (there can be more than two lists) and put them inside a single new list. There are various orders in which we can combine the lists. For e.g., we can maintain the repetition and order or remove the repeated elements in the final list and so on. Examples:

Straightforward from your will (`D[i] = D1[i] + D2[i]`

), the simplest way is to use comprehension lists. Asumming `len(D1) == len(D2)`

, :

D = [ D1[i] + D2[i] for i in range(len(D1)) ]

will do the job.

**Algorithms,** Union of a list means, we must take all the elements from list A and list B (there can be more than two lists) and put them inside a single new list. To get rid of all the repetitive elements from the initial list, we use the set() function on both Modulo · Python | Merge key value lists · Python | Using 2D arrays/lists the right way Step 1: We first create an empty list with the empty square brackets. Then we call the append method and add 2 empty lists. Initialize list. Step 2: We access each sub-list and call append on it. This appends to the inner lists. List append. Step 3: We display the element at indexes 0, 0 and this value is 1.

First copy D1 to D, if you don't want to alter D1. Then use `extend`

method in python. It'll add all elements of list2 to list1.

Here is a simple code: though the time complexity of this code is O (n^2), it can be improved.

D1=[["a "," "," "," "," "," "],["b "," ","o"," "," "," "],["c ","x"," "," "," "," "],["d "," "," "," "," "," "],["e "," "," "," "," "," "]] D2=[["a "," ","o"," ","x"," "], ["b "," "," "," "," "," "],["c "," "," "," "," "," "],["d "," "," "," "," "," "],["e "," "," "," "," "," "]] D = D1 [:] for i in range (len (D)): D[i].extend (D2 [i]) print D

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