Extracting list of Strings from a file

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I have to extract 3 strings from a file as shown below:

I only need to extract the 3 strings before the keyword: ">> For"

I wrote the following code to extract the list of strings, however it does not extract correctly:

import re
import sys

contents = "JLYLFPMKKLZDSRLBTEKH                                        KMZMGQNLLMAETSMCUFLI                                         KXKEOLJJKYCRQKASDJG                    J                    LYLFPMKKLZDSRLBTEKH                    K                    MZMGQNLLMAETSMCUFLI                    L                    KXKEOLJJKYCRQKASDJGJ                                        LYLFPMKKLZDSRLBTEKHK                                        MZMGQNLLMAETSMCUFLIL                                        KXKEOLJJKYCRQKASDJGJ                                        LYLFPMKKLZDSRLBTEKHK                                        MZMGQNLLMAETSMCUFLIL                    >> For"

m = re.match(r'(.*)[A-Z]{20}\s{40}(.*)\s{20}>> For', contents)

if m:
    print m.group(1)

Expected result for the above file:

['KXKEOLJJKYCRQKASDJGJ', 'LYLFPMKKLZDSRLBTEKHK', 'MZMGQNLLMAETSMCUFLIL']

re.findall('(\w{20}\s+\w{20}\s+\w{20}\s+)>> For', x)[0].split()

This should return what you're after:

['KXKEOLJJKYCRQKASDJGJ', 'LYLFPMKKLZDSRLBTEKHK', 'MZMGQNLLMAETSMCUFLIL']

How to extract lines from a text file that contains strings from a list in , grep -f <(sed 's/.*/\^&\\>/' town-list.txt) ma-towns.txt. Explanation: grep -f file reads file for a list of patterns to match against. We are searching in  I have to extract 3 strings from a file as shown below: I only need to extract the 3 strings before the keyword: ">> For" I wrote the following code to extract the list of strings, however it doe


simple and stupid non-regex solution, using split without delimiter so it doesn't care about newlines, spaces, etc...

contents = "JLYLFPMKKLZDSRLBTEKH                                        KMZMGQNLLMAETSMCUFLI                                         KXKEOLJJKYCRQKASDJG                    J                    LYLFPMKKLZDSRLBTEKH                    K                    MZMGQNLLMAETSMCUFLI                    L                    KXKEOLJJKYCRQKASDJGJ                                        LYLFPMKKLZDSRLBTEKHK                                        MZMGQNLLMAETSMCUFLIL                                        KXKEOLJJKYCRQKASDJGJ                                        LYLFPMKKLZDSRLBTEKHK                                        MZMGQNLLMAETSMCUFLIL                    >> For"

toks = contents.split()
for i in range(len(toks)-1):
    if toks[i]==">>" and toks[i+1]=="For":
        print(toks[i-3:i])
        break

prints:

['KXKEOLJJKYCRQKASDJGJ', 'LYLFPMKKLZDSRLBTEKHK', 'MZMGQNLLMAETSMCUFLIL']

Reading and Writing Lists to a File in Python, Using the read and write Methods. To deal with characters (strings) the basic methods work excellent. Saving such a list line by line into the file listfile.txt can be  We can accomplish this using the string's find() method. The list stores each line of our text as a string object. All string objects have a method, find(), which locates the first occurrence of a substrings in the string. Let's use the find() method to search for the letter "e" in the first line of our text file, which is stored in the list mylines.


You can use this regex,

([A-Z]{20})\s+([A-Z]{20})\s+([A-Z]{20})\s+>>\s*For

and capture group1, group2 and group3

Demo

Sample python codes,

import re
contents = 'JLYLFPMKKLZDSRLBTEKH                                        KMZMGQNLLMAETSMCUFLI                                         KXKEOLJJKYCRQKASDJG                    J                    LYLFPMKKLZDSRLBTEKH                    K                    MZMGQNLLMAETSMCUFLI                    L                    KXKEOLJJKYCRQKASDJGJ                                        LYLFPMKKLZDSRLBTEKHK                                        MZMGQNLLMAETSMCUFLIL                                        KXKEOLJJKYCRQKASDJGJ                                        LYLFPMKKLZDSRLBTEKHK                                        MZMGQNLLMAETSMCUFLIL                    >> For'
m = re.match(r'.*([A-Z]{20})\s+([A-Z]{20})\s+([A-Z]{20})\s+>>\s*For', contents)
if m:
 print(m.group(1))
 print(m.group(2))
 print(m.group(3))

Which prints,

KXKEOLJJKYCRQKASDJGJ
LYLFPMKKLZDSRLBTEKHK
MZMGQNLLMAETSMCUFLIL

How to extract strings from a file, The assignment to the @strings array creates the required list context. This means the regex will return the list of the actual matches. In our case the output will look  In any cell, enter the folder address of the folder from which you want to list the file names. In the cell where you want the list, enter the following formula (I am entering it in cell A3): =IFERROR (INDEX (GetFileNames ($A$1),ROW ()-2),"") Copy and paste the formula in the cells below to get a list of all the files.


Reading data from file, The task now is to understand how Python programs can read and write files. Instead of reading one line at a time, we can load all lines into a list of strings However, string objects have many useful functions for extracting information. Extract numbers from list of strings in Python Python Server Side Programming Programming While using python for data manipulation, we may come across lists whose elements are a mix of letters and numbers with a fixed pattern.


Software Engineering and Formal Methods: 9th International , The first element of each pair in the list represents a file ID, and the second element represents the Definition IICountList (lfw:list (string*string)) (word' file':​string) : nat 3 Extracting Haskell Programs from Coq Proofs Coq officially supports  When using a regular expression to extract multiple numbers (or multiple pattern matches, to be exact), you can use the re.findall() function. Dan did not discuss this in the video, but it is straightforward to use: You pass in a pattern and a string to re.findall() , and it will return a list of the matches.


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