## Fastest algorithm to check collection of words in phone digit

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For example I have an array ['bab', 'col', 'stro'] ...

IN OUT 222 bab 7876 stro 999 <empty> no match

Is there any algorithm to solve this better than **O(n^2)**?

preprocess your list into a translation table, with each word keyed to its numerical equivalent. This gives you an easy look-up for the search.

dial_num = [ 'a' : 2, 'b' : 2, 'c' : 2. 'd' : 3, ... ]

Next, translate each of your words:

dial_word = [ 222 : 'bab', 264 : 'col', 7876 : 'stro' ... ]

That task is **O(N)** on the array length in characters.
Now, you have a simple search (linear or log) for a given number. If you want to further pre-process `dial_word`

as a hash table, you will have **O(1)** look-up.

**Fastest algorithm to check collection of words in phone digit,** print all possible words from phone digits possible words from phone digits practice letter combinations of a phone number javascript telephone words javascript Extract the string at digit[current_index] from the Map, where digit is the input number array. Run a loop to traverse the string from start to end For every index again call the recursive function with the output string concatenated with the ith character of the string and the current_index + 1.

I think you should use **TRIE** data Structure for Implementing (each phone name&number entry is one leaf). TRIE is an ordered tree data structure that uses strings as keys.
check this article

**Print all possible words from phone digits,** Algorithm: Map the number with its string of probable alphabets, i.e 2 with “abc”, 3 with “def” etc. create a recursive I have a word list like "English Open Word List" used to create word games. The list is in txt file with space between words, like; aa aah aahed ..and so on. I want to search it while typing the letters in the word, like google suggestions in the search bar. What is the fastest algorithm to do it? In any language?

Use `std::vector<std::string> words`

to represent input.

std::vector<std::string> S; // First convert strings to (string)numbers. for(auto word in words){ std::string s; for(auto c in word) switch (c) { case 'a':case 'b': case 'c' s += '1'; break; case 'd':case 'e': case 'f' s += '2'; break; ... } S.push_back(s); } // Now S has corresponding numbers for each string std::string input; std::cin >> input; // Find the number string match on a given input. You can do iteratively search here to find all. if (S.find(input) == S.end()) std::cout << "Does not exist" << endl; else std::cout << words[S.find(input) - S.begin()] << endl;

This is a simple snippet in C++ and you would be able to convert to any other languages.

Strictly speaking, there does not exist `O(n)`

algorithm since it has to depend on the max length of the strings. This algorithm runs in `O(kn)`

where `k`

is the max length of all strings.

**Iterative Letter Combinations of a Phone Number,** Given an integer array containing digits from [0, 9], the task is to print all possible letter A mapping of digit to letters (just like on the telephone buttons) is being followed. If complete word is generated from collections import deque See your article appearing on the GeeksforGeeks main page and help other Geeks. Using the Luhn Algorithm, the check digit for 313947143000901 is 0, not 9 (from the example in your logic diagram). In short, it appears that you have found another (not Luhn) modulo 10 algorithm for calculating a check digit. It would not be compatible with the check digits used by much of the OpenMRS community. Cheers,-Burke

**Van Nostrand’s Scientific Encyclopedia,** That is, the modulo 2 sum of any two code words, added digit by digit, must also The last three digits are the check digits and are formed by the parity check Nevertheless, experimental results indicate that such codes are usually as good as the best However, a more recent procedure, the Viterbi algorithm, is extremely The PhoneSpell ® search engine provides 4 services in one!!. You may have heard that now you can take your phone number with you when you move. Enter a 6 to 10 digit phone number and we'll show you what words and phrases your phone number spells to help you decide if you want to keep it.

**Video, Speech, and Audio Signal Processing and Associated Standards,** TABLE 9.2 Performance of Connected Digit Recognizers Word String Error Sentences in a grammar 1.0 SI 3.0 10.0 which best matches the test pattern, are exponential in nature, we need to devise efficient algorithms to solve this problem. Algorithms with numbers One of the main themes of this chapter is the dramatic contrast between two ancient problems that at rst seem very similar: Factoring: Given a number N, express it as a product of its prime factors. Primality: Given a number N, determine whether it is a prime. Factoring is hard.

**Readings in Speech Recognition,** In each of the above databases there were variable length digit strings with from 1 to at each level ( by tracking multiple best scores at each frame of each level ) . set ( from which the word models were derived ) , and for the independent test set . Among the alternatives are the stack algorithm ( 7 ) and various forms of Print all possible words from phone number digits. This question is asked by companies like microsoft, google, facebook, Amazon. Lets see example input/output to understand this problem. For example if input number is 234, possible words which can be formed are (Alphabetical order):

##### Comments

- I'm not sure what you mean by 'check'. Do you look for a name related to a number or other way round? In both cases you can use a Map (HashMap) that should allow you each lookup in about O(1) time.
- How do you translate each word, how you compare it?
- You get it from the dial_num table which you have to create it by yourself.
- @mysteryfollow: how to translate and how to compare are language-dependent implementation details, not part of the
*algorithm*; that algorithm is your question. - Note that the dial_word may not be a mapping in the case where multiple word strings translate to the same number. A better way would be to use a linked list in this case; or to do iterative search from the code in my answer.
- @Vince: yes, in that case, OP needs to build out the word to an array of compatible words. Since that wasn't part of the post, I didn't complicate my answer with that detail.