Removing an Element of a <String> ArrayList-Java

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For a java homework assignment we were assigned to initialize an ArrayList of Strings containing dictionary words. If the words were not of a length we generated ,they are then to be removed from the ArrayList. The following code is not working.

public static int randLength() {
        int range=(RAND_MAX-RAND_MIN)+1;
        int randomNum=(int)(Math.random()*range)+RAND_MIN;
        return randomNum;

This function works correctly.

int randomLength=randLength();
      for(int i=0;i<dictionaryList.size()-1;i++) {
          if(dictionaryList.get(i).length()!=randomLength) {
              System.out.println("The lucky word is " + dictionaryList.get(i));

This however, does not. dictionaryList was initialized using a text file of words. Mine were, "apples" "beer" "charlie" "dogs" "elephant" "fogerty" In some cases, the code above does remove words that are not of the randomLength value. However it does not remove them all. Any help would be appreciated.

When you remove an item from the ArrayList, you are skipping over the next item in the list, and not checking if it should be removed.

For example, if you list is "apples", "beer", "charlie", "dogs", "atom", "elephant" and your random number for the length of the words that should be removed is 4 (beer, dogs, and atom should be removed), "atom" will not be removed. When the for loop runs, it runs as the following:

i: 0, word: "apples", not removed

i: 1, word: "beer", removed

i: 2, word: "dogs", removed

i: 3, word: "elephant", not removed.

If an element is removed, you must decrease i by 1 so all elements are checked. You can do this by putting i-- in the line after dictionaryList.remove(i)

This happens because when an element is removed from an ArrayList, all elements after it are shifted down to fill in the space, unlike an Array.

Additionally, your for loop should have i<dictionaryList.size() instead of i<dictionaryList.size()-1 in order to check the last element.

You could also use an Iterator to iterate through your ArrayList, but you probably don't want to use this if you weren't taught it yet.

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Better use iterator to remove elements to avoid concurrent modification exception.

int randomLength=randLength();
Iterator<String> iter = dictionaryList.iterator();
while(iter.hasNext()) {
    String word =;
    if(word.length() != randomLength) {
        System.out.println("The lucky word is " + word);

.remove(), Yesterday, I showed you how to inject elements into the DOM. Today, let's look at how to remove them. There are two ways to remove anĀ  The remove() function uses the list element as the argument to delete. You have to pass only the single element which you want to delete. You have to pass only the single element which you want to delete.

Java Collection classes are fail-fast, which means if the Collection will be changed while some thread is traversing over it using iterator, the will throw ConcurrentModificationException.

ie : it is not generally permissible for one thread to modify a Collection while another thread is iterating over it

To Avoid ConcurrentModificationException in multi-threaded environment

  1. You can convert the list to an array and then iterate on the array. This approach works well for small or medium size list but if the list is large then it will affect the performance a lot.
  2. You can lock the list while iterating by putting it in a synchronized block. This approach is not recommended because it will cease the benefits of multithreading.
  3. If you are using JDK1.5 or higher then you can use ConcurrentHashMap and CopyOnWriteArrayListclasses. This is the recommended approach to avoid concurrent modification exception

Consider below example which is fail fast

with ConcurrentHashMap:

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ChildNode.remove(), Example 2: remove() method on a list having duplicate elements. If a list contains duplicate elements, the remove() method only removes the first matching elementā€‹Ā  Removing a particular element/string from an array can be done in a one-liner: theArray.splice(theArray.indexOf("stringToRemoveFromArray"), 1); where: theArray: the array you want to remove something particular from. stringToRemoveFromArray: the string you want removed and 1 is the amount of elements you want to remove.

Python List remove(), To remove elements and content, there are mainly two jQuery methods: remove() - Removes the selected element (and its child elements); empty() - RemovesĀ  Removing a single element. iterator erase (iterator position); Removing a range of elements. iterator erase (iterator first, iterator last); Since std::vec.begin() marks the start of container and if we want to delete the ith element in our vector, we can use: vec.erase(vec.begin() + index);

  • Maybe just i < dictionaryList.size(), Why you minus one here?
  • Yeah that wasn't accounting for the last element, however the larger problem was I wasn't accounting for the arraylist to be shorted once an element was removed. This in turn wasn't searching through all of the elements of the arraylist. Mathias's solution works! Thank you for the input.
  • Ahhhhhhhhhh. I did not even think of that. Thank you for solving the past 5 hours of my frustration! Much appreciated.