## Python function to convert seconds into minutes, hours, and days

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Question: Write a program that asks the user to enter a number of seconds, and works as follows:

• There are 60 seconds in a minute. If the number of seconds entered by the user is greater than or equal to 60, the program should display the number of minutes in that many seconds.

• There are 3600 seconds in an hour. If the number of seconds entered by the user is greater than or equal to 3600, the program should display the number of hours in that many seconds.

• There are 86400 seconds in a day. If the number of seconds entered by the user is greater than or equal to 86400, the program should display the number of days in that many seconds.

What I have so far:

```def time():
sec = int( input ('Enter the number of seconds:'.strip())
if sec <= 60:
minutes = sec // 60
print('The number of minutes is {0:.2f}'.format(minutes))
if sec (<= 3600):
hours = sec // 3600
print('The number of minutes is {0:.2f}'.format(hours))
if sec <= 86400:
days = sec // 86400
print('The number of minutes is {0:.2f}'.format(days))
return
```

This tidbit is useful for displaying elapsed time to varying degrees of granularity.

I personally think that questions of efficiency are practically meaningless here, so long as something grossly inefficient isn't being done. Premature optimization is the root of quite a bit of evil. This is fast enough that it'll never be your choke point.

```intervals = (
('weeks', 604800),  # 60 * 60 * 24 * 7
('days', 86400),    # 60 * 60 * 24
('hours', 3600),    # 60 * 60
('minutes', 60),
('seconds', 1),
)

def display_time(seconds, granularity=2):
result = []

for name, count in intervals:
value = seconds // count
if value:
seconds -= value * count
if value == 1:
name = name.rstrip('s')
result.append("{} {}".format(value, name))
return ', '.join(result[:granularity])
```

..and this provides decent output:

```In : display_time(1934815)
Out: '3 weeks, 1 day'

In : display_time(1934815, 4)
Out: '3 weeks, 1 day, 9 hours, 26 minutes'
```

Python program to convert seconds into hours, minutes and seconds , Datetime module provides timedelta object which represents a duration, the difference between two dates or times. datetime. timedelta can be used to represent seconds into hours, minutes and seconds format. Given an integer n (in seconds), convert it into hours, minutes and seconds.. Examples: Input : 12345 Output : 3:25:45 Input : 3600 Output : 1:00:00 Approach #1 : Naive

This will convert n seconds into d days, h hours, m minutes, and s seconds.

```from datetime import datetime, timedelta

def GetTime():
sec = timedelta(seconds=int(input('Enter the number of seconds: ')))
d = datetime(1,1,1) + sec

print("DAYS:HOURS:MIN:SEC")
print("%d:%d:%d:%d" % (d.day-1, d.hour, d.minute, d.second))
```

Python: Convert seconds to day, hour, minutes and seconds , Python: Tips of the Day. Executes the provided function once for each list element​. Example: def tips_for_each(itr, fn): for el in itr: fn(el)  There are several ways to convert seconds to days, hours, minutes and seconds. Here we will see the easiest way to do that. Using the datetime module’s timedelta() object, you can convert the seconds in integer or decimal (with microseconds) value to days, hours, minutes and seconds in one line of code. Here is an example.

To convert seconds (as string) into datetime, this could also help. You get number of days and seconds. Seconds can be further converted into minutes and hours.

```from datetime import datetime, timedelta
sec = timedelta(seconds=(int(input('Enter the number of seconds: '))))
time = str(sec)
```

Python program to convert seconds into hours, minutes and seconds, Python program to convert seconds into hours, minutes and seconds. Python​Server Side Approach 1: The brute-force method. Example. Python program to convert seconds into hours, minutes and seconds Count of a, b & c after n seconds for given reproduction rate Program to convert given number of days in terms of Years, Weeks and Days

I'm not entirely sure if you want it, but I had a similar task and needed to remove a field if it is zero. For example, 86401 seconds would show "1 days, 1 seconds" instead of "1 days, 0 hours, 0 minutes, 1 seconds". THe following code does that.

```def secondsToText(secs):
days = secs//86400
hours = (secs - days*86400)//3600
minutes = (secs - days*86400 - hours*3600)//60
seconds = secs - days*86400 - hours*3600 - minutes*60
result = ("{} days, ".format(days) if days else "") + \
("{} hours, ".format(hours) if hours else "") + \
("{} minutes, ".format(minutes) if minutes else "") + \
("{} seconds, ".format(seconds) if seconds else "")
return result
```

EDIT: a slightly better version that handles pluralization of words.

```def secondsToText(secs):
days = secs//86400
hours = (secs - days*86400)//3600
minutes = (secs - days*86400 - hours*3600)//60
seconds = secs - days*86400 - hours*3600 - minutes*60
result = ("{0} day{1}, ".format(days, "s" if days!=1 else "") if days else "") + \
("{0} hour{1}, ".format(hours, "s" if hours!=1 else "") if hours else "") + \
("{0} minute{1}, ".format(minutes, "s" if minutes!=1 else "") if minutes else "") + \
("{0} second{1}, ".format(seconds, "s" if seconds!=1 else "") if seconds else "")
return result
```

EDIT2: created a gist that does that in several languages

How to Convert Seconds to Years with Python, How to Convert Seconds to Years with Python. Start with a number of seconds. Divide by 60 to get the number of minutes: minutes = seconds / 60 print(minutes) Output: 24443409.48451446. Divide by 60 to get the number of hours: hours = minutes / 60 print(hours) Output: 407390.158075241. Develop a program that reads the number of days, hours, minutes, and seconds from the user. Calculate and display the total number of seconds represented by that duration. Load your favorite IDEs on the cloud & code on the go with virtual desktops remotely from your preferred mobile devices (iOS/Android/PC) with CloudDesktopOnline.com .

```def normalize_seconds(seconds: int) -> tuple:
(days, remainder) = divmod(seconds, 86400)
(hours, remainder) = divmod(remainder, 3600)
(minutes, seconds) = divmod(remainder, 60)

return namedtuple("_", ("days", "hours", "minutes", "seconds"))(days, hours, minutes, seconds)
```

Python's program to Convert time unit seconds in days,hours,minutes, Develop a python program that begins by reading a number of seconds from the user. Then your program should display the equivalent  days, hours, minutes = td.days, td.seconds // 3600, td.seconds // 60 % 60 As for DST, I think the best thing is to convert both datetime objects to seconds. This way the system calculates DST for you.

8.1. datetime — Basic date and time types, For related functionality, see also the time and calendar modules. Attributes: year, month, day, hour, minute, second, microsecond, and tzinfo. class datetime.timedelta(days=0, seconds=0, microseconds=0, if and only if, after converting it to minutes and subtracting utcoffset() (or 0 if that's None), the result is non-zero. Last update on February 26 2020 08:09:18 (UTC/GMT +8 hours) Python Basic: Exercise-65 with Solution Write a Python program to convert seconds to day, hour, minutes and seconds.

How to Convert seconds to day, hour, minutes and seconds in Python, How to Convert seconds to day, hour, minutes and seconds in Python. T3SO Tutorials Duration: 4:43 Posted: Apr 17, 2019 Converting seconds into days, hours, minutes and seconds in C++ C++ Server Side Programming Programming In this tutorial, we will be discussing a program to convert seconds into days, hours, minutes and seconds.

Seconds -> Days, Hours, Minutes, and Seconds, python datetime. This is just a simple function to convert seconds to days, hours, minutes and seconds for a larger app I'm going to be building. Using python programming to convert seconds into days,hours, and minutes. Using python programming to convert seconds into days,hours, and minutes. Using floor division and modulo. https

• Hint: docs.python.org/library/functions.html#divmod lets you do something like this: `divmod(3660,3600) # (1, 60)` and `divmod(60,60) # (1,0)`. Also, what exactly are you asking?
• On my Python 2.6.6 system, I had to use `result.append("%s %s" % (value, name))`
• using 3.0 style format strings, you can use: `t = timedelta(seconds=long(valu)); print("Time to Keep: {}m-{}d {} (h:mm:ss)".format(t.days/30, t.days%30, timedelta(seconds=t.seconds)))`