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I am using phone number to let user signup and now when they sign out and wanna sign in again i have same interface as Uber so they've to verify their phone to login , but my code won't work it just loads one and only one user, loops through whole db to last user instead of if() returning true it ignores and iterates through whole db

                        for (DataSnapshot snapshot : dataSnapshot.getChildren()) {
                        User user = snapshot.getValue(User.class);
                        //user.getUserPhone().matches(mobileNumber)
                        String ph = user.getUserPhone();

                        boolean matched = ph.contentEquals(mobileNumber);
                        if (!matched) {
                            signInWithPhoneAuthCredential(phoneAuthCredential);
                        } else {
                            Intent intent = new Intent(RegisterActivity.this, HomeActivity.class);
                            user = snapshot.getValue(User.class);
                            intent.putExtra("PhoneNumber", mobileNumber);
                            startActivity(intent);
                        }
                    }

You could try this:

if (!matched) {
    signInWithPhoneAuthCredential(phoneAuthCredential);
    break; //add this to exit loop
}

Nested IF statements, Here's a quick tutorial on the IF statement and some of its more complex uses. The nested IF. I'm sure at this point you are all fairly comfortable  Is your code cluttered? You know what they say: tidy code, tidy mind! With this article, you’ll learn how to simplify your code. Specifically, we’re going to compare two ways of checking the value of an integer: using several if statements vs using one if statement. If you need an introduction to coding and want to learn for FREE, check out our 30-minute beginners course here: training

You need exit from the whole for loop after check the condition in

 if (!matched) {
    signInWithPhoneAuthCredential(phoneAuthCredential);

   // return;

    } else {
       Intent intent = new Intent(RegisterActivity.this, 
       HomeActivity.class);
       user = snapshot.getValue(User.class);
       intent.putExtra("PhoneNumber", mobileNumber);
       startActivity(intent);
     //  return;
                    }

user return keyword place where you want do some execution after true matched both numbers.

Code Smells: If Statements, You may have noticed we've been ignoring the series of if s that was the multiple isPresent checks that are the result of wrapping the MappedField mf in an Optional . The abuse of the for loop syntax in this code pains me:. Array for loop in Android Studio. 535. March 01, 2017, at 12:37 PM. but if you want to do it with two nested for then I think a solution could be:

I Acheived it by calling a function inside if else and then using break;

Introduction to Nested If Statements: Android Studio Crash Course , Specifically, we're going to compare two ways of checking the value of an integer: using several if statements vs using one if statement. I'm trying to loop through an array of user names and populate a TextView depending on the location in the array. I'm using an adapter to do this. The problem I'm running into is that when I set the text for userNameTextView, only the name for the last position in the for loop will be set for the TextView .

if / else errors, Typically the following error messages are caused by faulty if/else syntax counts as one statement aswell, which lets us create an else if case by nesting: Hi everyone, I'm new to Android Studio and am trying to make an app that uses the phone's orientation as a control for a device that it will communicate to through wifi. So far, I've been able to access the sensors I need and output the readings to the app screen. At this point, it only updates a new sensor value each time a button is pressed.

Incremental Java break and continue, break causes the control flow to exit current loop body (as if the loop condition has just more than one enclosing loop, then these enclosing loops must be nested in one another. If a break statement appears in an if body, just ignore the if. Android Studio Tutorials In 2 Minutes - 14 - If Statement Excel IF Formula: Simple to Advanced (multiple criteria, nested IF, AND Android Studio Android Programming Tutorial for

Java's Ternary Operator in Three Minutes, Ternary Operator; Syntax; Examples; Nesting Multiple Operators; Summary; Comments. The ternary operator is a form of syntactic sugar for if -then- else statements. the basic structure is very similar to an if -then- else statement but it is Visual Studio Code: End-to-End Editing and Debugging Tools for  Open Android Studio. 2. Go to File => New => New Project. Write application name as NestedScrollView. Then, click next button. 3. Select minimum SDK you need. However, we have selected 17 as minimum SDK. Then, click next button: 4. Then, select Empty Activity => click next => click finish. 5.

Comments
  • Your description is a little unclear, but I would mention that starting an Activity is an asynchronous operation. That is, your for loop is not going to pause when you call startActivity().
  • i've tried the if otherway too, i mean if (matched) launch activity else SignInwithPhoneAuth
  • so should i use finish there? or call another function to launch my activity?
  • No, you'll have to rethink your approach. Do you mean to start HomeActivity multiple times, once for each matched user? Or are you just trying to pass all of them to HomeActivity at once?
  • i'm matching phone number of the user with the user's saved on db if that number is there, the app should launch homeActivity otherwise it should send the user to another method which sends to profileActivity where user provides name and stuff for first time
  • it always go to not matched so, i don't think that'd help but lemme try