Datediff more than 24 hours

sql time greater than 24 hours
how to calculate time difference in hours and minutes and seconds in sql server
time difference in sql

I have to datetimeoffset fields, which I want to calculate the time between then.

I have done this:

CONVERT(varchar(5), DATEADD(MINUTE,DATEDIFF(MINUTE, P.DT_INIC_PARD , P.DT_TMNO_PARD ),0),114) AS 'Duration'.

The problem is: When the time between then is higher than 24 hours, the result query shows me '00:00'.

Example:

P.DT_INIC_PARD = 2014-03-18 07:00:00.0000000 -03:00

P.DT_TMNO_PARD = 2014-03-19 07:20:00.0000000 -03:00

This gives me more than 24 hours. And shows me '00:20'

The question is: how to solve this?

Thanks

What do you intend to do with that DATEADD() function? What it's doing is turning your DATEDIFF() output into a DATETIME field, which you then CONVERT() to a time format. You can't display more than 24 hours in a time format 00:00, so you need to choose a different way to display the output.

This works fine:

SELECT DATEDIFF(MINUTE, '2014-03-18 07:00:00.0000000' , '2014-03-19 07:20:00.0000000' ) -- 1460 minutes

If you want the result in days/hours/minutes you can use modulus division:

WITH cte AS (SELECT DATEDIFF(MINUTE, '2014-03-18 07:00:00.0000000' , '2014-03-19 07:20:00.0000000') Duration)
SELECT CAST(Duration/1440 AS VARCHAR(15))+'d '
     + CAST((Duration-1440)/60 AS VARCHAR(15))+'h '
     + CAST((Duration-1440)%60 AS VARCHAR(15))+'m'
FROM cte

SQL Server - DATEDIFF, SQL Server DATEDIFF function returns the difference in seconds, minutes, hours, days, of seconds in 24 hours SELECT DATEDIFF(ss, GETDATE() - 1, GETDATE()); -- Returns: 86400. Negative Value, Returned is start_date is later than end_date For more information including a UDF example, see How to Implement  Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. Learn more How to calculate time difference more than 24 hours in sql server 2014

You can do the following:

SELECT  CAST(Duration/60 AS VARCHAR(5)) + ':' + 
        RIGHT('0'+ CAST(Duration % 60 AS VARCHAR(2)),2)
FROM (  SELECT DATEDIFF(MINUTE, P.DT_INIC_PARD, P.DT_TMNO_PARD) Duration
        FROM YourTable) A

Calculation of time more than 24 hours in sql, Please, have a look at example: Hide Copy Code. DECLARE @​employee_task_table TABLE (empid INT, taskid INT, alot VARCHAR(30))  How to add / subtract more than 24 hours, 60 minutes, 60 seconds. To add a desired time interval to a given time, divide the number of hours, minutes, or seconds you want to add by the number of the corresponding unit in a day (24 hours, 1440 minutes, or 86400 seconds), and then add the quotient to the start time.

I have taken a slightly different approach, works especially well for large time differences. The output is in the following format:

HH:MM:SS

Of course that can be attempted by just removing/adding differing parts. Here is how it's done generically for one value:

DECLARE @NumberOfSeconds INT = 123

SELECT (CASE WHEN FLOOR(@NumberOfSeconds / (60 * 60)) < 10 THEN '0' ELSE '' END) + 
    CAST(FLOOR(@NumberOfSeconds / (60 * 60)) AS VARCHAR(MAX)) + ':' + 
    (CASE WHEN FLOOR((@NumberOfSeconds % (60 * 60)) / 60) < 10 THEN '0' ELSE '' END) + 
    CAST(FLOOR((@NumberOfSeconds % (60 * 60)) / 60) AS VARCHAR(MAX)) + ':' + 
    (CASE WHEN FLOOR((@NumberOfSeconds % (60 * 60)) % 60) < 10 THEN '0' ELSE '' END) + 
    CAST(FLOOR((@NumberOfSeconds % (60 * 60)) % 60) AS VARCHAR(MAX))

And for this specific question:

SELECT (CASE WHEN FLOOR(DATEDIFF(SECOND, DT_INIC_PARD, DT_TMNO_PARD) / (60 * 60)) < 10 THEN '0' ELSE '' END) + 
    CAST(FLOOR(DATEDIFF(SECOND, DT_INIC_PARD, DT_TMNO_PARD) / (60 * 60)) AS VARCHAR(MAX)) + ':' + 
    (CASE WHEN FLOOR((DATEDIFF(SECOND, DT_INIC_PARD, DT_TMNO_PARD) % (60 * 60)) / 60) < 10 THEN '0' ELSE '' END) + 
    CAST(FLOOR((DATEDIFF(SECOND, DT_INIC_PARD, DT_TMNO_PARD) % (60 * 60)) / 60) AS VARCHAR(MAX)) + ':' + 
    (CASE WHEN FLOOR((DATEDIFF(SECOND, DT_INIC_PARD, DT_TMNO_PARD) % (60 * 60)) % 60) < 10 THEN '0' ELSE '' END) + 
    CAST(FLOOR((DATEDIFF(SECOND, DT_INIC_PARD, DT_TMNO_PARD) % (60 * 60)) % 60) AS VARCHAR(MAX))
FROM YourTable

As far as I can tell this works for as large of a time difference you have up to the max value of a "int".

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Convert DateDiff into Hours, Minutes, Seconds, Milliseconds , Convert DateDiff into Hours, Minutes, Seconds, Milliseconds – Learn more However, if the time difference is greater than 24 hours, it will not  What it's doing is turning your DATEDIFF() output into a DATETIME field, which you then CONVERT() to a time format. You can't display more than 24 hours in a time format 00:00, so you need to choose a different way to display the output.

Comments
  • The way you did it dosen't work the way I'd like, but anyway, I used just the DATEDIFF to return in minutes and I treated the days in my C# backend. Thanks anyway! I cant give you a +1 cause I dont have reputation enough haha.