Unique Integer Value

random number generator
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I need a way to generate unique integer values in swift

//string
let g = NSUUID().UUIDString

How can I accomplish the above in int format?

Int(rand()) will give you random numbers, but not unique random numbers. Making them unique requires more work. If the set of numbers you want to draw from is small you can build a var array of numbers and remove one at a time randomly from the array.

The memory requirements of that get bad as the range of numbers gets large.

If you need a very large range of numbers but only need to generate a fairly small number of them you can add each number to a set of already-used numbers and then test each new number against the already-used numbers before returning it. That's fast and fairly memory-efficient until you generate thousands of unique numbers. It's memory requirements keep climbing. Sets test for membership quite fast, so that should be fine.

Can you give more details of your requirements?

Unique Integer Value, Int(rand()) will give you random numbers, but not unique random numbers. Making them unique requires more work. If the set of numbers you  I have different unique strings in the same format. The string looks like this axf25!j&809>-11~dc and I want to get unique integer value from this string. Each time this value must be the same and depends on the string. I've tried to convert each char of the string to int and then I sum chars to each other.

Sounds like you just want a UUID value, or equivalent unique value, stored as an Int - which you can do with the built in hashValue method:

let g = UUID().hashValue

This method is deterministic so you'll always get the same resulting integer when supplying the same UUID.

How to Create a Unique 64bit Integer from String, How to Create a Unique 64bit Integer from String $values); // Parameters are sorted by name, using lexicographical byte value ordering. Counting Unique Values In Excel – 5 Effective Ways Let’s consider we have a long list of duplicate values in a range and our objective is to count only the unique occurrences of each value. Though this can be a very common requirement in many scenarios but excel doesn’t have any single formula that can directly help us to count unique

Figured it out using:

Int(rand())

How to Generate a Sequence of Unique Random Integers, Using this approach, we could begin with an array containing all possible 32-bit integers, and shuffle the first 10000000 values out of the array to  template ForwardIterator unique (ForwardIterator first, ForwardIterator last, BinaryPredicate Pred); Here, first and last are the same as previous case. Pred: Binary function that accepts two elements in the range as argument, and returns a value convertible to bool. The value returned indicates whether both arguments are considered equivalent (if true, they are equivalent and one of them is removed).

Unique Integer Generation in Distributed Systems, Unique integer generation in distributed systems number of bits of the generated value for metadata and not the actual sequence number. As a result, they want a technique to generate a random and unique integer. Generating a random number on its own is not difficult, using methods like RAND() or CHECKSUM(NEWID()). The problem comes when you have to detect collisions. Let's take a quick look at a typical approach, assuming we want CustomerID values between 1 and 1,000,000:

Unique Numbers By Shyam Sunder Gupta, value generator methods, such as nextInt(), nextDouble(), or nextLong(). To count unique numeric values in a range, you can use a formula based on the FREQUENCY and SUM functions. In the example shown, employee numbers appear in the range B5:B14. The formula in F5 is: = SUM ( -- ( FREQUENCY ( B5:B14 , B5:B14 ) > 0 ))

Integer Generator, const id = uniqueInteger(). avoidClashes(options) ⇒ number. Generate a unique integer avoiding a particular range import assert from 'assert'  Assign a value of 1 to each true condition by using the IF function. Add the total by using the SUM function. Count the number of unique values by using the FREQUENCY function. The FREQUENCY function ignores text and zero values. For the first occurrence of a specific value, this function returns a number equal to the number of occurrences of that value.

Comments
  • If you want a random integer, check out the arc4random family of functions. If you want unique integers for successive calls, you have 2 options: (1) keep looping so you don't repeat a previously generated value and (2) randomly shuffle an array.
  • .hashValue isn't guaranteed to return the same hash between application launches (and it often doesn't)
  • If you really need unique, this is going to fail. Sooner or later.