function parameter of array of T "decaying" to pointer to T?

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If I have a function...

void f(int x[3]) {}

...is this distinguishable from a function...

void f(int* x) {}

If not, where in the standard does it address this issue?

Clearly there are array-to-pointer standard conversions, but I don't think they apply here?

I seem to remember language which said something to this effect, but can't seem to find it.

$ cat t.cc
void f(int x[3]) {}

void f(int* x) {}

$ g++ t.cc
t.cc: In function ‘void f(int*)’:
t.cc:3:6: error: redefinition of ‘void f(int*)’
 void f(int* x) {}
      ^
t.cc:1:6: note: ‘void f(int*)’ previously defined here
 void f(int x[3]) {}
      ^

If I have a function...

void f(int x[3]) {}

...is this distinguishable from a function...

void f(int* x) {}

No. Those declarations are equivalent.

Standard draft:

[dcl.fct]

The type of a function is determined using the following rules. The type of each parameter (including function parameter packs) is determined from its own decl-specifier-seq and declarator. After determining the type of each parameter, any parameter of type "array of T" or of function type T is adjusted to be "pointer to T". ...

This rule complements the array decaying rule. Array decaying allows calling a function with - apparently - an array argument, while this rule allows declaring a function with - apparently - an array argument, while actually what is passed is a pointer. These rules stem from the C heritage of the language. Same with function to pointer decaying.

C++ Passing Arrays to Functions, C++ Passing Arrays to Functions - C++ does not allow to pass an entire array as As you can see, the length of the array doesn't matter as far as the function is  If you want to pass a single-dimension array as an argument in a function, you would have to declare a formal parameter in one of following three ways and all three declaration methods produce similar results because each tells the compiler that an integer pointer is going to be received.


From [dcl.fct§5] (emphasis mine):

The type of a function is determined using the following rules. The type of each parameter (including function parameter packs) is determined from its own decl-specifier-seq and declarator. After determining the type of each parameter, any parameter of type "array of T" or of function type T is adjusted to be "pointer to T".

Passing an array as a function parameter in JavaScript, Why don't you pass the entire array and process it as needed inside the function? var x = [ 'p0', 'p1', 'p2' ]; call_me(x); function call_me(params)  Arrays can be passed as arguments to method parameters. Because arrays are reference types, the method can change the value of the elements. Passing single-dimensional arrays as arguments. You can pass an initialized single-dimensional array to a method. For example, the following statement sends an array to a print method.


It's described in the specification of function declarators

[dcl.fct]

5 [...] After determining the type of each parameter, any parameter of type "array of T" or of function type T is adjusted to be "pointer to T". [...]

Passing arrays as arguments, After each method returns, the DisplayArray method shows that passing an array by value doesn't prevent changes to the array elements. C# Since an array is passed as a pointer, the array's memory is not copied. The function uses the memory of the same array that is passed to it, and can change what is in that memory. Passing an array by reference.


The arguments object, arguments is an Array-like object accessible inside functions that zero, but it doesn't have Array 's built-in methods like forEach() and map() . When we pass an array as a parameter then it splits into the pointer to its first element. We can say that if I shall pass the array of character as a parameter then it would be split into the pointer to the character. So, if a function parameter declared as T arr[] or T arr[n] is treated as T *arr.


Passing Arrays as Function Arguments, If you want to pass an array into a variadic function. You can use ES6 spread to turn that array into a list of arguments. Math.max(numbers[0], numbers[1], numbers[2]); // ❌ And this won't work Math.max(numbers); // NaN. Lucky for us, we can  And you don't need to define every parameters for call_me function either. You can just use arguments function call_me () { // arguments is a array consisting of params.


How to pass Arrays to a Function in C Language?, How do you pass an array as a parameter in a function? However, You can pass a pointer to an array by specifying the array's name without an index. If you want to pass a single-dimension array as an argument in a function, you would have to declare function formal parameter in one of following three ways and all three declaration methods produce similar results because each tells the compiler that an integer pointer is going to be received.