how to pull exactly 6 continuous figures from string

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Problem: how to pull exactly 6 continuous figures from string

Example:

f657674
576767g
tt454656y
465767yy
x1234567
1234567x
n645856g
s-5656-54654657657-6576-46567785-4354
pof-user-201734545435454
4545665
345678
f546576767g
rtryty

it should give

657674
576767
454656
465767
(blank value)
(blank value)
645856
(blank value)
(blank value)
(blank value)
345678
(blank value)
(blank value)

What I've tried: (A1 is the cell of the first string)

=IFERROR(LOOKUP(10^6;MID(A1;ROW(INDIRECT("1:"&LEN(A1)-5));6)+0);"")

Then I drag this formula for the other rows and it gives:

    657674    (right)
    576767    (right)
    454656    (right)
    465767    (right)
   (blank value)  (right) 
   (blank value)  (right)
    645856    (right)
    657457    (wrong)
    435454    (wrong)
    4545665   (wrong)  
    345678    (right)
    546576767 (wrong)
    (blank value)  (right)

Version: Excel 2016

What's the regular expression to match a string of exactly six numbers?, To match a string exactly six digits long, you'll have to specify the start(^) and end​($) What are some simple steps I can take to protect my privacy online? How to do kipping pull ups. Check out these steps to improve your kipping pull ups. If you want free training to learn exactly how to improve these movements

You will likely want a UDF instead of a built-in function. This should work, but likely needs tweaking. Your example in your OP returns 345678 as a correct return, but there are no letters on either side. Therefore, I assume you want either: 6 consecutive numbers on their own, or 6 consecutive numbers with a letter on both sides.

Add this to the workbook module, and you can call like =return_numbers(A1). You may or may not have to add the RegEx Reference to VBEditor.

Function return_numbers(ByVal cel As Range) As String
Dim strPattern As String
Dim regEx As New RegExp

strPattern = "[a-z]\d{6}[a-z]"

With regEx
    .Global = True
    .MultiLine = True
    .IgnoreCase = True
    .Pattern = strPattern
End With

Dim matches As Object
Set matches = regEx.Execute(cel)

If Len(cel) = 6 And IsNumeric(cel) Then
    return_numbers = cel.Value
    Set regEx = Nothing
    Exit Function
End If

If matches.Count <> 0 Then
    return_numbers = Mid(matches.Item(0), 2, Len(matches.Item(0)) - 2)
ElseIf matches.Count = 0 Then
    strPattern = "[a-z]{1}\d{6}$"
    regEx.Pattern = strPattern
    Set matches = regEx.Execute(cel)
    If matches.Count <> 0 Then
        return_numbers = Mid(matches.Item(0), 2, Len(matches.Item(0)) - 1)
    ElseIf matches.Count = 0 Then
        strPattern = "^\d{6}[a-z]{1}"
        regEx.Pattern = strPattern
        Set matches = regEx.Execute(cel)
        If matches.Count <> 0 Then
            return_numbers = Mid(matches.Item(0), 1, Len(matches.Item(0)) - 1)
        End If
    End If
End If

Set regEx = Nothing

End Function

If you're wanting to speed this up, I think if you switch the If/else statements, it might run a little quicker since it won't always run the Regex, if it finds 6 lonely digits

Edit: This is rather clunky. I'm sure there's a better regex pattern, so please let me know.

Excel: Extract number from text string, The tutorial shows how to extract number from text string in Excel by using formulas To find out how many characters should be extracted, you subtract the 5 is the 6th element of the array constant and the 8th character in the to insert the results as values, and the add-in did exactly what was asked for: To match a string exactly six digits long, you'll have to specify the start(^) and end($) indicators on the expression: [code]/^[0-9]{6}$/[/code] However, {N} is possible only with extended regular expressions.

=IFERROR(0+MID(A1,MATCH(8,MMULT(ABS(ISNUMBER(0+MID(MID("ζ"&A1&"ζ",ROW(INDEX(A:A,1):INDEX(A:A,LEN(A1)-5)),8),{1,2,3,4,5,6,7,8},1))-{1,0,0,0,0,0,0,1}),{1;1;1;1;1;1;1;1}),0),6),"")

Note that if you're not using an English-language-version of Excel then parts of the above may need amending.

Regards

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Comments
  • You may be better off here with VBA
  • unfortunately I do not know VBA.
  • So, you only want six numbers returned, where there's a letter on either side?
  • yes, I want to pull only six CONTINUOUS numbers. so 565dft676 should give a blank value. But st645594uy should give 645594
  • "Therefore, I assume you want either: 6 consecutive numbers on their own, or 6 consecutive numbers with a letter on both sides." OR it can happen one letter in one of the sides, like f565679 it should give 565679. Or 454656g it should give 454656.
  • @graphene - What should it return for x1234567? or 1234567x?
  • x1234567? or 1234567x? In both cases, a blank value.
  • @BruceWayne - The following strPattern: (?<!\d)(\d{6})(?!\d) would allow you to avoid the isnumberic test alltogether
  • it throws an error: user-defined type not defined... and points out to Dim regEx As New RegExp. I suppose I need to add the regfex refernce..