## how to pull exactly 6 continuous figures from string

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Problem: how to pull *exactly* 6 continuous figures from string

Example:

f657674 576767g tt454656y 465767yy x1234567 1234567x n645856g s-5656-54654657657-6576-46567785-4354 pof-user-201734545435454 4545665 345678 f546576767g rtryty

it should give

657674 576767 454656 465767 (blank value) (blank value) 645856 (blank value) (blank value) (blank value) 345678 (blank value) (blank value)

What I've tried: (`A1`

is the cell of the first string)

=IFERROR(LOOKUP(10^6;MID(A1;ROW(INDIRECT("1:"&LEN(A1)-5));6)+0);"")

Then I drag this formula for the other rows and it gives:

657674 (right) 576767 (right) 454656 (right) 465767 (right) (blank value) (right) (blank value) (right) 645856 (right) 657457 (wrong) 435454 (wrong) 4545665 (wrong) 345678 (right) 546576767 (wrong) (blank value) (right)

Version: Excel 2016

**What's the regular expression to match a string of exactly six numbers?,** To match a string exactly six digits long, you'll have to specify the start(^) and end($) What are some simple steps I can take to protect my privacy online? How to do kipping pull ups. Check out these steps to improve your kipping pull ups. If you want free training to learn exactly how to improve these movements

You will likely want a UDF instead of a built-in function. This should work, but likely needs tweaking. Your example in your OP returns `345678`

as a correct return, but there are no letters on either side. Therefore, I assume you want either: 6 consecutive numbers **on their own**, or 6 consecutive numbers with a letter on both sides.

Add this to the workbook module, and you can call like `=return_numbers(A1)`

. You may or may not have to add the RegEx Reference to VBEditor.

Function return_numbers(ByVal cel As Range) As String Dim strPattern As String Dim regEx As New RegExp strPattern = "[a-z]\d{6}[a-z]" With regEx .Global = True .MultiLine = True .IgnoreCase = True .Pattern = strPattern End With Dim matches As Object Set matches = regEx.Execute(cel) If Len(cel) = 6 And IsNumeric(cel) Then return_numbers = cel.Value Set regEx = Nothing Exit Function End If If matches.Count <> 0 Then return_numbers = Mid(matches.Item(0), 2, Len(matches.Item(0)) - 2) ElseIf matches.Count = 0 Then strPattern = "[a-z]{1}\d{6}$" regEx.Pattern = strPattern Set matches = regEx.Execute(cel) If matches.Count <> 0 Then return_numbers = Mid(matches.Item(0), 2, Len(matches.Item(0)) - 1) ElseIf matches.Count = 0 Then strPattern = "^\d{6}[a-z]{1}" regEx.Pattern = strPattern Set matches = regEx.Execute(cel) If matches.Count <> 0 Then return_numbers = Mid(matches.Item(0), 1, Len(matches.Item(0)) - 1) End If End If End If Set regEx = Nothing End Function

If you're wanting to speed this up, I think if you switch the `If/else`

statements, it might run a little quicker since it won't *always* run the Regex, if it finds 6 lonely digits

Edit: This is rather clunky. I'm sure there's a better regex pattern, so please let me know.

**Excel: Extract number from text string,** The tutorial shows how to extract number from text string in Excel by using formulas To find out how many characters should be extracted, you subtract the 5 is the 6th element of the array constant and the 8th character in the to insert the results as values, and the add-in did exactly what was asked for: To match a string exactly six digits long, you'll have to specify the start(^) and end($) indicators on the expression: [code]/^[0-9]{6}$/[/code] However, {N} is possible only with extended regular expressions.

`=IFERROR(0+MID(A1,MATCH(8,MMULT(ABS(ISNUMBER(0+MID(MID("ζ"&A1&"ζ",ROW(INDEX(A:A,1):INDEX(A:A,LEN(A1)-5)),8),{1,2,3,4,5,6,7,8},1))-{1,0,0,0,0,0,0,1}),{1;1;1;1;1;1;1;1}),0),6),"")`

Note that if you're not using an English-language-version of Excel then parts of the above may need amending.

Regards

**Extract Numbers From String Using Java Regular Expressions,** The following are examples which show how to extract numbers from a string Being able to parse strings and extract information from it is a key skill and we want to extract 6B1BC0 which is 6 characters long, we can use: MFor this assignment, you will create a program that tests a string to see if it is a palindrome. A palindrome is a string such as “madam”, “radar”, “dad”, and “I”, that reads the same forwards and backwards. The empty string is regarded as a palindrome. Write a recursive function: bool isPalindrome(string str, int lower, int upper)

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##### Comments

- You may be better off here with VBA
- unfortunately I do not know VBA.
- So, you only want six numbers returned, where there's a letter on either side?
- yes, I want to pull only six CONTINUOUS numbers. so 565dft676 should give a blank value. But st645594uy should give 645594
- "Therefore, I assume you want either: 6 consecutive numbers on their own, or 6 consecutive numbers with a letter on both sides." OR it can happen one letter in one of the sides, like f565679 it should give 565679. Or 454656g it should give 454656.
- @graphene - What should it return for
`x1234567`

? or`1234567x`

? - x1234567? or 1234567x? In both cases, a blank value.
- @BruceWayne - The following strPattern:
`(?<!\d)(\d{6})(?!\d)`

would allow you to avoid the`isnumberic`

test alltogether - it throws an error: user-defined type not defined... and points out to Dim regEx As New RegExp. I suppose I need to add the regfex refernce..