How to check if the input is within the first column of the matrix

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I have created a matrix called rix.

rix = [[1,2,3],[4,5,6][7,8,9]]

And as an input I have variable put which is a single list of length 2 which represents the position of the matrix. The part that I'm struggling in, is how do I check that the variable put represents one of the positions in the first column?

Design your function to be generic; it should take the argument row_n (row number) that represents which row you want to check its bounds. Check if the row_n exists in your rix's list. Then, do a comparison between your put's second element (that represents the expected row length) with the original row_n length in the rix list.

According to your case, you should compare if the put's second element is less than or equal to the rix's row_n length and then return your booleans.

Check if the given matrix is increasing row and column wise , First row doesn't satisfy the required condition. Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: Linearly  Checking a specific column in a matrix with a specific row,column in another matrix. I was able solved the first part of the problem that is to "check 1 set of B

You use len(rix) to evaluate the number of rows and len(rix[0]) to evaluate the number of columns your matrix has

so

if len(rix) <= put[0]:
    return false
elif len(rix[0]) <= put[1]:
    return false
else:
    return true

Check if the Matrix satisfies the given conditions, For every row, it must contain a single distinct character. No two consecutive rows have a character in common. Examples: Input: mat[][] = { {0,  Check if one column value exists in another column using MATCH. You can use the MATCH() function to check if the values in column A also exist in column B. MATCH() returns the position of a cell in a row or column.

You also have to consider negative indices.

def in_first_col(put, list2D):
    row_idx, col_idx = put

    # return False if we can't get the row
    try:
       row = list2D[row_idx]
    except IndexError:
       return False

    # return False if row is empty
    # return False if col_idx does not refer to first element of row
    return row and (col_idx == 0 or col_idx == -len(row))

Demo:

>>> rix = [[1,2,3],[4,5,6],[7,8,9]]
>>> in_first_col([1,1], rix)
>>> False
>>> in_first_col([2,0], rix)
>>> True
>>> in_first_col([5,0], rix)
>>> False
>>> in_first_col([-2,-3], rix)
>>> True

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Comments
  • Don't you think that posting code while showing no attempt from the OP is against the main use of SO?