## How to check if the input is within the first column of the matrix

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I have created a matrix called `rix`.

```rix = [[1,2,3],[4,5,6][7,8,9]]
```

And as an input I have variable `put` which is a single list of length `2` which represents the position of the matrix. The part that I'm struggling in, is how do I check that the variable put represents one of the positions in the first column?

Design your function to be generic; it should take the argument `row_n` (row number) that represents which row you want to check its bounds. Check if the `row_n` exists in your `rix`'s list. Then, do a comparison between your `put`'s second element (that represents the expected row length) with the original `row_n` length in the `rix` list.

According to your case, you should compare if the `put`'s second element is less than or equal to the `rix`'s `row_n` length and then return your booleans.

Check if the given matrix is increasing row and column wise , First row doesn't satisfy the required condition. Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: Linearly  Checking a specific column in a matrix with a specific row,column in another matrix. I was able solved the first part of the problem that is to "check 1 set of B

You use `len(rix)` to evaluate the number of rows and `len(rix[0])` to evaluate the number of columns your matrix has

so

```if len(rix) <= put[0]:
return false
elif len(rix[0]) <= put[1]:
return false
else:
return true
```

Check if the Matrix satisfies the given conditions, For every row, it must contain a single distinct character. No two consecutive rows have a character in common. Examples: Input: mat[][] = { {0,  Check if one column value exists in another column using MATCH. You can use the MATCH() function to check if the values in column A also exist in column B. MATCH() returns the position of a cell in a row or column.

You also have to consider negative indices.

```def in_first_col(put, list2D):
row_idx, col_idx = put

# return False if we can't get the row
try:
row = list2D[row_idx]
except IndexError:
return False

# return False if row is empty
# return False if col_idx does not refer to first element of row
return row and (col_idx == 0 or col_idx == -len(row))
```

Demo:

```>>> rix = [[1,2,3],[4,5,6],[7,8,9]]
>>> in_first_col([1,1], rix)
>>> False
>>> in_first_col([2,0], rix)
>>> True
>>> in_first_col([5,0], rix)
>>> False
>>> in_first_col([-2,-3], rix)
>>> True
```

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