Average of elements in a subarray

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I have an array like a=[1, 2, 3, 4, 5, 6, 7]. I want to split this array into 3 chunks of any size.

When I split this into 3 chunks, I get 3 subarrays: [array([1, 2, 3]), array([4, 5]), array([6, 7])].

My goal is to get an array with the average of the elements in a subarray: [2, 4.5, 6.5], since (1+2+3)/3=2 (first element), (4+5)/2=4.5 (second element), and so on.

I tried the following code:

import numpy as np
a=[1, 2, 3, 4, 5, 6, 7]
a_split=np.array_split(a, 3)
a_split_avg=np.mean(a_split, axis=1)

I am getting the following error: tuple index out of range.

You're getting the error because np.array_split returns a python list of numpy array, not a multidimentional numpy array, so axis wouldn't work with it. Replace the last line with this:

a_split_avg = [np.mean(arr) for arr in a_split]

Count the number of sub-arrays such that the average of elements , Given an array of integers arr[], the task is to count the number of sub-arrays such that the average of elements present in the sub-array is greater than the average​  Longest subarray having average greater than or equal to x | Set-2; Maximum average of a subarray of size of atleast X and atmost Y; Find the average of first N natural numbers; Find average of two numbers using bit operation; Program to find simple moving average; Find the deleted value from the array when average of original elements is given

Here's a vectorized solution that avoids the splitting step to gain performance and directly gets the grouped summations and hence averages -

def average_groups(a, N): # N is number of groups and a is input array
    n = len(a)
    m = n//N
    w = np.full(N,m)
    w[:n-m*N] += 1
    sums = np.add.reduceat(a, np.r_[0,w.cumsum()[:-1]])
    return np.true_divide(sums,w)

Sample run -

In [357]: a=[1, 2, 3, 4, 5, 6, 7]

In [358]: average_groups(a, N=3)
Out[358]: array([2. , 4.5, 6.5])

Program for average of an array (Iterative and Recursive , How do you find the average of an element in an array? Maximum Average Subarray Average Rating: 4.54 (13 votes) July 15, 2017 | 30.8K views Elements of the given array will be in the range [-10,000, 10,000].

Try this:

In [1224]: mean_arr = []
In [1225]: for i in a_split:
      ...:     mean_arr.append(np.mean(i))

In [1226]: 

In [1226]: mean_arr
Out[1226]: [2.0, 4.5, 6.5]

Average of elements in a subarray, How do you find the average of an array element in Java? Given an array with positive and negative numbers, find the maximum average subarray of given length. Example: Input: arr[] = {1, 12, -5, -6, 50, 3}, k = 4 Output: Maximum average subarray of length 4 begins at index 1.

You can use np.vectorize in your calculation to apply the mean function to each item in the list of arrays:

means = np.vectorize(np.mean)(a_split)

The result is a list with the mean for each sub-array you create.

Maximum Average Subarray I, You're getting the error because np.array_split returns a python list of numpy array, not a multidimentional numpy array, so axis wouldn't work  Step 1 : First we compute the sum of the first subarray of size k and store it in sum_here and update the maximum sum to Step 2 : Now we traverse the array by subtracting the first element and adding the present element. a. Initialize the Step 3 : We compare the sum_here at every index value

Find the subarray of given length with least average, Elements of the given array will be in the range [-10,000, 10,000]. Accepted. 74,047. Submissions. 179,498. Initialize index =0, which is the starting index of the subarray with least average. 2. Find the sum of first X elements and store it in sum variable. 3. Initialize least_sum to the above sum variable. 4. Traverse the array from (X+1)th index till end of the array a. For every element arr[i], calculate sum = sum + arr[i] -arr[i-X] b.

Maximum average subarray of size k- IDeserve, Algorithm. 1. Initialize index =0, which is the starting index of the subarray with least average. 2. Find the sum of first X elements and store it in sum variable. 3. Given an array consisting of n integers, find the contiguous subarray of given length k that has the maximum average value. And you need to output the maximum average value. Example 1: Input: [1,12,-5,-6,50,3], k = 4 Output: 12.75 Explanation: Maximum average is (12-5-6+50)/4 = 51/4 = 12.75.

Maximum average subarray of size k, Maximum average subarray of size k is a subarray (sequence of contiguous elements in the array) for which the average is maximum among all subarrays of​  Average value of the array elements is : 7.0. Flowchart: Visualize Java code execution (Python Tutor): Java Code Editor: Improve this sample solution and post your code through Disqus. Previous:Write a Java program to print the following grid. Next:Write a Java program to test if an array contains a specific value.

Comments
  • I appreciate your help.
  • I appreciate it.
  • You might want to add this from the doc on np.vectorize : The vectorize function is provided primarily for convenience, not for performance. The implementation is essentially a for loop..
  • I appreciate it.