## Average of elements in a subarray

subarray with least average

what is maximum average

counting subarrays

maximum subarray length

maximum sum of subarray

largest sum subarray of size k

maximum sum subarray indices

I have an array like `a=[1, 2, 3, 4, 5, 6, 7]`

. I want to split this array into 3 chunks of any size.

When I split this into 3 chunks, I get 3 subarrays: `[array([1, 2, 3]), array([4, 5]), array([6, 7])]`

.

My goal is to get an array with the average of the elements in a subarray: `[2, 4.5, 6.5]`

, since `(1+2+3)/3=2`

(first element), `(4+5)/2=4.5`

(second element), and so on.

I tried the following code:

import numpy as np a=[1, 2, 3, 4, 5, 6, 7] a_split=np.array_split(a, 3) a_split_avg=np.mean(a_split, axis=1)

I am getting the following error: `tuple index out of range`

.

You're getting the error because `np.array_split`

returns a python list of numpy array, not a multidimentional numpy array, so `axis`

wouldn't work with it. Replace the last line with this:

a_split_avg = [np.mean(arr) for arr in a_split]

**Count the number of sub-arrays such that the average of elements ,** Given an array of integers arr[], the task is to count the number of sub-arrays such that the average of elements present in the sub-array is greater than the average Longest subarray having average greater than or equal to x | Set-2; Maximum average of a subarray of size of atleast X and atmost Y; Find the average of first N natural numbers; Find average of two numbers using bit operation; Program to find simple moving average; Find the deleted value from the array when average of original elements is given

Here's a vectorized solution that avoids the splitting step to gain performance and directly gets the grouped summations and hence averages -

def average_groups(a, N): # N is number of groups and a is input array n = len(a) m = n//N w = np.full(N,m) w[:n-m*N] += 1 sums = np.add.reduceat(a, np.r_[0,w.cumsum()[:-1]]) return np.true_divide(sums,w)

Sample run -

In [357]: a=[1, 2, 3, 4, 5, 6, 7] In [358]: average_groups(a, N=3) Out[358]: array([2. , 4.5, 6.5])

**Program for average of an array (Iterative and Recursive ,** How do you find the average of an element in an array? Maximum Average Subarray Average Rating: 4.54 (13 votes) July 15, 2017 | 30.8K views Elements of the given array will be in the range [-10,000, 10,000].

Try this:

In [1224]: mean_arr = [] In [1225]: for i in a_split: ...: mean_arr.append(np.mean(i)) In [1226]: In [1226]: mean_arr Out[1226]: [2.0, 4.5, 6.5]

**Average of elements in a subarray,** How do you find the average of an array element in Java? Given an array with positive and negative numbers, find the maximum average subarray of given length. Example: Input: arr[] = {1, 12, -5, -6, 50, 3}, k = 4 Output: Maximum average subarray of length 4 begins at index 1.

You can use `np.vectorize`

in your calculation to apply the `mean`

function to each item in the list of arrays:

means = np.vectorize(np.mean)(a_split)

The result is a list with the mean for each sub-array you create.

**Maximum Average Subarray I,** You're getting the error because np.array_split returns a python list of numpy array, not a multidimentional numpy array, so axis wouldn't work Step 1 : First we compute the sum of the first subarray of size k and store it in sum_here and update the maximum sum to Step 2 : Now we traverse the array by subtracting the first element and adding the present element. a. Initialize the Step 3 : We compare the sum_here at every index value

**Find the subarray of given length with least average,** Elements of the given array will be in the range [-10,000, 10,000]. Accepted. 74,047. Submissions. 179,498. Initialize index =0, which is the starting index of the subarray with least average. 2. Find the sum of first X elements and store it in sum variable. 3. Initialize least_sum to the above sum variable. 4. Traverse the array from (X+1)th index till end of the array a. For every element arr[i], calculate sum = sum + arr[i] -arr[i-X] b.

**Maximum average subarray of size k- IDeserve,** Algorithm. 1. Initialize index =0, which is the starting index of the subarray with least average. 2. Find the sum of first X elements and store it in sum variable. 3. Given an array consisting of n integers, find the contiguous subarray of given length k that has the maximum average value. And you need to output the maximum average value. Example 1: Input: [1,12,-5,-6,50,3], k = 4 Output: 12.75 Explanation: Maximum average is (12-5-6+50)/4 = 51/4 = 12.75.

**Maximum average subarray of size k,** Maximum average subarray of size k is a subarray (sequence of contiguous elements in the array) for which the average is maximum among all subarrays of Average value of the array elements is : 7.0. Flowchart: Visualize Java code execution (Python Tutor): Java Code Editor: Improve this sample solution and post your code through Disqus. Previous:Write a Java program to print the following grid. Next:Write a Java program to test if an array contains a specific value.

##### Comments

- I appreciate your help.
- I appreciate it.
- You might want to add this from the doc on
`np.vectorize`

:`The vectorize function is provided primarily for convenience, not for performance. The implementation is essentially a for loop.`

. - I appreciate it.