## How do I subtract the smallest number from each integer in a list using a while loop?

python subtract number from every element in list

how to subtract array elements

maximum and minimum loop python

find smallest number with given number of digits and sum of digits

java program to find smallest digit in a number

input:

5 30 50 10 70 65

5 is how many numbers follow after.

My code:

n = int(input()) list = [] i = 0 while len(list) < n: integer = int(input()) list.append(integer) i = i + 1 minList = min(list) integers = list[i - 1] - minList print(integers)

I'm suppose to subtract the smallest number from the 5 integers.

The correct output: 20 40 0 60 55

My output: 0 20 0 60 55

I understand why my output is wrong since the smallest number is 20 until 10 is inputed, but I don't know how to correct it. I tried different ways, but none of them work. How do I subtract the smallest number from each integer?

Collect all the input first, then find the minimum value and print the numbers.

n = int(input()) numbers = [] while len(numbers) < n: integer = int(input()) numbers.append(integer) smallest = min(numbers) for number in numbers: print number - smallest

**How to subtract from a list by the smallest value in the list?,** Is it possible to do it without it leaving the 2 highest value integers ? If you actually want each min and have to go one by one keep going until the list is empty: If you want to repeatedly remove the smallest element in this list and Your problem is that you're using a for loop on a list while modifying it To subtract larger numbers, stack one on top of the other as you do with addition. (For subtraction, however, don’t stack more than two numbers — put the larger number on top and the smaller under it.) For example, suppose you want to subtract 386 – 54. To start out, stack the two numbers and begin subtracting in the ones column: 6 – 4 = 2: 386

size = int(input()) lst = [int(input()) for _ in range(size)] m = min(lst) res = [abs(n - m) for n in lst]

**While loop - Learn Python 3,** On each iteration we cut the last digit of the number using integer division by 10 ( n //= 10 ). In the variable length we count how many times we did that. In Python Questions: I’m still reading the Python 3.1.3 tutorial and encountered the following problem: How do you remove a value from a group of numbers? # A list with a group of values a = [49, 51, 53, 56] How do I subtract 13 from each integer value in the list?

Get the inputs to a list. Take minimum of this list using `min()`

and then subtract minimum value from each of the list elements:

n = int(input()) # Read number of numbers lst = [] for _ in range(n): lst.append(int(input())) # Append to list min_value = min(lst) # Take the minimum number final_lst = [abs(x-min_value) for x in lst] # Subtract minimum from each number

**Find smallest number with given number of digits and sum of digits ,** Julia, Kotlin, Linked List, Linux-Unix, Machine Learning, Mathematical, Matrix, MCQ, Misc How to find the smallest number with given digit sum s and number of digits d? int res[m];. // deduct sum by one to account for cases later. // (There must be 1 left for the most significant res[0] = s + 1; // The initially subtracted 1 is. I have a list a = [49, 51, 53, 56] How do I subtract 13 from each integer value in the list?

This looks like a default puzzle for sites like Hackerrank ... take all the inputs , then perform your operations on all inputs. Do not meddle with data while still gathering inputs (unless it makes sense to do so).

A nice way of getting all the data is:

n = int(input()) # get how many inputs follow # get n inputs, perform the int() conversion, store as list. data = list(map(int, (input().strip() for _ in range(n)))) # calculate the min value min_value = min(data) # print all reduced values in order each on one line print( *[x-min_value for x in data], sep = "\n") # or comma seperated: print( *[x-min_value for x in data], sep = ",")

Output:

# print with sep="\n" 20 40 0 60 55 # print with sep="," 20,40,0,60,55

Read the doku for map(), int(), min() and look at Built in functions: do not use those as names for your variables, neither use `list`

,`dict`

,`set`

,`tuple`

.

**Subtraction in the Array,** Given an integer k and an array arr[], the task is to repeat the following operation exactly k times: Find the minimum non-zero element in the array, print it and then subtract this number from all the non-zero elements of the array. If all the elements using namespace std;. #define ll long while (i < n && arr[i] - sum == 0). i++;. The while-loop passes over a range of numbers. In it, we use an iteration variable named i. On the first line of the while-loop, we specify a condition. Less than 10: This while-loop continues as long as the variable i has a value less than 10 when the statement is encountered. And: After each iteration, the variable i has 2 added to it. When

Try this:

l = list() for _ in range(int(input())): l.append(int(input())) xmin = min(l) print(*[x - xmin for x in l])

Output:

C:\Users\Documents>py test.py 5 30 50 10 70 65 20 40 0 60 55

**are an infinite loop because there is no iteration ,** Updating a variable by adding 1 is called an increment; subtracting 1 is called a decrement. One form of iteration in Python is the while statement. Here is a When the loop has completed, smallest contains the minimum value in the list. @Sven Marnach Another obvious issue I have encountered while using both map() and the numpy array, is unequal array length. IF A is shorter ,Is it possible to subtract 1 list from another, for the length of the shortest list? something like: for i in A: C = map(sub,A,B) – manengstudent Jul 27 '12 at 14:49

**Lists,** The following list contains a string, a float, an integer, and (lo!) another list: ['spam' A list that contains no elements is called an empty list; you can create one with empty This loop traverses the list and updates each element. len returns the number of numlist = list() while ( True ) : inp = raw_input('Enter a number: ') if inp The "While" Loop . A "While" Loop is used to repeat a specific block of code an unknown number of times, until a condition is met. For example, if we want to ask a user for a number between 1 and 10, we don't know how many times the user may enter a larger number, so we keep asking "while the number is not between 1 and 10".

**9. Lists,** A list is an ordered set of values, where each value is identified by an index. The following list contains a string, a float, an integer, and (mirabile dictu) The function len returns the length of a list, which is equal to the number of its elements. to the while loop from the Accessing elements section written with a for loop. Subtract same number from a range of cells using paste special. EXCEL. Select the number that you want to subtract > Copy > Select the range that you want to subtract from > Select the Home tab > Clipboard group > Click Paste > Click Paste Special > Select All > Select Subtract > Click OK.

**[PDF] Java Loops & Methods The while loop Syntax: while ( condition is ,** false, execution continues with the statements that appear after the loop. Example: can we determine how many times this loop will run? No! We'll use a while loop to solve it, though: Why is this one an infinite loop? count starts at 1, then goes to 3, 5, 7, 9, 11, etc., never MIN_VALUE; //initialize to smallest int possible. Let’s assume that you have no information about the integer values in the array. They could be positive or negative, and we know nothing about the range of the numbers.

##### Comments

- Your indentation if off - currently all is below the while list - the code you use there makes no sense and would throw plenty of errors. Also: dont name your variables after built ins - the name
`list`

is already taken by the datastructure. Use`data`

,`numbers`

or call it`hugo`

so you do not shadow said built ins - What is the purpose of i = 0?
- It was copied from the original code and I forgot to remove it. I'll remove it now.