list of dictionaries (create/handle)

python list of dictionaries get value
iterate list of dictionaries python
python dictionary with list as value
python dictionary value list append
dictionary inside list python
python update dictionary value list
python dictionary append
list of dictionaries python to dataframe

I am trying to create 10 rooms that have a random number of boxes and apples. When I try to display them I get this error: "IndexError('list index out of range',)" Also, I am looking for the best method to handle multiple dictionaries and work on them. This is my code:

for i in range(1,11):
for i in range(1,11):

It doesn't work here because indexes are from 0 to 9 on your list of dicts and you ask for the dict at the index 10

Replace both range(1,11) by range(10) and it will work.

Python, are accessed via keys and not via their position. Again, keep in mind that the data passed to json_normalize needs to be in the list-of-dictionaries (records) format. As mentioned, json_normalize can also handle nested dictionaries. Here's an example taken from the documentation.

The issue is that you are using:

for i in range(1,11)

to iterate through your list. Your list of rooms has a length of 10. However, you are looking to iterate through a 11th item, which of course does not exist (remember that python uses 0 indexing)

Instead, use:

for i in range(10)

Before we dive into our discussion about lists and dictionaries in Python, we'll define both Figure 4 - Creating a list and adding new elements. Create list from string. How to create list of dates between two dates? How to Create list of Domains and its User Names from the Network using C# Subform - create list of records. Request.Form [""] - catch all and create list. Create list of dependencies and dependants. tools to create class dictionaries for documentation.

Its showing error because rooms does not have any index '10'

there is a better way to do it using list comprehension

import random

rooms=[{'apples':random.randint(0,3),'box':random.randint(0,2)} for i in range(10)]

for d in rooms:

also if you are creating 10 rooms then you can do range(10) there is no need of range(1, 11)

Watch Now This tutorial has a related video course created by the Real Python You can define a dictionary by enclosing a comma-separated list of key-value  Print a dictionary line by line using for loop & dict.items() dict.items() returns an iterable view object of the dictionary that we can use to iterate over the contents of the dictionary, i.e. key-value pairs in the dictionary and print them line by line i.e.

To iterate over all the elements in a collection, you can use the following:

for room in rooms:

When you iterate with the range(...), you're effectively doing the same thing with a collection of numbers. You can think of it as this:

for index in [1,2,3,...11]:

The first way expresses what you want more directly, and will avoid the off-by-one error with your range statement.

Now, let's see different ways of creating a dictionary of list. Note that the restriction with keys in Python dictionary is only immutable data types can be used as keys,  import pandas dataframe = pandas.read_csv(filepath) list_of_dictionaries = dataframe.to_dict('records') dataframe.to_csv(filepath) pandas will take care of opening the file for you if you give it a path, and will default to utf8 in python3, and figure out headers too. a dataframe is not the same structure as what CSV gives you, so you add one

import random
for i in range(1,11):
for i in range(0,10):

EDIT 1: When you are creating rooms list using first loop for i in range(1,11) but in rooms list indexing start from 0 so rooms list contain item from index 0 to 10. So while printing the list after appending dict to it you have to start indexing from 0 to the length of list.

Always check first length of list and starting and ending index of list and then start printing elements This method you write is applicable when you modify existing list on some particular index. So take care of indexing while working with list.

Both the dictionary and list are ubiquitous for representing real-world data. we'll find ourselves using strings as keys when manually creating dictionary objects and The dictionary implementation, however, can handle additions to the data​  For a more complete list of notable online dictionaries, see Category:Online dictionaries. The examples and perspective in this article deal primarily with the English-speaking world and do not represent a worldwide view of the subject. You may improve this article, discuss the issue on the talk page, or create a new article, as appropriate.

Tuples. Tuples are pretty easy to make. You give your tuple a name, then after that the list of values it will carry. For example,  In the above program, we create an empty dictionary 3 inside the dictionary people. Then, we add the key:value pair i.e people[3]['Name'] = 'Luna' inside the dictionary 3 . Similarly, we do this for key age , sex and married one by one.

It returns a view object or iterator to the list of all keys in dictionary. We can use this object for iteration or creating new list. Let's use that to get  Converting a list to dictionary with list elements as keys in dictionary. using dict.fromkeys () '''. dictOfWords = dict.fromkeys(listOfStr , 1) dict.fromKeys () accepts a list and default value. It returns a dictionary with items in list as keys. All dictionary items will have same value, that was passed in fromkeys ().

It returns a view object / iterator to the list of all values in dictionary. We can use this object for iteration or creating new list. Let's use that to get  Dictionaries are Python’s implementation of a data structure that is more generally known as an associative array. A dictionary consists of a collection of key-value pairs. Each key-value pair maps the key to its associated value. You can define a dictionary by enclosing a comma-separated list of key-value pairs in curly braces ( {} ). A

  • In python lists are zero indexed. Replace both range(1, 11) with range(10)
  • When iterating over the contents in a list, just do for item in rooms: print(item). (That would work for you bottom loop)
  • rooms[10] does not exists as last index would be 9 and not 10.As commented by other changing to range(10) should solve the problem
  • Possible duplicate of IndexError: list index out of range and python
  • Thank you for the code snippet, which might provide some limited, immediate help. A proper explanation would greatly improve its long-term value by describing why this is a good solution to the problem, and would make it more useful to future readers with other similar questions. Please edit your answer to add some explanation, including the assumptions you've made.
  • @sepehr Understand.