awk or sed to remove text after last digit in field

awk remove everything after character
sed remove last character from each line
sed remove everything after last occurrence of character
sed remove everything after character
sed remove first character from specific line
bash remove everything after last slash
sed remove special characters
sed remove last n characters

In the tab-delimited file below I am trying to remove the text after the last digit in $1. I have tried twosed commands and gotten close but not the desired output. I don't know if I am using the best approach. Thank you :).


chr7:55249071C>T    EGFR
chr7:55242469_55242477delTTAAGAGAAG EGFR

desired output

chr7:55249071   EGFR
chr7:55242469_55242477  EGFR


sed 's/[0-9]//g' file

chr:C>T EGFR

sed 's/[a-z]//g' file

7:55249071C>T   EGFR
7:55242469_55242477TTAAGAGAAG   EGFR

How can I remove the text from a line after a certain character with awk, There are two general approaches. Set awk 's field separator to that character. You can then get the parts you want as $1 : $ echo "Today was  In the awk below I am trying to print the entire line, along with the header row, if $2 is SNV or MNV or INDEL. If that condition is met or is true, and $3 is less than or equal to 0.05, then in $7 the sub pattern :GMAF= is found and the value after the = sign is checked.

If it's guaranteed that your input has only two tab delimited fields you can use this:

sed 's/[^0-9]\+\t/\t/' file

sed - 20 examples to remove / delete characters , 9. To remove last n characters of every line: $ sed -r 's/.{3}$//' file Li (so I inserted one char before% and I removed/deleted 1 char after % thx. Using sed/awk/replace, in the above text I want to remove anything that comes after the first space in each line. For example the output will be: aaaaaaaa bbbbbbbb ccccccccccccccc ddddd any help will be appreciated.

This might work for you (GNU sed):

sed 's/\(.*[0-9]\)\S\+/\1/' file

Match up to the last numeric digit and store as a back reference and remove any non-space characters following it.

command line - Cutting all the characters after the last /, If parameter is @ or *, the pattern removal operation is applied to each Another way is to use grep to only display the last slash per line and empty string ( which really is "dereferencing" of the number of fields NF variable ): hai guys, pick the 1st field and calculate max length. if suppose max length is 2, then compare the all records if <2 then add zero's prefix of the record. for ex:,sname 1,djud 37,jtuhe in this max length of the 1st field is 2 right the output wil be,sname 01,djud

sed, a stream editor, The following example prints the first line of the first file ( one.txt ) and the last line of [addr] can be a single line number, a regular expression, or a range of lines If pattern space contains newlines, delete text in the pattern space up to the first The following command prints lines in /etc/passwd which end with ' bash ':. I'm trying to change the delimiter after the 4th column. So every semi-colon after identite will be changed to a ,. I've tried that . awk '$4=$4' FS=";" OFS="," filename but it is changing everything to a comma. if you have any tips, I'm all ears. Answer: You can specify the occurrence using sed: sed 's/;/,/4g' file Results:

[PDF] grep, awk and sed – three VERY useful command-line utilities Matt , following case, grep will print every line that does not contain the string "boo," and will display the line numbers, as in the last example grep -vn on each line of the file, and finally there is an optional END{} section of actions that happen after the input file) and NF which is the number of fields in the current line. AWK can  Classic solution with awk, that treats / as field separator for both input and output and sets the last field to empty string ( which really is "dereferencing" of the number of fields NF variable ):

sed - delete everything until the first digit comes up, Hi, I have a text file with content as follows: pre { overflow:scroll; margin:2px; So I need the correct "sed" command to delete everything until the first number. but from your sample file, seems you need output last column. you can try this: file: report.txt i like very much but john is good boy i will love u so after execute.