Required regex to avoid requested value occurs multiple times in given array

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I have array from request. I want to validate it. E.g. If I have array,

$array = ['red', 'yellow', 'green', 'red'];

$request = ['colour' => 'red'];

In above case it should through validation as request value presents multiple times in given array.

So according to your new specs and edited question:


$array = ['red', 'yellow', 'green', 'red'];

$request = ['colour' => 'red'];

// Error counter
$errors = 0;

// If request shows up in the array.. move to next block
if( in_array( $request['colour'], $array ) ){

  /* Check how many times this key value shows up,then assign to count 
     In this example, $request['colour'] is red
     array_count_values($arr) returns an array 
        $array['red'=> 2,'yellow'=> 1,...], so 
     show me the **count** in this array at array_key position for "red", 
     being two.
    $count = array_count_values( $array )[ $request['colour'] ];
    // if this count is more than 1, increment our error flag for use later
    if ($count > 1){
        echo "Ut oh, this value shows up more than once in our array";


or for simplicity:

$count = array_count_values( $array )[ $request['colour'] ];

if ($count > 1){ $errors++; }

echo $errors;

Select Count Matches in the Search menu to see how many times this regular Replace method will remove the regex match from the string, and insert the replacement NET (dot net) where backreferences are made available as an array or If the words may also occur in reverse order, we need to specify the opposite  You're not doing anything wrong. It's just the way a regex works (otherwise matching would become O(n^2), since regex matching is done in linear time, this cannot be processed). In this case you could simply search for [\w]+. And postprocess these groups.

I think this is what you want if I understand your quetion properly

$array = ['red','red','yellow','green'];
$arr = array_unique($array);
// $arr would now be ['red','yellow','green'];

if I misunderstood this will give you the count of appearances in an array

Both of those regular expression objects represent the same pattern: an a character To indicate that a pattern should occur a precise number of times, use braces. Other than that, the object looks like (and in fact is) an array of strings, whose first element is the String values have a match method that behaves similarly. I am trying to match a regex pattern in Java, and I have two questions: Inside the pattern I'm looking for there is a known beginning and then an unknown string that I want to get up until the first occurrence of an &. there are multiple occurrences of these patterns in the line and I would like to get each occurrence separately.

If you want the count of each item in the array you can use array_count_values.

This will return an array with key "red" and the value 2.


If you only want "red" as the output you can use array_diff to sort out all values that is 1.

$array = ['red', 'yellow', 'green', 'red'];

$counts = array_count_values($array);
$oneOrMore = array_diff($counts, [1]);


//array(1) {
//   ["red"]=>int(2)

For example, a method with an array argument, such as every program's main method You need to learn the syntax of Java regular expressions. Mrs. And .​* means “any character, any number of times,” and is similar in meaning to most package java . util . regex ; public final class Pattern { // Flags values ('or' together)  Get the index and last index of an int type value array: 31. Get the index and last index of a short type value array: 32. Get the index and last index of a char type value array: 33. Get the index and last index of byte type array: 34. Get the index and last index of a double type array: 35. Get the element index and last index in a float type value array: 36.

11.1.1 The Set Class A set is a collection of values, like an array is. Unlike arrays, however, sets are not ordered or indexed, and they do not allow or it is not a member; it is not possible to ask how many times a value appears in a set. to the Set() constructor need not be an array: any iterable object (including other Set​  Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length.

more prolog declarations :) (: {#if "value"||$i}) return (map:keys($m1), - $m1("abc'), deep-equal($m 1,5m2)) GIVES 1 abd 123 array: append, array:Subarray, array: remove, array; insert-before, array:head, array; 2 times "aa aa bb cc" contains text "aa" true occurs from 2 to 3 times "aa bb CC"  Any multiple occurrences captured by several groups will be exposed in the form of a classical array: we will access their values specifying using an index on the result of the match.

To match a character having special meaning in regex, you need to use a regex with global modifier # Store all matches in an array print "@matches\n"; (​$inStr =~ /$regex/g) { # The built-in array variables @- and @+ keep the start w​{2,3})+ specifies that the above sub-expression could occur one or more times, e.g.,  I have 21 parts labeled PP1 through PP21. I can use 4 (or less) parts per run. Example: Run 1 - PP1, PP5, PP7, PP21; Run 2 PP5, PP8, PP10, PP12 etc. After 25 usages of each part, I need to

  • You don't need regex for this, just use in_array().
  • I want to through validation error and also want to check is this key presents multiple times in this array not once.
  • See array_count_values()
  • Hi, sorry for late but I added my comment in question tab. What actually I want.