Why do I keep getting 0 My C Code won't enter Switch

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Write a C program that computes the maximum, minimum, sum and average of 4 integers.

This program reads 4 integers in decimal, hexadecimal or octal formats and a character that specifies the math operation (x for maximum, m for minimum, s for sum, a for average) from command prompt (xterminal on Ubuntu) and prints the result of the operation.

The input/output fomat details are provided below.

Result should be printed as integer for x, m and s operations; but as a floating point number for the average (a) operation.

The integer outputs will be printed in hexadecimal format, and the floating point values will be printed in scientific format. Input:

<number 1>[space] <number 2>[space] <number 3>[space] <number 4>[space] <operation>

Sample Input1: 0xFF 99 077 0 s , Expected Output1:0x1a1

Sample Input2:0x10 10 10 010 a , Expected Output2:1.100000e+01

Sample Input3: 0770 0xFF 270 0xAB m , Expected Output3: 0xab

Sample Input4: 010 0x10 10 0x3 x , Expected Output4:0x10

Here's the code I've written

#include <stdio.h>

int main() {
  int num1, num2, num3, num4;
  char op;

  scanf("%d%d%d%d%c", &num1, &num2, &num3, &num4, &op);

  switch (op)
  {
  case'x':
    if (num1 > num2&&num1 > num3&&num1 > num4)
      printf("%d", num1);
    else if (num2 > num1&&num2 > num3&&num2 > num4)
      printf("%d", num2);
    else if (num3 > num1&&num3 > num1&&num3 > num4)
      printf("%d", num3);
    else
      printf("%d", num4);
    break;
  case'm':
    if (num1 < num2&&num1 < num3&&num1 < num4)
      printf("%d", num1);
    else if (num2 < num1&&num2 < num3&&num2 < num4)
      printf("%d", num2);
    else if (num3 < num1&&num3 < num1&&num3 < num4)
      printf("%d", num3);
    else
      printf("%d", num4);
    break;
  case's':
    printf("%d", num1 + num2 + num3 + num4);
    break;
  case'a':
    printf(" %f", (num1 + num2 + num3 + num4) / 4);
    break;
  }

  return 0;
}

You need to add space between %d's.Here is a good description why you need space . So the code will become

scanf("%d %d %d %d %c",&num1,&num2,&num3,&num4,&op);

To print in hexadecimal format you need to use, "%x" for ex.

printf("%x",num1);

To print in scientific format,use "%.10e"

printf("%.10e",num1);

One more thing,in order to get a floating point number in division and every number is integer, you need to make at least numerator or denominator floating point. In your case,

printf("%.10e"(num1+num2+num3+num4)/4.0);

Multiple problems here: First problem: You're using both m and n before assigning them any valid value (so their initial value is most likely huge). Second​  I am wondering why my C program does not print any information. I am 100% new to programming, and have been able to learn a few things in Ruby and Python these past few weeks, but I am getting nowhere with the C stuff. Here is the total baseline, simple program that everyone learns first:

Adding a printf("0x%2x", op); after your scanf() results in 0x20 being printed out.

0x20 is the hex value for the space character, thus confirming our suspicions that a whitespace character was being read instead of your wanted operator.

Replacing the format string in scanf() (%d%d%d%d%c) with %d%d%d%d %c causes the method to work properly, since the whitespace character is now ignored before the operator.

Input: 1 2 3 4 x

Output: 4

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Comments
  • Before the switch, you should display what values have been read (with some printf("%d... %c", ...);
  • the problem may be with the %d%d%d%d%c format string. you are wanting the inputs to be spaced out, but the format string doesn't. (at least for the %c part)
  • The op read the space character between the 4th number and <operation> instead of <operation> character. Try once with eliminating the space between 4th number and <operation> or add space between %d and %c.
  • Also, always check the return value of scanf to see whether it parsed all the values you wanted. Otherwise you could be using uninitialized variables.
  • As a general rule -- an important one which I strongly recommend to follow -- one should inspect the return values of functions. scanf() returns the number of items successfully converted; in your case it should return 5, I think. Does it?
  • %d already skips leading whitespace; it's just the %c that needs a space before.
  • The %d operations already skip white space; the spaces between then are not needed. The space between %d %c is crucial; the %c (and %[…] and %n) conversion specifiers do no skip white space.