I'm getting a TypeError for a += b, but not b += a (numpy)
why I'm getting
a += b but it works fine for
b += a for below code
import numpy as np a = np.ones((2,3), dtype=int) b = np.random.random((2,3)) a += b
Report the whole TypeError!
----> 3 a += b TypeError: Cannot cast ufunc add output from dtype('float64') to dtype('int64') with casting rule 'same_kind'
a is integer dtype, right?
b is float. Add a float and integer and the result is a float. But
a+=... is expected to put that float into
a, the integer array.
numpy does not want to do that.
But this is fine:
In : a = a + b In : a Out: array([[1.01407496, 1.96122364, 1.91447533], [1.68130058, 1.99773138, 1.50043386]])
The original integer array,
a has now been replaced by a float array. That's a Python level assignment, where as
a+=... attempts to modify the original
a array (in-place). The distinction is important.
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The error message will give you a hint:
TypeError: Cannot cast ufunc add output from dtype('float64') to dtype('int32') with casting rule 'same_kind'
a is an array of
b is an array of
float64s. Adding an
int32 and a
float64 (nevermind which comes first), will produce a
float64. This value cannot be stored in
a, but can be stored in
If you define
a to use
a+=b would be perfectly legal:
a = np.ones((2,3), dtype=float)
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a is a numpy array with types
int and your variable
b is a numpy array with types
float. When add
a it will try to convert these floats to integers which looses information. However, when you do it the other way around you cast an integer to a float, which is perfectly fine.
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