Add blank line after every result in grep

Add blank line after every result in grep

grep add new line after match
grep new line for every match
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line separator in shell script

my grep command looks like this zgrep -B bb -A aa "pattern" *

I would lke to have output as:

file1:line1
file1:line2
file1:line3
file1:pattern
file1:line4
file1:line5
file1:line6
            </blank line>
file2:line1
file2:line2
file2:line3
file2:pattern
file2:line4
file2:line5
file2:line6

The problem is that its hard to distinguish when lines corresponding to the first found result end and the lines corresponding to the second found result start.

Note that although man grep says that "--" is added between contiguous group of matches. It works only when multiple matches are found in the same file. but in my search (as above) I am searching multiple files.

also note that adding a new blank line after every bb+aa+1 line won't work because what if a file has less than bb lines before the pattern.


pipe grep output through

awk -F: '{if(f!=$1)print ""; f=$1; print $0;}'

the hold space starts out empty and is only used by some commands. The G command appends a newline and the contents of the hold space to the pattern space. The above sed up vote 3 down vote. Is this what you are after? grep SPAM mail.log | while read -r line; do echo; echo $line; done Pipe | any output to: sed G  If you don't mind a --in lieu of a </blank line>, add the -0 parameter to your grep/zgrep command. This should allow for the -- to appear even when searching multiple files. You can still use the -A and -B flags as desired.


I can't test it with the -A and -B parameters so I can't say for sure but you could try using sed G as mentioned here on Unix StackEx. You'll loose coloring though if that's important.

I'm using grep to grep very long lines in a text file. When I get results I want to put a blank line after each line found. How do i do this? Man pages did not have an  that list and insert each group of rows into a #temp table and insert a blank row after each insert. I was hoping there was a simpler way to do it without a loop.


The problem is that its hard to distinguish when lines corresponding to the first found result end and the lines corresponding to the second found result start.

Note that although man grep says that "--" is added between contiguous group of matches. It works only when multiple matches are found in the same file. but in my search (as above) I am searching multiple files.

If you don't mind a -- in lieu of a </blank line>, add the -0 parameter to your grep/zgrep command. This should allow for the -- to appear even when searching multiple files. You can still use the -A and -B flags as desired.

If pattern not found append a blank line to file3. do grep $line file2 >> file3 ok if you run the script as you posted itno lines after the grep and before the if. 6 6 i need to insert a blank line in the file if i don't find a match and put the items at  In this article, we will see the different ways in which we can insert a line before or after on finding a pattern. On finding the pattern 'Fedora', the requirement is to insert a line: The '1' at the end prints every line by default. On finding the pattern 'Fedora', 'Cygwin' is printed. Hence, first "Cygwin" gets printed followed by 'Fedora' (1).


There is no option for this in grep and I don't think there is a way to do it with xargs or tr (I tried), but here is a for loop that will do it (for f in *; do grep -H "1" $f && echo; done):

[ 11:58 jon@hozbox.com ~/test ]$ for f in *; do grep -H "1" $f && echo; done

a:1

b:1

c:1

d:1

[ 11:58 jon@hozbox.com ~/test ]$ ll
-rw-r--r--  1 jon  people     2B Nov 25 11:58 a
-rw-r--r--  1 jon  people     2B Nov 25 11:58 b
-rw-r--r--  1 jon  people     2B Nov 25 11:58 c
-rw-r--r--  1 jon  people     2B Nov 25 11:58 d

The -H is to display file names for grep matches. Change the * to your own file glob/path expansion string if necessary.

I've this task, to search in file2 based on pattern in file1 and output it to file3. sed - How to insert line before the first blank line following a token. Hello. I have a​  grep N lines after match and then print them on 1 line each Hello I need some help with this job. file.txt ----- cut ---- TARGET 13/11/08 20:43:21 POINT 1 MOVE 8 772102y64312417771 TARGET 13/11/08 21:10:01 POINT 2 MOVE 5 731623jjd12njhd ----- cut ---- this is the example. i need to grep for the word TARGET and print next 4 lines like


Try with -c 2; with printing a context I see grep is separating its found o/p

Insert a blank line above and below every line that matches "regex". sed: Insert 7: 04-01-2009 06:46 PM: grep/sed/awk - find match, then match on next line:  grep will filter out empty lines since they don't match any pattern. In the case empty line separators appear in the original file you can let them pass through, adding -e "^$" . If those empty lines are not present in the original file, you'll have to add them.


The following command modifies file.txt and does not produce any output: Add a newline to the pattern space, then append the next line of input to the to match respectively (in addition to the normal behavior) the empty string after a Basic Regular Expression (BRE) syntax is the default in sed (and similarly in grep ). I need to add a new line before any line containing a pattern where we can assume that the pattern is always the first string of the current line. For example. This is a pattern This is a pattern I can add a new line with the sed command. sed -i 's/pattern\+/ &/g' file to get the output. This is a pattern This is a pattern


You can do that with -e using a single grep command: grep -v -e "^#" -e "^$" #a uncommented line #comment below blank line. output will be: sed adding a blank line. will contain 1st line as a blank line & after every 5 lines one blank line will be inserted. but i wish to add a blank line after


sed-output. 2 – To insert two blank lines – [root@rhel7 ~]# sed 'G;G' a.txt. 3 – Delete blank lines and insert one blank line after each line – [root@rhel7 ~]# sed​  insert blank line between lines Hello, I am trying to write a script that will count the number of characters for each line in a file and all the lines that have less than 80 characters and that are ending with a period, I want it to insert a blank line after them immediately.