Not more than three consecutive repeating characters need to be returned

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I have a String of repeating or may be non repeating characters. Now I have to write a program that returns a string in such a way that if there are consecutive repeating of the same character more than 3 times, then only 3 consecutive characters should be returns. If there are less than 3 consecutive characters, all of them should be returned. Ex.

Input: "aaaaaabbcccdeeeeeeeeeeffff" Expected Output: aaabbcccdeeefff

Heres what I did:

public class StringCountUptoThree {
    public static void main(String[] args) {
        String str = "aaaaaabbcccdeeeeeeeeeeffff";
        System.out.println(stringCount(str));
    }

    public static StringBuffer stringCount(String str) {
        StringBuffer sb = new StringBuffer();
        int len = str.length();
         int j = 1;
        for (int i = 0; i < len; i++) {
            int count = 0;
         if( count >3 && (str.charAt(i)==str.charAt(j)))
                    continue;
            for (j = i + 1; j < len; j++) {
                if (str.charAt(i) == str.charAt(j)) {
                    sb.append(str.charAt(i));
                    count++;
                    if (count > 3)
                        break;
                }
            }
        }
        return sb;
    }
}

The output is coming the original string. Confused where I got wrong.

You break the loop and stop counting when you hit 3. You need to make sure you "consume" all of the remaining consecutive letters. I would break the logic up. First a method to count consecutive appearances. Like,

private static int countConsecutive(char[] arr, int i) {
    int count = 0;
    for (int j = i; j < arr.length; j++) {
        if (arr[j] == arr[i]) {
            count++;
        } else {
            break;
        }
    }
    return count;
}

Then we can invoke that to determine the correct count (and the minimum of three and that count to determine the output). And, I would prefer a StringBuilder to StringBuffer. Like,

public static String stringCount(String str) {
    char[] arr = str.toCharArray();
    StringBuilder sb = new StringBuilder();
    for (int i = 0; i < arr.length; i++) {
        int c = countConsecutive(arr, i);
        int v = Math.min(3, c);
        for (int j = 0; j < v; j++) {
            sb.append(arr[i]);
        }
        i += (c - 1); // <-- not v, but the actual count!
    }
    return sb.toString();
}

Password Policy Enforcer Repeating Characters Rule, How do you find the longest substring without repeated character? The Restriction of Repeated Characters for Passwords (QPWDLMTREP) system value limits the use of repeating characters in a password. This value provides additional security by preventing users from specifying passwords that are easy to guess, such as the same character repeated several times.

I encourage you to use a debugger and figure out what's wrong with your code. Here's an extremely simple solution I came up with.

public class StringCountUptoThree  {
    public static void main(String[] args) {
        System.out.println(stringCount("aaaaaabbcccdeeeeeeeeeeffff", 3));
    }

    private static String stringCount(String str, int k) {
        if(str.length() <= k) return str;
        int start = 0, end = 1;
        StringBuilder sb = new StringBuilder();
        sb.append(str.charAt(start));

        while(end < str.length()) {
            char chStart = str.charAt(start);
            char chEnd = str.charAt(end);
            if(chStart != chEnd){
                sb.append(chEnd);
                start = end;
            } else {
                if(end - start < k)
                    sb.append(chEnd);
            }

            end++;
        }

        return sb.toString();
    }
}

repetition can increase resistance to both brute-force and dictionary cracking algorithms. Given a string S, remove all the consecutive duplicates. Note that this problem is different from Recursively remove all adjacent duplicates. Here we keep one character and remove all subsequent same characters. The above problem can be solved using recursion. If the string is empty, return. Else compare the adjacent characters of the string.

Longest substring such that no three consecutive characters are same “​aabbabb” is the required substring. and ans as 2 initially, since this is the minimum length of the longest substring when the length of the given string is greater than 2. int main(). {. string s = "baaabbabbb" ;. cout << maxLenSubStr(s​);. return 0;. }  I want to check a text for consecutive repeating characters. For example, with a minimum of 3 consecutive chars, this should match: Okeee OOOkee Alsoook This should not match: No not okee, oh no

Given a string, you have to remove the three consecutive duplicates from the string. If no three are consecutive then output the string as it is. If the size of vector is greater than 2, then we will check whether the last 3 characters of the string are string str = "aabbbaccddddc" ;. remove3ConsecutiveDuplicates(str);. return 0;. We insert the characters of string one by one to vector and keep on checking the size of vector. If the size of vector is greater than 2, then we will check whether the last 3 characters of the string are same or not. If the characters are same then we will move three steps backwards in array using resize() else not.

Passwords with excessive repeating characters may be more vulnerable To check the maximum value for consecutive repeating characters, run the If maxrepeat is not found or not set to the required value, this is a finding. – Password must contain at least one number, at least one English uppercase character, and at least one English lowercase character. – Password must contain one special character like #,*,& – Password may not have more than two consecutive identical characters.

Password can not have 3 consecutive characters of username 3. Password can not have more than 2 consecutive repeating characters  Given a string, the task is to find maximum consecutive repeating character in string. Note : We do not need to consider overall count, but the count of repeating that appear at one place. The Simple solution of this problem is to use two for loops. The outer loop considers current character, the inner loop counts occurrences of current character.

Comments
  • Looks like homework.
  • str.replaceAll("(.)\\1{3,}", "$1$1$1")