Why won't Python store 0 in list?
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I have the following code that takes an input number, multiplies the first digit by 3 and then prints out the first digit. When I input 023, it gives me 6 instead of 0. Why is that?
a=int(input()) b=str(a) c=int(b)*3 print(c)
You are doing:
a=int(input()) So if input() = '023', int('023') will be 23. So a=23 b=str(a) => b='23' int(b) => c=2*3=6
You should do:
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If you want to keep all the digits you're entering you shouldn't convert your input into an
a=input('Enter a number: ') c=int(a)*3 print(c)
If you enter
023 this returns
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You can use a
while loop to keep asking the user for digit-only input until the user enters one, and you should use the
list() constructor to convert the digits to a list:
while True: a = input('Enter digits: ') if a.isdigit(): break print('Please enter only digits.') b=list(a) c=int(b)*3 print(c)
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- You're converting the input string to int, so the leading zero is removed.
- How should I make it not remove the 0?
- I guess by not converting it into an int:
a = input()
- How can I do it if I want to restrict the input to int?
- Why don't you make the user enter a list of integers? For doing that, I suggest you to follow this answer.
- This works but it also allows suspicious inputs to go through, such as
3foo, which might be valid or not depending on the OP's use cases.