Decimal to binary conversion for large numbers in Excel

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I have some large numbers in an Excel sheet and I want to convert them to binary.



If we are talking positive number between 0 and 2^32-1 you can use this formula:


NOTE: =DEC2BIN() function cannot handle numbers larger than 511 so as you see my formula breaks your number into four 8-bit chunks, converts them to binary format and then concatenates the results.

Well, theoretically you can extend this formula up to six 8-bit chunks. Maximum precision you can get in Excel is 15 (fifteen) decimal digits. When exceeded, only the most significant 15 digits remain, the rest is rounded. I.e. if you type 12345678901234567 Excel will store it as 12345678901234500. So since 2^48-1 is 15 decimal digits long the number won't get rounded.

Microsoft Excel converts from binary to decimal notation using the BIN2DEC function and from decimal to binary using the DEC2BIN function. Type "=DEC" without quotes in an Excel cell. Click "DEC2BIN," the first of the three options. Enter the number you wish to convert. Type a comma. Where your binary number is in A1 Mike "ahmedmidany" wrote: Hello All, I need your help, i want to convert large binary numbers using excel but whenever i use the BIN2DEC function the result is negative which is not correct. Ex. BIN2DEC(1100110110) the result is -202 but if i use the calculator the result is 822 which is the correct value

See VBA posted here

' The DecimalIn argument is limited to 79228162514264337593543950245
' (approximately 96-bits) - large numerical values must be entered
' as a String value to prevent conversion to scientific notation. Then
' optional NumberOfBits allows you to zero-fill the front of smaller
' values in order to return values up to a desired bit level.
Function DecToBin(ByVal DecimalIn As Variant, Optional NumberOfBits As Variant) As String
  DecToBin = ""
  DecimalIn = CDec(DecimalIn)
  Do While DecimalIn <> 0
    DecToBin = Trim$(Str$(DecimalIn - 2 * Int(DecimalIn / 2))) & DecToBin
    DecimalIn = Int(DecimalIn / 2)
  If Not IsMissing(NumberOfBits) Then
    If Len(DecToBin) > NumberOfBits Then
      DecToBin = "Error - Number too large for bit size"
      DecToBin = Right$(String$(NumberOfBits, "0") & _
      DecToBin, NumberOfBits)
    End If
  End If
End Function

How to convert decimal to binary in excel. Converting Decimal Numbers to 8-bit Binary Duration: 0:39 Posted: 7 Dec 2017 An emailer has a 16 digit binary string (1’s and 0’s) and a 17th bit indicating whether the number is positive or negative. He read the Decimal to Binary post and all the great comments, but wants to do the reverse. That is, he wants a UDF to convert the binary string to a decimal number. And he wants to convert negative numbers assuming

I just tried the formula above, and found that Microsoft screwed up the DEC2BIN function in another way that keeps the formula from working correctly with negative numbers. Internally, DEC2BIN uses a ten bit result; leading zeroes are dropped from the text result, unless the optional length parameter is used, in which case the required number of leading zeroes are left in the string. But here's the rub: a negative number always starts with a one, so there are no leading zeroes to drop, so DEC2BIN will always show all ten bits! Thus, DEC2BIN(-1,8), which should show 11111111 (eight ones) will instead show 1111111111 (ten ones.)

To fix this, use RIGHT to trim each eight bit chunk to eight bits, dumb as that sounds.

=RIGHT(DEC2BIN(QUOTIENT(A1,256^3),8),8) & RIGHT(...

(I read through the VBA, and it does not have the same problem, but it doesn't look like it will handle negatives at all.)

This video explains how to convert binary to decimal using excel. It discusses how to use the Duration: 6:04 Posted: 28 May 2018 How can I convert a decimal fraction (for example 10.5) to binary form and vice versa (i.e., if I have a binary form such as 10010.011 back to decimal form)? The DEC2BIN function in Excel works for Whole numbers and not fractions. Please suggest!! Search the internet for the X-Numbers add-in. The BaseChange function will do what you want.

To add easier to read formatting to Taosique's great answer, you can also break it up into chunks of 4 bits with spaces in between, although the formula grows to be a monster:

=DEC2BIN(MOD(QUOTIENT($A$1,16^7),16),4)&" "&DEC2BIN(MOD(QUOTIENT($A$1,16^6),16),4)&" "&DEC2BIN(MOD(QUOTIENT($A$1,16^5),16),4)&" "&DEC2BIN(MOD(QUOTIENT($A$1,16^4),16),4)&" "&DEC2BIN(MOD(QUOTIENT($A$1,16^3),16),4)&" "&DEC2BIN(MOD(QUOTIENT($A$1,16^2),16),4)&" "&DEC2BIN(MOD(QUOTIENT($A$1,16^1),16),4)&" "&DEC2BIN(MOD(QUOTIENT($A$1,16^0),16),4)

1101 0100 1111 0110 0011 0001 0000 0001

Of course, you can just use the right half of it, if you're just interested in 16 bit numbers:

=DEC2BIN(MOD(QUOTIENT($A$1,16^3),16),4)&" "&DEC2BIN(MOD(QUOTIENT($A$1,16^2),16),4)&" "&DEC2BIN(MOD(QUOTIENT($A$1,16^1),16),4)&" "&DEC2BIN(MOD(QUOTIENT($A$1,16^0),16),4)

0011 0001 0000 0001

Does anyone know how to convert a 4 digit number to binary in excel? I used the =DEC2BIN formula, but it only works on a 3 digit number that  I have an excel with 28 position binary numbers. I need to convert them to decimal numbers, but function bin2dec don't work with numbers longer than 10 bits.

Perhaps a simpler option:

For positive numbers only, just use BASE (as in BASE2) for numbers between 0 to 2^53 in Excel. Here are some examples:

=BASE(3,2)  # returns 11

=BASE(11,2)  # returns 1011

Credit for answer goes here:

Negative numbers: Come to think of it, negative numbers could be handled as well by building upon howy61's answer. He shifts everything by a power of two (2^31 in his case) to use the 2's complement:

=BASE(2^31+MyNum, 2)

so (using 2^8 for only 8 bits):

=BASE(2^8+(-1),2)  # returns 11111111 

=BASE(2^8+(-3),2)  # returns 11111101

The numbers given by the OP requires more bits, so I'll use 2^31 (could go up to 2^53):

=BASE(2^31+(-12457896),2)  # returns 11111111010000011110100001011000

For either positive or negative, both formulas could be coupled in a single IF formula. Here are two ways you could do it that give the same answer, where MyNum is the decimal number you start with:

=IF(MyNum<0, BASE(2^31+MyNum,2), BASE(MyNum, 2))


=BASE(IF(MyNum<0, MyNum+2^32, MyNum), 2)

I need your help, i want to convert large binary numbers using excel The most common number system is decimal, which has a base value of  NOTE: =DEC2BIN() function cannot handle numbers larger than 511 so as you see my formula breaks your number into four 8-bit chunks, converts them to binary format and then concatenates the results. Well, theoretically you can extend this formula up to six 8-bit chunks. Maximum precision you can get in Excel is 15 (fifteen) decimal digits.

Then I want to convert them into 16 bit binary numbers. A Google search for "​algorithm for converting decimal to binary" yielded several  The most straightforward way to represent an arbitrarily large binary number is an array of its binary digits. You can then apply the algorithms for addition and multiplication your learned in elementary school, except that digits will "overflow" when they exceed 1 rather than 9.

The DEC2BIN function converts a decimal number to binary. Starter 2010 More​ Less. This article describes the formula syntax and usage of the DEC2BIN function in Microsoft Excel. The decimal integer you want to convert. If number is  I am aware that you can keep dividing a decimal number by two, finding the remainders in the process, in order to convert the number to binary. However, when I am working with a long decimal number such as 2147483647, is there any easier way of converting this to binary?

Electronic memory is a collection of a large number of elements, each of which has only two Duration: 4:12 Posted: 27 Jul 2014

  • Have you tried the DEC2BIN function?
  • See…
  • DEC2BIN cannot handle number larger than 511.
  • user3103991, the information provided in the comment above by Taosique would normally be expected to be included by yourself to show some level of research effort on your part.
  • Possible duplicate of Using DEC2BIN() with large numbers
  • This is AMAZING, and strongly appreciated. Thank you!!!! And also to importantly note, SHAME ON YOU Microsoft...!
  • It's easier and clearer to use Excel's TEXT function: =TEXT( DEC2BIN(MOD(QUOTIENT(A1,256^3),256),8) & DEC2BIN(MOD(QUOTIENT(A1,256^2),256),8) & DEC2BIN(MOD(QUOTIENT(A1,256^1),256),8) & DEC2BIN(MOD(QUOTIENT(A1,256^0),256),8), "00000 0000 000 00 0") This also makes it easy to break it into different length chunks separated by spaces simply by placing the spaces where you want them in the text string. For example, if A1 contains 14,163, the text string "00000 0000 000 00 0" would give 01101 1101 010 01 1
  • Can't seem to get the formatting in the above post... I'd like to look like the comment immediately above. Can someone tell me how?
  • Welcome to SO! Code-only answers are discouraged, as they provide no insight into how the problem was solved. Please update your solution to include an explanation of how your code solves the problem at hand :)