java - how to delete a node from linkedlist?

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This code is a table that has an option to Inert name, delete, show, and quit .

this code run's well but my only problem is on how to delete a chosen name in a node

class Node{

Node in;
String name;

public Node(){

    in = null;

}

public Node(String n){

    in = null;
    name = n;

}

public void setIn(Node n){

    in = n;

}

public Node getIn(){

    return in;

}

public void setName(String n){

    name = n;

}

public String getName(){

    return name;

}




 public class Main{

public static void main(String args[]){
    Scanner scan = new Scanner(System.in);
    LinkedList bi = new LinkedList();
    while(true){

        System.out.println("Choose!\n[a] Insert Name\n[b] Delete\n[c] Show\n[d] Exit");
        char c = scan.next().charAt(0);
        System.out.println();

        if(c == 'a'){

            System.out.print("Enter Name: ");
            bi.insert(scan.next());
            System.out.println();

        }
        else if(c == 'b'){

            System.out.print("Enter Name to delete: ");
            bi.delete(scan.next());
            System.out.println();
        }
        else if(c == 'c'){

            bi.show();
            System.out.println();

        }
        else if(c == 'd'){

            System.exit(0);

        }

    }

}

  }


class LinkedList{

private Node root;

public LinkedList(){

    root = null;
}

public void insert(String n){

    root = insert(root, n);

}

private Node insert(Node n, String r){

    if(n == null){

        n = new Node(r);

    }
    else{

        n.in = insert(n.in, r);

    }

    return n;

}

public void delete(String n){

    root = delete(root, n);

}

private Node delete(Node n, String r){




}

public void show(){

    show(root);

}

private Node show(Node n){
    if(n == null){

        System.out.println("Empy list!");

    }
    else{

        while(n!=null){

            System.out.println(n.getName());
            n = n.getIn();

        }

    }

    return n;
}

 }

*i don't know how to delete a node . What should i put on my delete method?

public void delete(String n){

    root = delete(root, n);

}

private Node delete(Node n, String r){




}

To delete Node you actually need to update it's previous node's in to be deleting Node's in, and the left alone Node will eventually get garbage collected.

Just one catch if node to be deleted is the root node then update root node.

private Node delete(Node root, String data)
{
    //in case list is empty then return
    if(root==null) return n;
    //in case node to be deleted is root then just return next as new root
    if (root.name.equals(data)) return root.in;

    Node curr = root;
    while(curr.in!=null)
    {
        if (curr.in.name.equals(data))
        {
            //curr.in's referenced Node will be garbage collected (or run some cleanup manually on it)
            curr.in = curr.in.in;
            //we are done and root is same
            return root;
        }
        curr = curr.in;
    }
    //if here then not found and nothing changed
    return root;
}

Delete a Linked List node at a given position, Write a function to delete a node (except the tail) in a singly linked list, is bit confusing so the Java implementation below will make this clear. Java program to delete a node from the beginning of the singly linked list. In this program, we will create a singly linked list and delete a node from the beginning of the list. To accomplish this task, we need to make the head pointer pointing to the immediate next of the initial node which will now become the new head node of the list.

We could code this for you, but that misses the point.

Instead, I'm going to suggest that you draw the linked-list data structure on paper using boxes for the list nodes and fields of the nodes, and arrows for the pointers / references. Then draw more boxes for your algorithm's local variables ... and "hand execute" it. That will help you visualize what your code should be doing.

Once you have done this kind of thing a few times, you will be able to visualize in your head ...


can you please give me a sample ?

Sorry, but No. You will learn more by working it out for yourself. See above.

Linked List, Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Given linked list -- head = [4,5,1,9], which looks like  Delete Node at a given position in a linked list : head pointer input could be NULL as well for empty list: Node is defined as : class Node {int data; Node next;} */ // This is a "method-only" submission. // You only need to complete this method. Node Delete(Node head, int position) {// Complete this method: Node current = head; Node parent

Are you trying to remove the name from the node, or remove the node from the list? To remove the node from the list, use the LinkedList.remove(int index) method. You'll need to find the index of the node you want to remove first.

[edit] Like the others have said, you should try to solve the problem yourself, but here's a hint: you can access each node with LinkedList.get(int index). You can get the length of the list with LinkedList.size(). This is probably a good place for a "for" loop.

LeetCode – Delete Node in a Linked List (Java), Java program to delete a node from the beginning of the singly linked list on fibonacci, factorial, prime, armstrong, swap, reverse, search, sort, stack, queue,  Java program to delete a new node from the middle of the doubly linked list on fibonacci, factorial, prime, armstrong, swap, reverse, search, sort, stack, queue, array, linkedlist, tree, graph, pattern, string etc.

while (node != null) {

            if (node.getNext() == null || head.getNext() == null) {
                break;

            } else if (head.getData() == data) {
                head = head.getNext();
            } else if (node.getNext().getData()==null&&data==null||node.getNext().getData().equals(data)) {
                node.setNext(node.getNext().getNext());
            } else {
                node = node.getNext();
            }
        }
    }

    return head;

Delete Node in a Linked List - SAURAV AGGARWAL, Deleting a node from a linked list in Java. 1-linked-list-delete.java. Node Delete(​Node head, int position) {. if (head == null) {. return null;. }  Delete a Linked List node at a given position Given a singly linked list and a position, delete a linked list node at the given position.

Delete Node in a Linked List, In this article, we will discuss how to delete given node from singly linked list. Given a pointer to node to be deleted but we don't have a pointer  The Java.util.LinkedList.remove (Object O) method is used to remove any particular element from the linked list. LinkedList.remove (Object O) Parameters: The parameter O is of the object type of linked list and specifies the element to be removed from the list. Return Value: Returns true if the specified element is found in the list.

Java program to delete a node from the beginning of the singly , Given a ‘key’, delete the first occurrence of this key in linked list. To delete a node from linked list, we need to do following steps. 1) Find previous node of the node to be deleted. 2) Change the next of previous node. 3) Free memory for the node to be deleted.

Deleting a node from a linked list in Java. · GitHub, After deletion of last node. All three mentioned cases can be handled in two steps if the pointer of the node to be deleted and the head pointer is known. If the node to be deleted is the head node then make the next node as head. If a node is deleted, connect the next and previous node of the deleted node.

Comments
  • As others have said, give it a try first. Hint: Use two pointers to traverse through your list as you search for the node to delete.
  • root = null It will do nothing inside a function . Java is passed by values, not by references
  • Welcome to SO! When you reply with just code, try to explain it a little bit.