Python set a column in list of list 2D matrix

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So given two lists

y_new = (   165,     152,     145,    174)
pos_2D  = ( (2,3), (32,52), (73,11), (43,97) )

I would like to so something like

pos_2D_new = setCol(2, y_new, pos_2D)

where column 2 is the Y coordinate.

pos_2D_new = ( (2,165), (32,152), (73,145), (43,174) )

How to set a 1D into a 2D tuple in Python?

You can do this with:

pos_2D_new = [ (x, y2) for (x, _), y2 in zip(pos_2D, y_new) ]

or if you want a tuple:

pos_2D_new = tuple((x, y2) for (x, __), y2 in zip(pos_2D, y_new))

We thus concurrently iterate over the pos_2D and ynew, and each time we construct a new tuple (x, y2).

The above is of course not very generic, we can make it more generic, and allow to specify what item to replace, like:

def replace_coord(d, old_pos, new_coord):
    return tuple(x[:d] + (y,) + x[d+1:] for x, y in zip(old_pos, new_coord))

So for the x-coordinate you can use replace_coord(0, old_pos, new_x_coord) whereas for the y-coordinate it is replace_coord(1, old_pos, new_y_coord). This also works for coordinates in three or more dimensions.

Nested lists: creating. Suppose that two numbers are given: the number of rows of n and the number of columns m . You must create a  In Python any table can be represented as a list of lists (a list, where each element is in turn a list). For example, here's the program that creates a numerical table with two rows and three columns, and then makes some manipulations with it:

You can use a generator expression with zip:

pos_2D_new = tuple((x, y) for (x, _), y in zip(pos_2D, y_new))

With your sample input, pos_2D_new would become:

((2, 165), (32, 152), (73, 145), (43, 174))

For example m = [[10, 20], [40, 50], [30, 60]] represents a matrix of 3 rows and 2 columns. First element of the list – m[0] and element in first row, first column – m[0​][0  to extend this to a number of columns you could store the column number and it's value in a dict. So to set colum 5 to 10 and column 2 to 7: cols = 7 rows = 8 data = [ [0] * cols for i in range(rows)] valdict = {5:10, 2:7} for col, val in valdict.items(): for row in data: row[col] = val.

Which would give

def setCol(idx, coords_1d, coords_nd):
    # recalling that indexing starts from 0
    idx -= 1
    return [
        c_nd[:idx] + (c_1d,) + c_nd[idx+1:]
        for (c_1d, c_nd) in zip(coords_1d, coords_nd)


>>> setCol(2, y_new, pos_2D)
[(2, 165), (32, 152), (73, 145), (43, 174)]

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Create a NumPy array ndarray from the original 2D list and get the transposed object with the T attribute. If you want a list type object, convert it to  I want to extract a part of a two-dimensional list (=list of lists) in Python. I use Mathematica a lot, and there it is very convenient to write. matrix[[2;;4,10;;13]] which would extract the part of the matrix which is between the 2nd and 4th row as well as the 10th and 13th column. In Python, I just used

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  • So you replace the second part of the tuple with y_new? What happens with the "old" second item?
  • Yes... I am creating a new tuple, with the the old X, and a new Y.
  • Thanks Willem! Amazing!... :)