## Python appending random int in range to list, count number of occurences of numbers

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So I have the following code:

```import random
from collections import Counter
L = []
for x in range(0, 100):
L.append([])
for y in range(0, 6):
L[x].append(random.randint(0, 45) + 1)
```

Now I need to be able to count the number of times each number appears in the list. I tried counter and all kinds of other stuff, still get errors and I'm stuck. Any help would be appreciated.

The easiest way to do this is to make use of the dictionary `.get()` method to increment values if they have been seen before, or start with a default count of 0.

```my_count = {}
for lst in L:
for item in lst:
my_count[item] = my_count.get(item, 0) + 1
```

However, since you're already iterating in this way to create the list, you can do it all together:

```import random

my_count = {}
L = []
for x in range(0, 100):
L.append([])
for y in range(0, 6):
num = random.randint(0, 45) + 1
L[x].append(num)
my_count[num] = my_count.get(num, 0) + 1
```

Python, Python | Generate random numbers within a given range and store in a list generate a given count of random numbers within a given range, starting from '​start' To generate random numbers we have used the random function along with the use of the randint num = number of res.append(random.randint(start, end)). numbers = [1,1,2,4,5,3,2,1,6,3,1,6] sixes = [. number. for number in numbers. if number == 6. ] count_sixes = len (sixes) Notice I split up the list comprehension into multiple lines for clarity

You can store a per sublist `Counter` in a list and then sum all these counters.

I assume you want the count of each number across all sublists.

```from collections import Counter
from functools import reduce
import random

L = []
counters = []

for _ in range(0, 100):
sublist = []

for y in range(0, 6):
sublist.append(random.randint(0, 45) + 1)

counters.append(Counter(sublist))
L.append(sublist)

def counter_reducer(accumulator, next_item):
return accumulator + next_item

counts = reduce(counter_reducer, counters, Counter())
print(counts)  # Counter({23: 20, 46: 19, 12: 19, ...})
```

How To Count Occurrences in a Python List, Counting the number of times a value exists within a list is a common task, whether test script that created a list of 1,000,000 random integers from 1 to 100,000 — as well as a numbers = [randint(1,100000) for _ in range(0,​1000000)] count_time.append(time.time() - count_start) list_start = time.time() Python can generate such random numbers by using the random module. In the below examples we will first see how to generate a single random number and then extend it to generate a list of random numbers. Generating a Single Random Number. The random() method in random module generates a float number between 0 and 1. Example import random n = random.random() print(n) Output. Running the above code gives us the following result − 0.2112200 Generating Number in a Range

You can add a List contain the same elements as L and count them using count try this :

```L = []
e = []
for x in range(0, 10):
L.append([])
for y in range(0, 3):
a = random.randint(0, 45) + 1
L[x].append(a)
e.append(a)
for z in e :
print (z,e.count(z))
```

Let Us Python Solutions: Learn by Doing-the Python Learning Mantra, Learn by Doing-the Python Learning Mantra Yashavant Kanetkar, Aditya Kanetkar of occurrences of a number in the list import random lst = [] for k in range(20): n 50) lst.append(n) print(lst) num = int(input('Enter number:')) count = 0 for i in at position: 8 Number found at position: 13 (c) Suppose a list has 20 numbers. Generate random number within a given range in Python Random integer: 7 Random integer: 22 Random integer: 180 Note: You cannot use float value randrange() . It will raise a ValueError: non-integer arg 1 for randrange() if you used values other than an integer.

If i understand your question right - You can create another list with the length of all your possible numbers, now every time that number appended you are adding 1 to the his corresponding index , say:

```count_list =  * 47
L = []
for x in range(0, 100):
L.append([])
for y in range(0, 6):
L[x].append(random.randint(0, 45) + 1)
count_list[L[x][y]] += 1
```

now, every index in the coubt_list represent a number and inside him the number of appears

random — Generate pseudo-random numbers, This module implements pseudo-random number generators for various distributions. For integers, there is uniform selection from a range. You can instantiate your own instances of Random to get generators that don't share state. seen = sample(list(deck.elements()), k=20) >>> seen.count('tens') / 20 0.15  Python - Call function from another function Python | Generate random numbers within a given range and store in a list Given lower and upper limits, generate a given count of random numbers within a given range, starting from ‘start’ to ‘end’ and store them in list.

You could use the histogram function from numpy:

```import numpy as np
import random
from collections import Counter
L = []
ll, lu = 0, 45 # set bounds for random samples
for x in range(0, 2):
L.append([])
for y in range(0, 3):
L[x].append(random.randint(ll,lu) + 1)

bcen=np.linspace(ll, lu, lu+1) # centers
bed=np.linspace(ll-0.5, lu+0.5, lu+2) #edges
cnts, bed =np.histogram(L, bins=bed)

print('Random integers')
print(L)
print('Counts')
print(np.append(bcen.reshape(-1,1),cnts.reshape(-1,1), axis=1))
```