## Python appending random int in range to list, count number of occurences of numbers

So I have the following code:

import random from collections import Counter L = [] for x in range(0, 100): L.append([]) for y in range(0, 6): L[x].append(random.randint(0, 45) + 1)

Now I need to be able to count the number of times each number appears in the list. I tried counter and all kinds of other stuff, still get errors and I'm stuck. Any help would be appreciated.

The easiest way to do this is to make use of the dictionary `.get()`

method to increment values if they have been seen before, or start with a default count of 0.

my_count = {} for lst in L: for item in lst: my_count[item] = my_count.get(item, 0) + 1

However, since you're already iterating in this way to create the list, you can do it all together:

import random my_count = {} L = [] for x in range(0, 100): L.append([]) for y in range(0, 6): num = random.randint(0, 45) + 1 L[x].append(num) my_count[num] = my_count.get(num, 0) + 1

**Python,** Python | Generate random numbers within a given range and store in a list generate a given count of random numbers within a given range, starting from 'start' To generate random numbers we have used the random function along with the use of the randint num = number of res.append(random.randint(start, end)). numbers = [1,1,2,4,5,3,2,1,6,3,1,6] sixes = [. number. for number in numbers. if number == 6. ] count_sixes = len (sixes) Notice I split up the list comprehension into multiple lines for clarity

You can store a per sublist `Counter`

in a list and then sum all these counters.

I assume you want the count of each number across all sublists.

from collections import Counter from functools import reduce import random L = [] counters = [] for _ in range(0, 100): sublist = [] for y in range(0, 6): sublist.append(random.randint(0, 45) + 1) counters.append(Counter(sublist)) L.append(sublist) def counter_reducer(accumulator, next_item): return accumulator + next_item counts = reduce(counter_reducer, counters, Counter()) print(counts) # Counter({23: 20, 46: 19, 12: 19, ...})

**How To Count Occurrences in a Python List,** Counting the number of times a value exists within a list is a common task, whether test script that created a list of 1,000,000 random integers from 1 to 100,000 — as well as a numbers = [randint(1,100000) for _ in range(0,1000000)] count_time.append(time.time() - count_start) list_start = time.time() Python can generate such random numbers by using the random module. In the below examples we will first see how to generate a single random number and then extend it to generate a list of random numbers. Generating a Single Random Number. The random() method in random module generates a float number between 0 and 1. Example import random n = random.random() print(n) Output. Running the above code gives us the following result − 0.2112200 Generating Number in a Range

You can add a List contain the same elements as L and count them using count try this :

L = [] e = [] for x in range(0, 10): L.append([]) for y in range(0, 3): a = random.randint(0, 45) + 1 L[x].append(a) e.append(a) for z in e : print (z,e.count(z))

**Let Us Python Solutions: Learn by Doing-the Python Learning Mantra,** Learn by Doing-the Python Learning Mantra Yashavant Kanetkar, Aditya Kanetkar of occurrences of a number in the list import random lst = [] for k in range(20): n 50) lst.append(n) print(lst) num = int(input('Enter number:')) count = 0 for i in at position: 8 Number found at position: 13 (c) Suppose a list has 20 numbers. Generate random number within a given range in Python Random integer: 7 Random integer: 22 Random integer: 180 Note: You cannot use float value randrange() . It will raise a ValueError: non-integer arg 1 for randrange() if you used values other than an integer.

If i understand your question right - You can create another list with the length of all your possible numbers, now every time that number appended you are adding 1 to the his corresponding index , say:

count_list = [0] * 47 L = [] for x in range(0, 100): L.append([]) for y in range(0, 6): L[x].append(random.randint(0, 45) + 1) count_list[L[x][y]] += 1

now, every index in the coubt_list represent a number and inside him the number of appears

**random — Generate pseudo-random numbers,** This module implements pseudo-random number generators for various distributions. For integers, there is uniform selection from a range. You can instantiate your own instances of Random to get generators that don't share state. seen = sample(list(deck.elements()), k=20) >>> seen.count('tens') / 20 0.15 Python - Call function from another function Python | Generate random numbers within a given range and store in a list Given lower and upper limits, generate a given count of random numbers within a given range, starting from ‘start’ to ‘end’ and store them in list.

You could use the histogram function from numpy:

import numpy as np import random from collections import Counter L = [] ll, lu = 0, 45 # set bounds for random samples for x in range(0, 2): L.append([]) for y in range(0, 3): L[x].append(random.randint(ll,lu) + 1) bcen=np.linspace(ll, lu, lu+1) # centers bed=np.linspace(ll-0.5, lu+0.5, lu+2) #edges cnts, bed =np.histogram(L, bins=bed) print('Random integers') print(L) print('Counts') print(np.append(bcen.reshape(-1,1),cnts.reshape(-1,1), axis=1))

Note: I made your list smaller, just so that the print out is readable, but just adjust it as you wish.

**Lists in Python,** To print the contents of a list in the Python shell just type the list name. list2 = list(range(1, 101)) ## create a list of numbers from 1 to 100. >>> list2. [1, 2, 3, 4, 5, mylist.append (x) print (mylist) But this can be done in a much more compact way in Python, with a one liner. The function to use is sample () which shuffles the input list, in the example below it shuffles the created list range (1,101). That is to say, range (1,101) creates a list of numbers 1 to 100.

**Python List count(),** Python List count(). The count() method returns the number of occurrences of an element in a list. In simple terms, count() method counts how many times an Binarytree Module in Python Generating random number list in Python Sometimes, in making programs for gaming or gambling, we come across the task of creating the list all with random numbers. This task is to perform in general using loop and appending the random numbers one by one.

**Python repeat each element of a list,** Return the number of times the value 9 appears int the list: points = [1, 4, 2, 9, 7, 8, 9, over a situation in which we require to add the integer k to each element in the list. all elements of the Python range() function generates a list of numbers. The count () method returns the number of occurrences of an element in a list. I have just started using python and am trying to write a program that generates 200 random numbers in the range (1,50),then counts the number of occurrences of each number and prints the frequency of occurrence. I have created the part of the code which generates the random numbers. I need help in counting the frequency of these numbers.

**IPython Interactive Computing and Visualization Cookbook: Over 100 ,** Next, we realize that Python offers the option to easily concatenate several strings: >>> def concat2(): Finally, we want to count the number of occurrences of all numbers between 0 and 99 in a list containing 100,000 integers between 0 and 99: >>> l = [random.randint(0, 100) for _ in range(100000)] 9. The count () method returns the number of occurrences of an element in a list. In simple terms, count () method counts how many times an element has occurred in a list and returns it. The syntax of count () method is: The count () method takes a single argument: The count () method returns the number of occurrences of an element in a list.