Maximum number of toys task for HackerRank challenge?

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I'm trying to solve this problem: http://www.hackerrank.com/challenges/mark-and-toys

Mark and Jane are very happy after having their first child. Their son loves toys, so Mark wants to buy some. There are a number of different toys lying in front of him, tagged with their prices. Mark has only a certain amount to spend, and he wants to maximize the number of toys he buys with this money.

Given a list of prices and an amount to spend, what is the maximum number of toys Mark can buy? For example, if and Mark has to spend, he can buy items for , or for units of currency. He would choose the first group of items.

My solution normally works but apparently is incorrect when a very large set of numbers are thrown at it.

// Complete the maximumToys function below.
function maximumToys(prices, k) {
    const pricesSorted = prices.sort();
    // console.log('pricesSorted ', pricesSorted);

    let budget = k;
    let noToys = 0;

    pricesSorted.forEach(toyPrice=>{
        if (toyPrice <= budget) {
            noToys++;
            budget = budget - toyPrice;
        }
    });

    // console.log('noToys ', noToys);
    return noToys;
}

If you don't pass comparable function to sort(), it assumes the values as strings and sorts them according to Unicode code points. Source: - Sort

So, pass a comaparable function and JS will sort objects depending upon return value of this function. Rest of your code is correct.

const pricesSorted = prices.sort(function(a,b){return a-b;});

UPDATE:

Since the sort() sorts in-place, pricesSorted is redundant.

Mark and Toys, It should return an integer representing the maximum number of toys Mark can purchase. maximumToys has the following parameter(s):. prices: an array of  There are a number of different toys lying in front of him, tagged with their prices. Mark has only a certain amount to spend, and he wants to maximize the number of toys he buys with this money. Given a list of prices and an amount to spend, what is the maximum number of toys Mark can buy?

Sort the toys according to price and keep taking toys as long as you have money left.

// Complete the maximumToys function below.
function maximumToys(prices, k) {
    var bought = 0
    var pricings = prices.sort((a, b) => a - b)
    var amtLeft = k;
    for (var i = 0; i < pricings.length; i++){
        if (amtLeft < pricings[i]) {
            break;
        } else {
            amtLeft = amtLeft - pricings[i];
            bought++;
        }
    }
    return bought
}

Maximise the number of toys that can be purchased with amount K , Write a program to find the maximum number of toys one can buy with the The idea to solve this problem is to first sort the cost array in ascending order. Challenges: The challenge_id is the id of the challenge, and hacker_id is the id of the student who created the challenge. Hackers Table: Challenges Table: Sample Output 0. 21283 Angela 6 88255 Patrick 5 96196 Lisa 1. Hackers Table: Challenges Table: Sample Output 1. 12299 Rose 6 34856 Angela 6 79345 Frank 4 80491 Patrick 3 81041 Lisa 1.

#include <bits/stdc++.h>

using namespace std;

vector<string> split_string(string);

// Complete the maximumToys function below.
int maximumToys(vector<int> prices, int k) {


}

int main()
{
    ofstream fout(getenv("OUTPUT_PATH"));

    string nk_temp;
    getline(cin, nk_temp);

    vector<string> nk = split_string(nk_temp);

    int n = stoi(nk[0]);

    int k = stoi(nk[1]);

    string prices_temp_temp;
    getline(cin, prices_temp_temp);

    vector<string> prices_temp = split_string(prices_temp_temp);

    vector<int> prices(n);

    for (int i = 0; i < n; i++) {
        int prices_item = stoi(prices_temp[i]);

        prices[i] = prices_item;
    }

    int result = maximumToys(prices, k);

    fout << result << "\n";

    fout.close();

    return 0;
}

vector<string> split_string(string input_string) {
    string::iterator new_end = unique(input_string.begin(), input_string.end(), [] (const char &x, const char &y) {
        return x == y and x == ' ';
    });

    input_string.erase(new_end, input_string.end());

    while (input_string[input_string.length() - 1] == ' ') {
        input_string.pop_back();
    }

    vector<string> splits;
    char delimiter = ' ';

    size_t i = 0;
    size_t pos = input_string.find(delimiter);

    while (pos != string::npos) {
        splits.push_back(input_string.substr(i, pos - i));

        i = pos + 1;
        pos = input_string.find(delimiter, i);
    }

    splits.push_back(input_string.substr(i, min(pos, input_string.length()) - i + 1));

    return splits;
}

Chocolate Distribution Problem, There are m students, the task is to distribute chocolate packets such that: The difference between the number of chocolates in packet with maximum  Output Format An integer that denotes maximum number of toys Mark can buy for his son. Constraints 1<=N<=105 1<=K<=109 1<=price of any toy<=109 A toy can't be bought multiple times. Sample Input 7 50 1 12 5 111 200 1000 10 Sample Output 4 Explanation He can buy only 4 toys at most.

Intelligent Hybrid Systems: Fuzzy Logic, Neural Networks, and , Figure 17 illustrates the knapsack problem and its GA coding. value is the highest under the condition that the total amount of goods is less than that of the knapsack. Although the knapsack problem itself is a toy task, there are several similar  After each bubble sort pass, make Mark buy the cheapest toy you found in it and deduct it from his budget. If you reach a point where he can't afford the cheapest toy in a pass, then he won't be able to afford any of the remaining and already have the maximum number of toys he could have bought, so you can abort your sorting there to save some

Family Observational Coding Systems: Resources for Systemic Research, For family problem-solving tasks (12 or 15 minutes; two parents and one or two issues that family members agree generate the greatest conflict in their family. away in appropriate containers a number of small toys or objects (e.g., blocks,  Find the maximum number of consecutive 1's in the base-2 representation of a base-10 number.

Touch Screen Tablets Touching Children's Lives, instructions included a description and illustration of the task set-up, goals, and Coding. –. Task. Variables. Transfer Success A primary coder scored from the button) on the test object (2D/3D condition) or test image (3D/2D condition). transfer on the task received a latency time of 5 min, the maximum amount of time​  The first task alone can be completed in 2 minutes, and so you won't overshoot the deadline. With the first two tasks, the optimal schedule can be: time 1: task 2 time 2: task 1 time 3: task 1. We've overshot task 1 by 1 minute, hence returning 1. With the first three tasks, the optimal schedule can be: time 1 : task 2 time 2 : task 1 time 3 : task 3

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