Creating list of five elements from a List of Number in Python
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i'm using Python 3.7.
I have a tuple of Numbers like this:
x = ((1,2,3,4,5,6,7,8,9....etc))
I would Like to obtain a list of list divided by 100 and with Five numbers from the list in an iterative way... something like this:
[[[0.0], [0.01], [0.02], [0.03], [0.04]], [[0.01], [0.02], [0.03], [0.04], [0.05]], [[0.02], [0.03], [0.04], [0.05], [0.06]], [[0.03], [0.04], [0.05], [0.06], [0.07]], [[0.04], [0.05], [0.06], [0.07], [0.08]], [[0.05], [0.06], [0.07], [0.08], [0.09]],... etc
I Tried this but it doesn't work properly:
Data = [[[(interest_over_time_data+j)/100] for interest_over_time_data in range(5)]for j in interest_over_time_data]
The real numbers are not a list of consecutive number so I cannot add +1 to each element...
Thank you in advance!
Python lists - working with lists in Python, It creates a list containing five elements. $ ./simple.py It contains numbers, a boolean value, another list, a string, a tuple, a custom object, and a dictionary. $ . A list of random numbers can be then created using python list comprehension approach: >>> l = [random.randint (0,10) for i in range (5)] >>> l [4, 9, 8, 4, 5] Another solution is to use randrange function (except that can specify a step if you need):
You can use 3rd party NumPy for an array-based solution:
import numpy as np first_row = np.arange(5) / 100 first_col = np.arange(10) / 100 res = first_row + first_col[:, None] array([[ 0. , 0.01, 0.02, 0.03, 0.04], [ 0.01, 0.02, 0.03, 0.04, 0.05], [ 0.02, 0.03, 0.04, 0.05, 0.06], [ 0.03, 0.04, 0.05, 0.06, 0.07], [ 0.04, 0.05, 0.06, 0.07, 0.08], [ 0.05, 0.06, 0.07, 0.08, 0.09], [ 0.06, 0.07, 0.08, 0.09, 0.1 ], [ 0.07, 0.08, 0.09, 0.1 , 0.11], [ 0.08, 0.09, 0.1 , 0.11, 0.12], [ 0.09, 0.1 , 0.11, 0.12, 0.13]])
11. Lists, The values that make up a list are called its elements, or its items. There are several ways to create a new list; the simplest is to enclose the elements in square brackets numbers[9-8] 5 >>> numbers[1.0] Traceback (most recent call last): File That's why Python is free to alias strings (and any other immutable kinds of In Python programming, a list is created by placing all the items (elements) inside square brackets , separated by commas. It can have any number of items and they may be of different types (integer, float, string etc.). A list can also have another list as an item. This is called a nested list.
Love one line solutions:
[[[x[p]/100] for p in range(k,k+5)] for k in range(len(x)-4)] #>[[[0.01], [0.02], [0.03], [0.04], [0.05]], #> [[0.02], [0.03], [0.04], [0.05], [0.06]], #> [[0.03], [0.04], [0.05], [0.06], [0.07]], #> [[0.04], [0.05], [0.06], [0.07], [0.08]], #> [[0.05], [0.06], [0.07], [0.08], [0.09]]]
Okay, you want your output containing lists with a length of 5 shifting from the first element of
x to the last. Therefore your output will contain
n-4 lists, where
So first we need to iterate over
Then we want five elements from
x starting at a given offset
i. We can use slicing for this, e.g.
And we want all elements of this sublist divided by
All together packed in list comprehension it looks like this:
x = (1,2,3,4,5,6,7,8,9) res = [ [j/100.0 for j in x[i:i+5]] for i in range(len(x)-4) ] print(res)
Which results in
[[0.01, 0.02, 0.03, 0.04, 0.05], [0.02, 0.03, 0.04, 0.05, 0.06], [0.03, 0.04, 0.05, 0.06, 0.07], [0.04, 0.05, 0.06, 0.07, 0.08], [0.05, 0.06, 0.07, 0.08, 0.09]]
Or if you want to have
0.0 as in your example output:
x = (1,2,3,4,5,6,7,8,9) x =  + list(x) res = [ [j/100.0 for j in x[i:i+5]] for i in range(len(x)-4) ] print(res)
Python, While working with the Python lists, we can come over a situation in which we The original list is : [4, 5, 6, 3, 9] The list after adding K to each element : [8, 9, 10, • We create a list by using the square brackets. •alist = [1, 3.5, “hello”] • A list with three elements of three diﬀerent types •blist = [1, 3.5, “hello”, 1] • A list with four elements, where one element is repeated •clist = [1, “hello”, 3.5] • A diﬀerent list than alist, but with the same elements • The order
List in Python : lists, range, slice, append, len, etc in Python, For example, in the list [3,4,2,5] , index will start from 0. So, index of 3 is 0, list in python. So, to access any element of a list, we write name_of_list[index]. [1, 3, 5, 7, 9]. range(1,10,2) will create a sequence of numbers but with a step of 2. Python module itertools has a function called repeat, which can be used to get a list repeating single element n times. If we want to create a list repeating number 5, ten times we can use itertools.repeat function as follows. import itertools. itertools.repeat (5, 10) itertools.repeat function yields an iterator not a list. So to get a list we
Lists, The values in list are called elements or sometimes items. There are The one-eth element of numbers, which used to be 123, is now 5. You can In this example, Python only created one string object, and both a and b refer to it. But when Here, a = 5 will simply make the element at the 1 st index of 'a' 5. Lists are mutable → It means that we can change the value of any member of the list as we have done above (a = 5). It is not necessary in Python for the list to contain only the same type of elements. We can also have a list as shown in the example given below: Python
Python: Generate and print a list of first and last 5 elements where , Write a Python program to generate and print a list of first and last 5 elements where the values are square of numbers between 1 and 30 (both In Python the items or elements of the list can be accessed by using the index operator that is . The index operator directly refers to the element. The index of a list is started from 0 and when we have to access the 4 th item of the list then we will write 3 as the index value. A list of 4 items or elements will have the items from 0 to 3.