Unable to understand last condition of FizzBuzz in following code

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I can understand how this code produces Fizz , Buzz when divisible by 3 , 5. But confused about how it produces FizzBuzz when divisible by both 3 and 5, because i do not see any if condition which satisfies divisible by both 3 and 5. Please explain.

for (let n = 1; n <= 100; n++) {
  let output = "";
  if (n % 3 == 0) output += "Fizz";
  if (n % 5 == 0) output += "Buzz";
  console.log(output || n);
}

Both if statement conditions evaluate to true, so it adds both "Fizz" and "Buzz" to "", which results in "FizzBuzz". The += operator is appending text to output.

Fizz Buzz Test, We can't understand why so many people "fail" the Fizz-Buzz test unless we is icky, and there are two tests for the same condition -- (theNumber is divisible by 5​). Why newbie programmers still have this urge to write clever code instead of Note: Remove the hash "#" to uncomment the last "# $return" and have only the​  There's nothing wrong with hardcoding some conditions. In the context of an interview, when I know that I'm coding FizzBuzz.java and not Enterprise Fizz Buzz with a database and 1000+ simultaneous users requiring five-nines uptime, it's ideal to hardcode these conditions. Entry-level programmers, the ones you ask FizzBuzz at least,


The use of output += ...; allows for the variable to be populated with FizzBuzz if/when the iteration is divisible by both 3 AND 5.

Tackling the FizzBuzz test, Solve this infamously difficult programming interview question with for-loops and I'm not convinced that it's the litmus test, or that programmers who fail it are In any case, if you know how to write a for-loop and an if/elif/else-statement, then this I recommend creating a file named fizzbuzz.py , writing the code in that file,​  It is always a good idea in a coding interview to do a quick run of the expected result without actually writing any code. Here, you will discuss that the expected output should be one, two, fizz instead of three, four, buzz instead of five, and so on. With this understanding out of the way, we can start writing some code.


I'm not sure i understand your issue

You don't understand why you get FizzBuzz sometimes ?

For example when n=15 you get it.

Because 15 % 3 = 0 ( 15 = 3*5 ) and 15 % 5 = 0 (15 = 5*3 )

It is the same for 30, 45, 60, 75, 90.

Homework 1, The FizzBuzz test is a common programming interview question used to establish if a team member to understand how and why all code in the assignment works​. The final product for this assignment should be a single Rmd document (a template This document must be reproducible and I must be able to compile it with  switch on the result of n mod 15 0=Fizzbuzz, [3,6,9,12]=fizz, [5,10]=buzz string array lookup (based again on n mod 15) Also, the 3 x 5 could stand some improvement; not because it should be 15 (because that is wrong too) but because they are 'magic numbers'. Neither 3 nor 5 should appear in the body


Unable to comprehend reasoning behind not getting this correct , Unable to comprehend reasoning behind not getting this correct. For numbers divisible by both 3 and 5, print out "FizzBuzz" in the console. Otherwise, just  I find the statement that 99% of the programmers are unable to program or to solve a simple coding test highly exaggerated. In the case of the FizzBuzz test, either you have encountered this problem before and can easily solve it with the modulo operator or you have not encountered it before and will struggle with it.


Fizz buzz, So, we need to put something with multiple conditions ahead of ones with more simple conditions. (Please let me know if this is wrong. I've just started myself). Fizz or Buzz, but not Fizz-Buzz: More challenging variation has the direction of play change on Fizz or Buzz, but not on Fizz-Buzz. For certain sequences, this makes the action bounce between 2 or 3 players and causes misplays when it breaks out. The 3/7 version of the game has a complex sequence between 12 and 18,


Learn Raspberry Pi 2 with Linux and Windows 10, We can do this test in another else statement off the divisible by 3 test. 0 ]; then if [ $(($number % 5)) -eq 0 ]; then echo "FizzBuzz" else echo "Fizz" fi else if This is how we will be able to increase the value of number by 1 over and Both are testing that some condition is true and both will then execute a section of code. Now FizzBuzz itself isn't a big challenge but I agree that it can be a good tool to see if someone can code or not. I wanted to practice my LINQ a little bit so here's my single line FizzBuzz solu