MIPS to C Translation

c to mips array
translate the following c code to mips assembly code
c to mips for loop
c to mips spim
mips compiler online
convert c code to assembly language online
c to mips convertor
mips code examples

I need to translate some MIPS assembly instructions to C code. I think I got it, but it seems counter-intuitive. Any help? We have variables f, g, h, i, j stored in registers $s0, $s1, $s2, $s3 and $s4 respectively. The base of arrays A and B are stored in $s6 and $s7 respectively. 4 byte words. Comments in the code are my own.

addi $t0, $s6, 4   # $t0 = A[1]
add $t1, $s6, $0   # $t1 = A[0]
sw $t1, 0($t0)     # $t0 = A[0]
lw $t0, 0($t0)     # $t0 = A[0]
add $s0, $t1, $t0  # f = A[0] + A[0]

I just feel like I'm wrong. Why make $t0 A[1] first if we never use it?

sw $t1, 0($t0)     # $t0 = A[0]

You've got this back-to-front. It is a store, so it is used:

sw $t1, 0($t0)     # A[1] = $t1

[PDF] Translating C code to MIPS, Translating C code to MIPS why do it. C is relatively simple, close to the machine. C can act as pseudocode for assembler program gives some insight into what  I need to translate some MIPS assembly instructions to C code. I think I got it, but it seems counter-intuitive. MIPS to C Translation. Ask Question Asked 6 years

I think you have got in completely wrong.

addi $t0, $s6, 4 # $t0 = A[1]

After the addi, register $t0 became the memory address of A[1], which would be &A[1], not A[1]. To get value of A[1], you need to use lw after you done the addi

lw $t0, 0($t0) # $t0 =A[1]

Example Converting MIPS Assembly to C, create hard-wired registers (like $zero) for small constants? ◇ . . . ??? ▫. MIPS Instructions: addi $29 $29 4 addi $29, $29, 4. I am trying to translate the C code below to MIPS assembly language, I kind of understand most of it however, I am lost as to what the equivalent of the first line is in assembly int ary[3] = {2,3,4}; I'd appreciate it if someone can take a look at my C to assembly 'translation' and verify I am on the right track. C Code

Just a little addition to the previous answers: The store word means that you cannot access $t1 anymore because it is copied to memory. At least you should not use the $t1 from the store word instruction. You should use the one before (add $t1, $s6, $0). This means that the answer is f ( which is in $s0) = &A[0] (base address in register $t1) + A[1] (value of the array with word index 1, which is in register $t0)

[PDF] Translate C into MIPS assembly, This program will use the g++ compiler to turn provided C code into MIPS assembly language. Note that the assembly code produced is suitable for use on a  Answer to Simple MIPS to C translation Translate the following MIPS code into C Part #1 : Iw Iw $t0, 120(Ss6) $t1, 40(Ss7) lw. add

Mnush's answer is incorrect.

The last line is adding $t1 and $t0.

$t1 = A[0] and

$t0 = A[1].

With proper comments:

addi $t0, $s6, 4   # $t0 = &A[1]
add $t1, $s6, $0   # $t1 = &A[0]
sw $t1, 0($t0)     # A[0] = A[1]
lw $t0, 0($t0)     # $t0 = A[0]
add $s0, $t1, $t0  # f = A[0] + A[1]

The C Code:

A[1] = A[0];
f = A[0] + A[1];

C to MIPS compiler, And in C, is &A == &A[0]?. In my book there is a practice problem telling us to translate the following assembly code into C: Recap of MIPS instruction set and formats MIPS addressing modes Rit ll tiRegister allocation graph coloring sppgilling Translating C statements into Assembler if statement hl MIPS_3000 while statement switch statement procedure / function (leaf and non-leaf) @HC Computation 5JJ70 pg 3 p( stack save and restore mechanism

Guess this is correct.

A[1] = A[0] 
f= A[1] + A[1]

[MIPS, homework] Translating MIPS to C, is my solution correct? And , Translate the C code into assembly: for(i = 0; i < 100; i++). { sum+=A[i];. } Assume int is 32 bits. $s0 = &A[0]. $v0 = sum;. $t0 = i; and $t0, $t0, $zero #let i = 0. [MIPS, homework] Translating MIPS to C, is my solution correct? And in C, is &A == &A[0]? In my book there is a practice problem telling us to translate the following assembly code into C:

[PDF] Instruction Set Architectures Part I: From C to MIPS, Seems like your h, i and j aren't used at all. Here is your code including my comments: sll $t0, $s0, 2 # $t0 = f * 4 add $t0, $s6, $t0 # $t0 = &A[f]  Writing directly in MIPS assembler is difficult (impossible?) Strategy for producing likely correct MIPS code develop the solution in C map to "simplified" C translate each simplified C statement to MIPS instructions Simplified C does not have while, switch, complex expressions does have simple if, goto, one-operator expressions

Convert MIPS assembly code to C?, (Depending on the C compiler), the memory layout looks like this. A Simple Expression. C code: i = N*N + 3*N "Unoptimized": (Note: There  C to MIPS compiler tool by Tyler Bletsch is licensed under a Creative Commons Attribution-NonCommercial 4.0 International License. This tool was created by starting with an Ubuntu 14.04 server with Apache+PHP and installing the MIPS cross compiler per these directions .

MIPS Assembly Language Examples, MIPS is a machine architecture, including instruction set. SPIM is Also provides extra instructions, mapped to MIPS core set Example translating C to MIPS:. CS61C Homework 3 - C to MIPS Practice Problems TA: Sagar Karandikar Spring 2015 This homework is an ungraded assignment designed to familiarize you with translating C code to MIPS. We will release solutions on Sunday, Feb 22nd, so that you may use them to study for the exam. Problem 1 - Useful Snippets

Comments
  • I don't think so. My revision changes the meaning of the fourth line. What do you get when taking that into account?