Split string, convert ToList<int>() in one line

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I have a string that has numbers

string sNumbers = "1,2,3,4,5";

I can split it then convert it to List<int>

sNumbers.Split( new[] { ',' } ).ToList<int>();

How can I convert string array to integer list? So that I'll be able to convert string[] to IEnumerable

var numbers = sNumbers.Split(',').Select(Int32.Parse).ToList();

Split string, convert ToList<int>() in one line, Let's now turn our string of numbers to a list of integers. We'll use the split method to convert our numbers string into an array of strings. Then, we'  If we want to convert string to list operation, then we need to use the Python string split() method. Python split() method is used to split the strings and store them in the list. The split()  method returns a list of the words in the string, using the “delimiter” as the delimiter string.

You can also do it this way without the need of Linq:

List<int> numbers = new List<int>( Array.ConvertAll(sNumbers.Split(','), int.Parse) );

// Uses Linq
var numbers = Array.ConvertAll(sNumbers.Split(','), int.Parse).ToList();

Convert comma-separated String to List in Java, Learn how to split a comma-separated String into a list of Strings and We'll also look at how to convert a string array to map using Stream API. If we want to split a string to list based on whitespaces, then we don’t need to provide any separator to the split() function. Also, any leading and trailing whitespaces are trimmed before the string is split into a list of words. So the output will remain same for string s = ' Welcome To JournalDev ' too.

Joze's way also need LINQ, ToList() is in System.Linq namespace.

You can convert Array to List without Linq by passing the array to List constructor:

List<int> numbers = new List<int>( Array.ConvertAll(sNumbers.Split(','), int.Parse) );

Convert a Comma Separated String to a List, The steps for conversion are as follows: 1) First split the string using String split() This method returns a list created based on the elements of the specified array​  The built-in method returns a list of the words in the string, using the “delimiter” as the delimiter string. If a delimiter is not specified or is None, a different splitting algorithm is applied: runs of consecutive whitespace are regarded as a single separator, and the result will contain no empty strings at the start or end if the string has leading or trailing whitespace.

Better use int.TryParse to avoid exceptions;

var numbers = sNumbers
            .Split(',')
            .Where(x => int.TryParse(x, out _))
            .Select(int.Parse)
            .ToList();

String Operations with Java and Stream API, Split method creates an array of substrings by splitting the input string based on one or more delimiters. It is often the easiest way to separate a  If you want to split any string into a list (of substrings) you can use simply the method split(). It can be used: without parameter - then space is used as separator with parameter - comma, dot etc - see next section

It is also possible to int array to direct assign value.

like this

int[] numbers = sNumbers.Split(',').Select(Int32.Parse).ToArray();

Java - String to ArrayList conversion, split() function that returns a List of String, then map() each item with CharSequence.trim() function to remove [space] character. val input: String =  The above code splits the string on a delimiter defined as: zero or more whitespace, a literal comma, zero or more whitespace which will place the words into the list and collapse any whitespace between the words and commas. Please note that this returns simply a wrapper on an array: you CANNOT

How to parse strings using String.Split (C# Guide), This article shows how to create an ArrayList by splitting a String. Here are a few ways to split (or convert, or parse) a string of comma separated values: input = "aaa,bbb,ccc"; // To array String[] arr = input.split(","); // To fixed-size list  The split () method splits a string into a list. You can specify the separator, default separator is any whitespace. Note: When maxsplit is specified, the list will contain the specified number of elements plus one. string .split ( separator, maxsplit ) Parameter Values. Optional. Specifies the separator to use when splitting the string. By

Kotlin – Convert comma-separated String to List & List to String , Learn to split string by comma or space and store in array or arraylist with example. Use given Java program to convert string to List in Java. A table-valued function that splits a string into rows of substrings, based on a specified separator character. Compatibility level 130. STRING_SPLIT requires the compatibility level to be at least 130. When the level is less than 130, SQL Server is unable to find the STRING_SPLIT function. To change the compatibility level of a database, refer

Java: How to split a String into an ArrayList, 4 Answers 4. string s = new List<string>(s.Split(.)); You want to be careful here to use StringSplitOptions.RemoveEmptyEntries or you may end up with a list with a single empty string instead of a list with no elements when the string is the empty string.

Comments
  • We had exactly the same question today: Click me
  • in "one line" si a very strong is a very strict requirement! </perl>
  • This question specifically says to split a string of numbers, which keeps the answer simple. The question Dario mentioned handles (bogs down in?) issues of TryParse for general strings.
  • This get Exception when the List has empty value or null.
  • Thanks, although you declare a separator and then you don't use it.
  • Welcome to Stack Overflow! While this code snippet may solve the question, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. Please also try not to crowd your code with explanatory comments, as this reduces the readability of both the code and the explanations!
  • The function ConvertIntoIntList doesn't exits.
  • Also, you need to add the following class: static public class HelperMethods { static public List<int> ConvertIntoIntList(this string[] stringList) { int x = 0; var intList = stringList.Where(str => int.TryParse(str, out x)) .Select(str => x) .ToList(); return intList; } }