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I have a list of integers and I am trying to define a function which loops through every element to check if they are less than 5 and returns the list in string according to their contents.

intlist=[12, 10, 11, 23, 25, 2]

def clear(x):
for i in x:
if i < 5:
x[i] = 0
return str(x)
else:
return str(x)

print clear(intlist)

My code is not working as intended, could anyone enlighten me?

If they are, I am to change all elements in the list to '0'. The outcome should look something like this.

intlist=[0, 0, 0, 0, 0, 0]

However if none of the elements are less than 5, the output should remain the same.

intlist=[12, 10, 11, 23, 25, 2]

Welcome to StackOverflow! Your code has some logic problem. Here's my fix:

intlist=[12, 10, 11, 23, 25, 2]

def clear(x):
for i in x:
if i < 5:          # If this is satisfied once, return string with n times of '0'
x = [0]*len(x) # This creates a list of zeros with same length as before
return str(x)
return str(x)

print clear(intlist)

Besides, in your example the element 2 is less than 5, so the output should be 000000

Logic-Based Program Synthesis and Transformation: 26th , P ending on An is equal to that of e1 and the value of xa in which the value of ia is at the start of the program (this facilitates an arbitrary choice of array element a[ia]). array writes other than a[ia ] are replaced by the witness variable xa ] are either unconditionally or non-deterministically; based on loop characteristics. The outer loop will one by one pick array elements from left to right. The inner loop will find the greatest element present after the picked element. Finally the outer loop will replace the picked element with the greatest element found by inner loop. The time complexity of this method will be O(n*n).

intlist=[12, 10, 11, 23, 25, 2]

def clear(x):
if (any(i<5 for i in intlist)): return [0]*len(intlist)
else: return(x)
print(clear(intlist)) # [0, 0, 0, 0, 0, 0]

check for the any item is <5 then return all zeros or keep the list as it is.

A Knowledge-Based Approach to Program Understanding, They do not affect the ability to assist the understanding of nested loops. directly replaces var?, if any, with its value as deduced from the outer loop invariant. for an array element aft[vario] which does not satisfy the loop condition condit. Python program that uses for-loop on strings s = "abc" # Loop over string. for c in s: print (c) # Loop over string indexes. for i in range (0, len (s)): print (s [i]) Output a Loop 1 b c a Loop 2 b c. A for-loop acts upon a collection of elements, not a min and max. In for, we declare a new variable. And after the in-keyword, we specify the

There are a couple of mistakes in the for loop that you have written. First, the return statement is inside the loop, which makes it exit just after the if statement or else statement, whichever it goes to first. Secondly, you are making a mistake with how you are indexing. If you wish to access elements through index, you range in your loop instead. Here is the correct implementation for the function that you want :

def clear(x):

for i in range(len(x)):
if x[i]<5:
x[i]=0

return str(x)

19 years GATE Computer Science & Information Technology , 'k' loop is used to compute sum of elements of the particular subarray. for (3), when i = O, value of A which old C[2] i.e. 'a' and replace with new C[2] i.e. also 'a' These would be filled dynamically depending upon previous rows &columns. Java provides a way to use the “for” loop that will iterate through each element of the array. Here is the code for the array that we had declared earlier- for (String strTemp : arrData) { System.out.println (strTemp); } You can see the difference between the loops. The code has reduced significantly. Also, there is no use of the index or

You can do it one one-line, creating a list of zeros if any one of the elements in list is less than 5 or retaining the list otherwise.

intlist = [12, 10, 11, 23, 25, 2]

intlist = [0] * len(intlist) if any(x < 5 for x in intlist) else intlist

print(intlist)
# [0, 0, 0, 0, 0, 0]

Shared-Memory Parallelism Can be Simple, Fast, and Scalable, in case the desired replacement element was shifted down in the meantime by another thread. It is important that this loop runs backward and is the reason that there are Combining For a deterministic hash table that stores key-value pairs, if there Here we outline an approach for growing a table based on incrementally  3. Replace element in arraylist while iterating. Do not use iterator if you plan to modify the arraylist during iteration. Use standard for loop, and keep track of index position to check the current element. Then use this index to set the new element. Java program to search and replace an element in an ArrayList.

11. Lists, The values that make up a list are called its elements, or its items. It is common to use a loop variable as a list index. Python has a built-in type conversion function called list that tries to turn whatever you give it into a list. Write a function replace(s, old, new) that replaces all occurrences of old with new in a string s:  Zero-based indexing means that the index value of a list always starts with 0 True List traversal is the process of accessing, one-by-one, each element in a list.

How to conditionally replace items in a list, I wanted to replace items in a list based on a specific condition. For example, given a list of numbers, I want to replace all items that are  elements larger than 0.5 be replaced by -1, else. keep the way it is. So I thought I should simply write the command below: X=rand (10,10); if X (:,:)>0.5; else T=X (:,:); but it does not work because T==X. Could someone tell me how to correct these command lines? Show Hide all comments. Sign in to comment. Sign in to answer this question.

How To Replace Your Python For Loops with Map, Filter, and Reduce, Reduce : Return a value that is passed from element to element. What Makes Python Map/Filter/Reduce Different? In Python, the three  The full range may replace all the matching elements of the list. It may replace more than the one element of the list. To change the element within a certain range. You have to limit the range and perform the loop to the list elements. Check each example given below to learn the method.

##### Comments
• What's the error message? As I can see in your code your indentations are not valid for if-else block.
• What does string have anything to do with it?
• i can't understand your question clearly,did you want to change the list element which less than 5 to 0?
• thank you! this works but I would like to ask if an else statement is possible here?
• @SamuelTan yeah it is possible but not necessary.
• A break is however necessary. This only works because 2 is the last element.
• @MadPhysicist It's true, I just realized I am missing a return statement as I said in the comment, fixed.
• Break is better if you want to avoid repeating code.
• Why filter the whole iterable when you can just do any(x < 5 for x in intimate)?
• @MadPhysicist, Yeah, that would be better. :) Thank you.