Check if file is symlink in python
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In python, is there a function to check if a given file/directory is a symlink ? For example, for the below files, my wrapper function should return
# ls -l total 0 lrwxrwxrwx 1 root root 8 2012-06-16 18:58 dir -> ../temp/ lrwxrwxrwx 1 root root 6 2012-06-16 18:55 link -> ../log
To determine if a directory entry is a symlink use this:
Return True if path refers to a directory entry that is a symbolic link. Always False if symbolic links are not supported.
For instance, given:
drwxr-xr-x 2 root root 4096 2011-11-10 08:14 bin/ drwxrwxrwx 1 root root 57 2011-07-10 05:11 initrd.img -> boot/initrd.img-2.. >>> import os.path >>> os.path.islink('initrd.img') True >>> os.path.islink('bin') False
How can I determine if a given directory is `symlink`ed to in Python , Creating a symlink does not change the inode of the destination file/folder (as opposed to hard links), so you can't tell by looking at the target, With os.path.exists(path) we can make sure that given path exists or not but we can not make sure if it’s a file or directory or link. Python – Check if a file exists Python’s os module provides a function to check if a given file exists or not i.e.
For python 3.4 and up, you can use the Path class
from pathlib import Path # rpd is a symbolic link >>> Path('rdp').is_symlink() True >>> Path('README').is_symlink() False
You have to be careful when using the is_symlink() method. It will return True even the target of the link is non-existent as long as the the named object is a symlink. For example (Linux/Unix):
ln -s ../nonexistentfile flnk
Then, in your current directory fire up python
>>> from pathlib import Path >>> Path('flnk').is_symlink() True >>> Path('flnk').exists() False
The programmer has to decide what he/she realy wants. Python 3 seems to have renamed a lots of classes. It might be worthwhile to read the manual page for the Path class: https://docs.python.org/3/library/pathlib.html
How to check if a file or directory or link exists in Python , In case path is of a symbolic link and link is broken i.e, file it points too Python's os module provides a function to check if a given file exists or Check if either file or directory exists os.path.exists() method in Python is used to check whether the specified path exists or not. This method can be also used to check whether the given path refers to an open file descriptor or not.
Without the intention to bloat this topic, but I was redirected to this page as I was looking for symlink's to find them and convert them to real files and found this script within the python tools library.
#Source https://github.com/python/cpython/blob/master/Tools/scripts/mkreal.py import sys import os from stat import * BUFSIZE = 32*1024 def mkrealfile(name): st = os.stat(name) # Get the mode mode = S_IMODE(st[ST_MODE]) linkto = os.readlink(name) # Make sure again it's a symlink f_in = open(name, 'r') # This ensures it's a file os.unlink(name) f_out = open(name, 'w') while 1: buf = f_in.read(BUFSIZE) if not buf: break f_out.write(buf) del f_out # Flush data to disk before changing mode os.chmod(name, mode) mkrealfile("/Users/test/mysymlink")
How do I check if a file is a symbolic link to a directory?, Just combine the two tests with && : if [[ -L "$file" && -d "$file" ]] then echo "$file is a symlink to a directory" fi. readlink may also set errno == ENOTDIR if the symlink missuses a file as a dir. – Johan Boulé Jul 20 '10 at 23:41. os.readlink(path) might not get the actual path if the link 'path' is given a relative path to its target.
Check if file is symlink in python, In python, is there a function to check if a given file/directory is a symlink ? For example, for the below files, my wrapper function should return True . # ls -l total 0 To determine if a directory entry is a symlink use this: os.path.islink(path) Return True if path refers to a directory entry that is a symbolic link. Always False if symbolic links are not supported.
Python os.readlink() Method, Python os.readlink() Method - Python method readlink() returns a string representing the path to which the symbolic link points. Python - Date & Time · Python - Functions · Python - Modules · Python - Files I/O · Python - Exceptions path − This is the path or symblic link for which we are going to find source of the link. It will return True even the target of the link is non-existent as long as the the named object is a symlink. For example (Linux/Unix): ln -s ../nonexistentfile flnk Then, in your current directory fire up python >>> from pathlib import Path >>> Path('flnk').is_symlink() True >>> Path('flnk').exists() False
Python Language, python documentation: check if the given path is a directory, file, symbolic link, mount point etc. symlink = dirname + 'some_sym_link' os.path.islink(symlink). check if file is a symlink. Here is a small piece of code: import os. from stat import *. filePath = "/home/xyz/symLinkTest". mode = os.stat(filePath)[ST_MODE] print 'Find using os.path : ',os.path.islink(filePath) print 'Find using mode :', S_ISLNK(mode)
- On Windows, Shortcuts appear as files with extension
- @EvgeniSergeev That's because they are just files - possibly a hangover from Windows 9x days when the only file system was FAT/FAT32. See this superuser.com/questions/347930/… for all the types of symbolic/hard links and directory junctions supported on NTFS. That said, I still don't think Python supports them.
- And islink() doesn't work for Windows symlinks, i.e. junctions. So the answer is applicable only for Unix.
- Please refer to this stackoverflow.com/questions/27972776/… answer if you need Windows solution.
- @TheGodfather: directory junction is not a symlink (
- this MAY only finds valid symlink, this MAY not identify a file that is a symlink but is broken. so if you are filtering for real files or all symlinks (good and bad) then ensure you do additional checks
- @2114L3 What does a valid but broken symlink mean? From simple testing with a broken symlink, it seems that
is_symlink()is true, and
exists()is false, which is what I would expect. Can you give a source for your concerns?
- @Sheljohn check the edits on this answer, before my comment exists() was not a part of the answer. using exists is a additional check of which i meant. as using is_symlink alone is not enough as per original version.
- On Windows this is not working correctly for me:
truefor nonexistent files (so