Sed remove all text after and including the third underscore

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I need to edit following string




I tried sed 's/^\(.*\)_.*/\1/' but that produces


Can someone help please?

Delete everything after second underscore, up vote 3 down vote. for the lazy among us: cut -d_ -f1,2 input. gives us: bash-[​514]$ cat input >gi_12_pork_cat ACGT >gi_34_pink_blue CGTA Only for lines that begin with the string >gi_ are we to try to effect the sub _ ---> \n . command which prints upto the first newline if it finds one or the whole of it. I have the following data.txt: 95 flour. 47 water.s etc.. I need to remove everything after the period . in the file to yield something like this: 95 flour 47 water etc..

you can simply use cut for this problem:

cut -d'_' -f1-3 <<<STRING

With your example:

kent$  cut -d'_' -f1-3 <<<"UA399_GTTTCG_L002_R1_001.file.gz"

How to delete all characters in one line after "]" with sed?, echo "] other characters in logs from sendmail." | sed 's/].*//'. So if you have a file full of lines like that you can do sed 's/].*//' filename. By default, sed performs an activity only on the 1st occurence. If n is specifed, sed performs only on the nth occurence of the pattern. The 2nd 'u' of 'Ubuntu' got deleted. 15. To delete everything in a line followed by a character : $ sed 's/a.*//' file Linux Sol Ubuntu Fedor RedH. 16. To remove all digits present in every line of a file :

With GNU sed:

sed -E 's/((_*[^_]*){3}).*/\1/' file

command line - Cutting all the characters after the last /, (Note: This uses the ability of sed to use a separator other than /, in this case |, in the s command) str=xxxx/x/xx/xx/xxxx/x/yyyyy $ echo /$(basename "$str") /yyyyy $ _ 3. Classic solution with awk , that treats / as field separator for both Also, the question isn't quite clear about what should happen with  How do I delete all “words” from the above file which ends with a particular letter (say ‘g’) in each line? The output should be as follows: How do I delete regex-based word using sed or awk under Linux / Unix like operating systems? You can use any standard Unix text editing and processing utility to find and replace/delete words from

This might work for you (GNU sed):

sed 's/_[^_]*//3g' file

Delete the third (or more) set(s) of characters beginning with an underscore and followed by zero or more non-underscores.

'sed' is a stream editor., For example, to replace all occurrences of 'hello' to 'world' in the file 'input.txt': 'c TEXT' Replace (change) lines with TEXT (alternative syntax). Example: stop after printing the second line: $ seq 3 | sed 2q 1 2 This command accepts only one address. A "word" character is any letter or digit or the underscore character. Remove Text after a specific character using FIND&Select command You can also use the Find and Replace command to remove text after a specified character, just refer to the following steps: 1# Click “ HOME “->” Find&Select ”->” Replace… ”, then the window of the Find and Replace will appear.

How to delete all character before certain word, and I would like to delete all the characters before abc so that it becomes "abc 111 222 333 Tagged: sed delete before after character, shell scripts. Discussion  Excel: Remove Everything After a Character (like a question mark, comma or underscore) If you’re looking to use Excel to trim off everything to the right of a question mark, including the question mark (useful for trimming query strings off of URLs), you can use the following formula:

Sed & Awk, Note that the text has been justified with spaces added between words. Remove all leading spaces from each line. 3. Remove the printer underscore line​, the  For removing all texts before or after a specific character with the Find and Replace function, please do as follows. 1. Select the cells you will remove texts before or after a specific character, press Ctrl + H keys to open the Find and Replace dialog.

magic of sed -- find and replace "text" in a string or a file · GitHub, DOS newlines to Unix newlines cannot be done with sed in a DOS center all text in the middle of 79-column width. In method 1,. # spaces add a blank line every 5 lines (after lines 5, 10, 15, 20, etc.) gsed -n '3~7p' # GNU sed only. sed -n  why does sed 's/.* //' show the last word in a line and sed 's/ .*//' show the first word in a line? How is that blank space before or after the ".*" being interpreted in the regex? i would think the first example would delete the first word and the next example would delete the second

  • What is the rule here? Delete all after the 3rd _ including it?
  • I need to remove text after third underscore, including it.
  • Try just awk -F'_' {'print $1"_"$2"_"$3'} <<< "$s", see demo. It is possible with sed, too, but looks worse.
  • This guy (.*\) is greedy, try ([^_]+_[^_]+[^_]+\) assuming your pattern X_X_X. Construction [^_] repaces your dot, basically. I think sed is justified when you need high performance of processing millions of log lines, otherwise use awk as suggested above.
  • Awesome. Thanks