Compare and update dictionary?

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I created two list of dictionaries

dict1 = [
    {'name':'Apple','lot':1234,'old_qty':100}, {'name':'Grape','lot':456,'old_qty':20}

dict2 = [
    {'name':'Apple','lot':1234,'new_qty':50}, {'name':'Grape','lot':456,'new_qty':30}

Desired Output:

[{'name':'Apple','lot':1234,'old_qty':100, 'new_qty':50}, {'name':'Grape','lot':456,'old_qty':20,'new_qty':30}]

How can I do this?

Maybe you are looking for this:

result = [] 
for i,j in zip(dict1, dict2):

the result would be your desired one.

Comparing two dictionaries and checking how many (key, value , UPDATE: I forgot to mention that I have to check how many key, value pairs are equal. share. The update() method takes either a dictionary or an iterable object of key/value pairs (generally tuples). If update() is called without passing parameters, the dictionary remains unchanged. Return Value from update() They update() method updates the dictionary with elements from a dictionary object or an iterable object of key/value pairs.

Assuming that you want to merge two dicts that share a name, try this:

dict1 = [{'name':'Apple','lot':1234,'old_qty':100},{'name':'Grape','lot':456,'old_qty':20}]
dict2 = [{'name':'Apple','lot':1234,'new_qty':50},{'name':'Grape','lot':456,'new_qty':30}]

z = []
common_attr = 'name'
for d1 in dict1:
    for d2 in dict2:
        if d1[common_attr] == d2[common_attr]:
            z.append({**d1, **d2})

If you mean to use another logic for merging, this code snippet could still be helpful.

Hope this helps :)

Comparing nested Python dictionaries with no hassle, Comparing nested Python dictionaries with no hassle. Update: As Stefano Crosta mentioned in the comments, you can simply compare the dictionaries like you  Copy the entire dictionary to new dictionary: dict.copy() update() Update a dictionary by adding a new entry or a key-value pair to an existing entry or by deleting an existing entry. Dict.update([other]) items() Returns a list of tuple pairs (Keys, Value) in the dictionary. dictionary.items() sort() You can sort the elements: dictionary.sort

IMHO, you are looking for something like this perhaps (considering values of the keys name and lot can uniquely identify a dictionary from other):

dict1 = [{'name':'Apple','lot':1234,'old_qty':100},{'name':'Grape','lot':456,'old_qty':20}]
dict2 = [{'name':'Apple','lot':1234,'new_qty':50},{'name':'Grape','lot':456,'new_qty':30}]

dict3 = [d1 for d1 in dict1 for d2 in dict2 if d1["name"]==d2["name"] if d1["lot"]==d2["lot"] if not d1.update(d2)]


How to compare dictionaries in Python, How to compare dictionaries in Python. Use a for loop. Use == Comparing two dictionaries checks each corresponding key-value pair between the two  In this article you can see how to compare two dictionaries in python: The first check is to verify that two dictionaries have equal keys. Below you can find code which check the keys: the result of this code is: Now let say that you want to find the key difference from d1 to d2 and the reverse. This is again a simple operation which can be

Just some layering of for loops

listc = lista[:] 

for i in listb:
    for j in listc:
        if i['name'] == j['name']:
            for x in i:
                if x not in j.keys():
                    j[x] = i[x]

(xenial)vash@localhost:~/python/stack_overflow$ python3.7 
[{'name': 'Apple', 'lot': 1234, 'old_qty': 100, 'new_qty': 50}, {'name': 'Grape', 'lot': 456, 'old_qty': 20, 'new_qty': 30}]

How to compare two different dictionary values in Python, Obviously that's just one form of comparison. You compare dictionary values by accessing the dictionary with the appropriate keys. The expression mydict['a']  update definition: 1. to make something more modern or suitable for use now by adding new information or changing its…. Learn more.

Python script to compare the keys of 2 dictionaries and if equal print , This would be better asked on StackOverflow. Here is the most pythonic way of doing this: d1 = {'a': 10, 'b': 20, 'c': 30, 'd': 40} d2 = {'z': 260, 'd': -12, 'r': 1, 'b': 0}  Merge two or more Dictionaries using **kwargs. Using **kwargs we can send variable length key-value pairs to a function. When we apply ** to a dictionary, then it expands the contents in dictionary as a collection of key value pairs. For example, if we have a dictionary i.e. dict1 = { 'Ritika': 5, 'Sam': 7, 'John' : 10 }

Dictdiffer, Dictdiffer is a helper module that helps you to diff and patch dictionaries. Compare two dictionary/list/set objects, and returns a diff result. Return an iterator with differences (#67); Updates package structure, sorts imports and runs doctests. Python | Increment value in dictionary Sometimes, while working with dictionaries, we can have a use-case in which we require to increment a particular key’s value in dictionary. It may seem a quite straight forward problem, but catch comes when the existence of a key is not known, hence becomes a 2 step process at times.

Dictionary of Information Technology, In computer graphics, update of a rectangular area, comprising the whole or part of the screen. (Philips). Compare LINE UPDATE. rectangular waveguide. SO let’s start learning how to compare two dictionaries in Python and find similarities between them. Similarities between dictionaries in Python. Basically A dictionary is a mapping between a set of keys and values. The keys support the basic operations like unions, intersections, and differences.

  • what did you try? what logic?
  • Look up comprehensions, zip, and merging dictionaries.
  • I am trying to get the quantity of a product before and after of a date. I wrote 2 SQL queries and stored in two dictionaries. Now i need to update the first dictionary with value from dictionary 2.
  • you will probably want to use dict.update but note that you certainly can get the old quantity and the new one with one SQL query
  • @Tryph, could you give me any example, that will be very helpful.
  • what if dict1 will not in the same sequence as second?
  • That's why I wrote maybe, the question's logic is a little unclear.@BearBrown
  • so i think you shoud not to do the answer, IMHO.
  • @KbiR Then my question is that do you need those items that don't share any data?