Order of flow in my simple calculator in Python

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Please help... it might be something quick and easy I hope. I'm 9 days in to Python. I have code for a simple calculator. I cant figure out how to stop the calculator from seeking the values to be calculated if the selection of operations from the choices 1-4 is invalid to start with. If someone selects > 4 (from options 1,2,3,4) it returns 'Invalid input' but then proceeds to ask for value to calculate. How can I stop this from happening? It should cease after 'Invalid input' and be run again.

Here is the code:

#Simple calculator
# define my simple functions

def add(x, y):
    return x + y

def min(x, y):
    return x - y

def mul(x, y):
    return x * y

def div(x, y):
    return x / y

# provide options for operations
print("Please select an operation.")
print("For addition select 1. ")
print("For subtraction select 2.")
print("For multiplication  select 3.")
print("For division select 4.")

option = input("Please enter the number of your option 1, 2, 3, 4:")

# limit option to 1,2,3,4
if option > '4':
    print("Invalid input. Please select 1,2,3 or 4.")

elif option < '5':

    print("Please select an operation.")
    print("For addition select 1. ")
    print("For subtraction select 2.")
    print("For multiplication  select 3.")
    print("For division select 4.")


num1 = float(input( "Please enter the first value: "))
num2 = float(input( "Please enter the second value: "))



if choice == '1':
    print(num1, " + ", num2, "=", add(num1,num2))

elif choice == '2':
    print(num1, " - ", num2, "=", min(num1, num2))

elif choice == '3':
    print(num1, " * ", num2, "=", mul(num1,num2))

elif choice =='4':
    print(num1, " / ", num2, "=", div(num1, num2))

One option is the use the exit command:

exit()

So that the program stops and should be restarted manually.

Another option is to use a while loop like this:

while option not in [1,2,3,4]:
     option = input("Please enter the number of your option 1, 2, 3, 4:")

This forces the user to use a valid input.

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You can put the input part in a while loop:

option = input("Please enter the number of your option 1, 2, 3, 4:")
while option > '4':
  print("Invalid input. Please select 1,2,3 or 4.")  
  option = input("Please enter the number of your option 1, 2, 3, 4:")

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