Making a dictionary that contains (i,i*i) where i is from 1 to n

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Input Format:

Take the number n in a single line.

Output Format:

Print the dictionary d in a single line.

Desired behaviour, for input 8, a dictionary:

{1: 1, 2: 4, 3: 9, 4: 16, 5: 25, 6: 36, 7: 49, 8: 64}

What I tried:

n=int(input())
for i in range(1,n+1):
    a=i*i
    print("{",i,": ",a,"}",sep="")

What it gives me, for input 6:

{1: 1}
{2: 4}
{3: 9}
{4: 16}
{5: 25}
{6: 36}

You can create the dict in a single statement:

d = dict((i,i*i) for i in range(1,n+1))

with n=8 you get

{1: 1, 2: 4, 3: 9, 4: 16, 5: 25, 6: 36, 7: 49, 8: 64}

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You can create the dictionary using a dictionary comprehension:

n = int(input())
d = {i: i * i for i in range(1, n + 1)}
print(d)

for 10 you get

{1: 1, 2: 4, 3: 9, 4: 16, 5: 25, 6: 36, 7: 49, 8: 64, 9: 81, 10: 100}

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If you want to print dictionary, why not just make one and keep it simple instead of making it complicated.

n=int(input())
d = {}
for i in range(1,n+1):
    a=i*i
    d[i] = a
print(d)

And you will get the expected O/P:

{1: 1, 2: 4, 3: 9, 4: 16, 5: 25, 6: 36, 7: 49, 8: 64}

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Comments
  • You are not creating a dictionary but only printing strings
  • If you want to print all those entries in the same line, you have to use string concatenation.