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Following is the code in python:

>>> print("abcdef".find("cd") == "cd" in "abcdef")

I think the output should be True, but it shows False. I want to know the logic behind it.


>>> print("abcdef".find("cd") == "cd" in "abcdef")
False
>>> print("abcdef".find("cd"))
2
>>> print("cd" in "abcdef")
True
>>> print(2 == True)
False
> 

str.find(sub[, start[, end]])

Return the lowest index in the string where substring sub is found within the slice s[start:end]. Optional arguments start and end are interpreted as in slice notation. Return -1 if sub is not found.

The find() method should be used only if you need to know the position of sub. To check if sub is a substring or not, use the in operator:

>>> print(("abcdef".find("cd") != -1) == ("cd" in "abcdef"))
True

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> "abcdef".find("cd")
2
> "cd" in "abcdef"
True
> 2 == True
False

"string".find() will return INDEX if string is found. Therefore you are getting int '2' as this is 3rd position in your given string.

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As shown next, "abcdef".find("cd") return the position of cd in abcdef, while "cd" in "abcdef" return if the first string can be found in the second string, the result is boolean. So the compare == will be false.

(base) C:\Users\nxa13855>python
Python 3.6.5 |Anaconda, Inc.| (default, Mar 29 2018, 13:32:41) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> "abcdef".find("cd")
2
>>> "cd" in "abcdef"
True
>>>

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