An exception of type 'System.Data.SqlClient.SqlException' occurred in System.Data.dll

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I'm a beginner with c#, when I execute the code this error message occurs>>

"An exception of type 'System.Data.SqlClient.SqlException' occurred in System.Data.dll but was not handled in user code

Additional information: Incorrect syntax near '='. "

And this is the code!!

string position;

SqlConnection con = new SqlConnection("server=free-pc\\FATMAH; Integrated Security=True; database=Workflow; ");
con.Open();
SqlCommand cmd = new SqlCommand("SELECT EmpName FROM Employee WHERE EmpID=" + id.Text, con);

SqlDataReader Read = cmd.ExecuteReader();

if (Read.Read()==true)
{
    position = Read[0].ToString();
    Response.Write("User Registration successful");
}
else
{
    Console.WriteLine("No Employee found.");
}

Read.Close(); 

There are some problems with your code. First I advise to use parametrized queries so you avoid SQL Injection attacks and also parameter types are discovered by framework:

var cmd = new SqlCommand("SELECT EmpName FROM Employee WHERE EmpID = @id", con);
cmd.Parameters.AddWithValue("@id", id.Text);

Second, as you are interested only in one value returned from query it is better to use ExecuteScalar MSDN:

var name = cmd.ExecuteScalar();

if (name != null)
{
   position = name.ToString();
   Response.Write("User Registration successful");
}
else
{
    Console.WriteLine("No Employee found.");
}

Last thing is to wrap SqlConnection and SqlCommand into using so any resources used by those would disposed:

string position;

using (SqlConnection con = new SqlConnection("server=free-pc\\FATMAH; Integrated Security=True; database=Workflow; "))
{
  con.Open();

  using (var cmd = new SqlCommand("SELECT EmpName FROM Employee WHERE EmpID = @id", con))
  {
    cmd.Parameters.AddWithValue("@id", id.Text);

    var name = cmd.ExecuteScalar();

    if (name != null)
    {
       position = name.ToString();
       Response.Write("User Registration successful");
    }
    else
    {
        Console.WriteLine("No Employee found.");
    }
  }
}

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I think your EmpID column is string and you forget to use ' ' in your value.

Because when you write EmpID=" + id.Text, your command looks like EmpID = 12345 instead of EmpID = '12345'

Change your SqlCommand to

SqlCommand cmd = new SqlCommand("SELECT EmpName FROM Employee WHERE EmpID='" + id.Text +"'", con);

Or as a better way you can (and should) always use parameterized queries. This kind of string concatenations are open for SQL Injection attacks.

SqlCommand cmd = new SqlCommand("SELECT EmpName FROM Employee WHERE EmpID = @id", con);
cmd.Parameters.AddWithValue("@id", id.Text);

I think your EmpID column keeps your employee id's, so it's type should some numerical type instead of character.

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Try this

SqlCommand cmd = new SqlCommand("SELECT EmpName FROM Employee WHERE EmpID=@id", con);
cmd.Parameters.AddWithValue("id", id.Text);

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An unhandled exception of type 'System.Data.SqlClient.SqlException' occurred in System.Data.dll

    private const string strconneciton = "Data Source=.;Initial Catalog=Employees;Integrated Security=True";
    SqlConnection con = new SqlConnection(strconneciton);

    private void button1_Click(object sender, EventArgs e)
    {

        con.Open();
        SqlCommand cmd = new SqlCommand("insert into EmployeeData (Name,S/O,Address,Phone,CellNo,CNICNO,LicenseNo,LicenseDistrict,LicenseValidPhoto,ReferenceName,ReferenceContactNo) values ( '" + textName.Text + "','" + textSO.Text + "','" + textAddress.Text + "','" + textPhone.Text + "','" + textCell.Text + "','" + textCNIC.Text + "','" + textLicenseNo.Text + "','" + textLicenseDistrict.Text + "','" + textLicensePhoto.Text + "','" + textReferenceName.Text + "','" + textContact.Text + "' )", con);
        cmd.ExecuteNonQuery();
        con.Close();
    }

System.Exception, Zero or more catch blocks are associated with a try block, and each catch block includes a type filter that determines the types of exceptions it handles. When an​  type ArgumentNullException = class inherit ArgumentException. Public Class ArgumentNullException Inherits ArgumentException. SystemException. ArgumentException. ArgumentNullException. Com Visible Attribute Serializable Attribute. An ArgumentNullException exception is thrown when a method is invoked and at least one of the passed arguments is


use try-catch to see real error occurred on you

 try
{
  //Your insert code here
}
catch (System.Data.SqlClient.SqlException sqlException)
{
  System.Windows.Forms.MessageBox.Show(sqlException.Message);
}

Catching Multiple Exception Types and Rethrowing Exceptions with , Rethrowing Exceptions with More Inclusive Type Checking. Handling More Than One Type of Exception. In Java SE 7 and later, a single catch block can handle  type NotImplementedException = class inherit SystemException. Public Class NotImplementedException Inherits SystemException. SystemException. NotImplementedException. Com Visible Attribute Serializable Attribute. The following example throws this exception for a method that has not been developed. static void Main(string[] args) { try


What Is an Exception? (The Java™ Tutorials > Essential Classes , The object, called an exception object, contains information about the error, including its type and the state of the program when the error occurred. Creating an  you can add some extra information to your exception in your class and then when you catch the exception you can control your custom information to identify your exception. this.Data["mykey"]="keyvalue"; //you can add any type of data if you want and then you can get your value. string mystr = (string) err.Data["mykey"];


InvalidCastException Class (System), An InvalidCastException exception is thrown when the conversion of an instance of one type to another type is not supported. For example, attempting to convert  Hi, I am doing text analytics using Microsoft Cognitive Service. I created a custom function following this tutorial.


How to: Use the Try-Catch Block to Catch Exceptions, Each catch block includes the exception type and can contain additional statements needed to handle that exception type. In the following