Detecting ENTER key in C++

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#define enter 13

I have a program like this,

char name[100];
char age[12];
cout << "Enter Name: ";
cin >> name;

cout << "Enter Age: ";
cin >> age;

Now age is a optional field, so user can simply press ENTER key and have that value as NULL. But the problem is, cin doesn't take ENTER key and just stay there waiting for a valid keyboard char or numerical input.

I think the problem is because cin needs a valid input and thus stays there forever.

So i tried below approach to detect ENTER key press for Age.

cout << "Enter Age: ";
if (cin.get() == '\n') {
            cout << "ENTER WAS PRESSED" << endl;
        }

Now as soon as user presses ENTER key after entering a NAME, it goes straight to the IF condition.

I also tried:

getline(cin, age);

But that also simply doesn't stop at cout << "Age: "; waiting for an input from the user.

The user can either a valid age or simply press ENTER key not to enter a age.

For the below Code:

cout << "Enter Name: ";
        cin >> name;

        cout << "Enter Age: ";
        if (cin.get() == '\n') {
            cout << "ENTER WAS PRESSED" << endl;
        }

The Output is:

Enter Name: asdf
Enter Age: ENTER WAS PRESSED

I want the cursor to wait at Enter Age: _

How can i do that?

Have you tried this?:

cout << "Press Enter to Continue";
cin.ignore();

also check out this question

Reading enter key in a loop in C, Why do you call fflushstdin()? If fgetc() returns something different from \n, that character is completely dropped. This should work: char prev = 0  If you are just looking for the "Enter" keypress, then you probably don't care about modifier keys (such as Shift and/or Ctrl), which is why most would use KeyDown instead of Keypress. A second benefit is to answer the question that is almost always asked after implementing any of the other answers: "When I use the referenced code, why does

You are several problems with your code:

  1. you are calling operator>> with char[] buffers without protection from buffer overflows. Use std::setw() to specify the buffer sizes during reading. Otherwise, use std::string instead of char[].

  2. cin >> name reads only the first whitespace-delimited word, leaving any remaining data in the input buffer, including the ENTER key, which is then picked up by cin >> age without waiting for new input. To avoid that, you need to call cin.ignore() to discard any unread data. Otherwise, consider using cin.getline() instead (or std::getline() for std::string), which consumes everything up to and including a linebreak, but does not output the linebreak (you should consider using this for the name value, at least, so that users can enter names with spaces in them).

  3. by default, operator>> skips leading whitespace before reading a new value, and that includes line breaks. You can press ENTER all you want, operator>> will happily keep waiting until something else is entered. To avoid that, you could use std::noskipws, but that causes an unwanted side effect when reading character data - leading whitespace is left in the input buffer, which causes operator>> to stop reading when it reads a whitespace character before any user input is read. So, to avoid that, you can use cin.peek() to check for an entered linebreak before calling cin >> age.

Try something more like this:

#include <iostream>
#include <limits>
#include <iomanip>

char name[100] = {0};
char age[12] = {0};

std::cout << "Enter Name: ";
std::cin >> std::setw(100) >> name;
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
/* or:
if (!std::cin.getline(name, 100))
    std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
*/

std::cout << "Enter Age: ";
if (std::cin.peek() != '\n')
    std::cin >> std::setw(12) >> age;
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');

Or:

#include <iostream>
#include <string>
#include <limits>

std::string name;
std::string age;

std::cout << "Enter Name: ";
std::cin >> name;
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
/* or:
std::getline(std::cin, name);
*/

std::cout << "Enter Age: ";
if (std::cin.peek() != '\n')
    std::cin >> age;
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
/* or:
std::getline(std::cin, age);
*/

How to Use Character Input/Output in C Programming, How do you check if Enter key is pressed in C? If I read any other character instead of enter key it works perfect, but with enter key In some iterations I have to press the enter 2 times. Thanks. EDIT: I'm executing the program through putty on windows and the program is running on a virtualized linux mint on virtual box.

One way to do it is to use getline to read the input, then test the length of the input string. If they only press enter, the length of the line will be 0 since getline ignores newlines by default.

std::string myString = "";

do {
     std::cout << "Press ENTER to exit" << std::endl;
     std::getline(std::cin, myString);
} while (myString.length() != 0);

std::cout << "Loop exited." << std::endl;

Enter key, How do you take input until Enter is pressed in C? Detecting ENTER key in C++. char name[100]; char age[12]; cout << "Enter Name: "; cin >> name; cout << "Enter Age: "; cin >> age; Now age is a optional field, so user can simply press ENTER key and have that value as . But the problem is, cin doesn't take ENTER key and just stay there waiting for a valid keyboard char or numerical input.

You might want to cin into a char variable and then check if it the ENTER key, and if not, continue getting characters and turn them into an int (using character substraction and all that). It is not a very pretty solution but it is the first thing that came into my head.

to take input till enter is pressed, key). scanf() is quite primitive compared to fgets(), and especially known for it's format specifiers being stubborn, and the entire function being "fragile". As you can see in the table ; it’s mentioned that for line feed the ASCII value is 10 and for carriage return the ASCII value is 13 and A line feed means moving one line forward.

Just use:

std::cout << "\nPress Enter to continue"; 
fgetc(stdin);
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');

See more at http://www.cplusplus.com/reference/cstdio/fgetc/

Check if user presses the Enter key, Now i need to add a part where if the user does not want to enter 10 values, they can just press the enter key and 10 defined numbers that i make  Write a simple cpp program which detects a key pressed and its ASCII value with out pressing enter key and using cin>> on press ESC key program should exit. When user press a key its ASCII value should be displayed instantly. You can use any Cpp compiler CodeBlocks Recommended.

What is the ASCII code for an enter key in the C/C++ language , The enter key's ascii value is 0a ,meaning newline ,it is different from Carriage Return (13 or 0d in ascii). Is right or not? 3.7k views. getch is a C function. Later versions of c++ have deprecated the use of the same. They ask you to use _getch instead. There is usually more than one set of arrow keys on your keyboard (one below and on in the numeric pad) so for special cases like these, _getch returns you the base Operation code

Detect Enter Key, Re: Detect Enter key. Posted 05 November 2016 - 08:11 PM. What are you entering at the prompt? Was This Post  EDIT again: Looks like I misuderstood the problem a little.. the KeyPress event is raised with any key you press.. so you need to make sure your only running the code you want for the enter key

How can I check that user press ENTER key in c++ ??, I want to preempt the user if user press ENTER key user will be able to the long​-dead header file <conio.h> in "C" language which no longer 

Comments
  • If you want the cursor to wait at Enter Age: _, then where do you want to see the output?
  • Do you want the cursor to wait at enter age even when user presses enter?