Printing list of list (containing integers) in lexicographic order

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Task:You are given three integers x,y and z along with an integer n. You have to print a list of all possible coordinates where the sum of is not equal to n. Print Print the list in lexicographic increasing order. Below is my code. Works fine except for printing in lexicographic order. Below is my code.Is there a better approach to get lexicographic order of list containing integers?

from itertools import combinations
if __name__ == '__main__':
    x = int(input())
    y = int(input())
    z = int(input())
    n = int(input())
    lst=[[a,b,c]  for b in range(y+1) for c in range(z+1)   for a in range(x+1) ]

for items in combinations(lst,3):
    for nums in items:
       if x!=n and nums not in finallst:

f_finallst= (sorted(map(str,(finallst)))) #converted to string to get lexicographic order
print (f_finallst) 
My result=['[0, 0, 0]', '[0, 0, 1]', '[0, 1, 0]', '[1, 0, 0]', '[1, 1, 1]']
Expected result=[[0, 0, 0], [0, 0, 1], [0, 1, 0], [1, 0, 0], [1, 1, 1]]
       for coords in itertools.product(range(x+1), range(y+1), range(z+1))
       if sum(coords) != n])

Python, It contains well written, well thought and well explained computer science and programming articles, quizzes Python | Sort list of lists by lexicographic value and then length print ( "The list after sorting by value and length " + str (test_list​))  Given an array of unique integer elements, print all the subsets of the given array in lexicographical order. Input Format First line of input contains T - number of test cases.

By using map(str, finallst), you cast each of the element in the list to a str. You want to keep the elements as they are, but use str as a sorting key.

f_finallst= sorted(finallst, key=str)

Hackerrank/ at master · anarayanan86 , You are given three integers X, Y and Z representing the dimensions of a cuboid along with an. # integer N. You have to print a list of all possible coordinates given by (i, j, k) on a 3D grid where Print the list in lexicographic increasing order. I am supposed to 'sort' the numbers in the array such that the resulting array has the integers ordered in a lexicographic manner (i.e they are sorted based on their string representations. Here "123" is the string representation of 123). Please note that the output should contain integers only, not their string equivalents.

x = int(input())
y = int(input())
z = int(input())
n = int(input())
lists=[[i,j,k] for i in range(x+1)
               for j in range(y+1)
               for k in range(z+1) if (i+j+k)!=n]

Printing numbers in lexicographic order, Okay, let me point out some stylistic things first: Doing traceback.print_exc() in an except block feels somewhat odd. Either you hide the stack  Given an integer N, print numbers from 1 to N in lexicographic order. Details: To be implemented without using character conversion (or Strings). Scanner input = new Scanner (;

Orderings, are 123, 132, 213, 231, 312, and 321. When applied to subsets, two subsets are ordered by their smallest elements. Print all permutations in sorted (lexicographic) order. Given a string, print all permutations of it in sorted order. For example, if the input string is “ABC”, then output should be “ABC, ACB, BAC, BCA, CAB, CBA”.

Sort the words in lexicographical order in Python, mean that we want to arrange them first by the first letter of the word. Then for the words whose first letter is the same, we arrange them within that group by the second letter and so on just like in a language's dictionary(not the data structure). Rearrange a string in sorted order followed by the integer sum. Given a string containing uppercase alphabets and integer digits (from 0 to 9), the task is to print the alphabets in the order followed by the sum of digits. Examples: Input : AC2BEW3 Output : ABCEW5 Alphabets in the lexicographic order followed by the sum of integers(2 and 3).

Lexicographic Order, Given an integer N, print numbers from 1 to N in lexicographic order. for (int i = 1;i<n;i++){ list.add(""+i); } Collections.sort(list); for (String j: list){ The idea is before printing the next number, exhaust all the number with the current prefix. # Enter your code here. Read input from STDIN. Print output to STDOUT: X = int (raw_input ()) Y = int (raw_input ()) Z = int (raw_input ()) N = int (raw_input ()) ans = [[i, j, k] for i in range (X + 1) for j in range (Y + 1) for k in range (Z + 1) if i + j + k!= N] print ans

  • Just do finallst.sort() without converting the lists to strings.
  • When you say lexicographical order, you mean character by character or element by element? By example, which of these is ordered: [[100, 0], [90, 0]] or [[90, 0], [100, 0]]
  • You may add some explanation to improve the usefulness of your answer.
  • @MosesKoledoye It's self explanatory
  • You don't need string at all!
  • For lexicographical order, yes, suppose there is a two-digit number in the list, then it makes a difference
  • Ok, Fair enough. But converting the entire list to string might have you comparing numbers with commas or spaces for cases where there are more than one digit leading to unintended results.
  • @MosesKoledoye Although, I added a comment to ask OP to be more specific about what they mean by lexicographical order.
  • Explain your answer. What is happening here?