## java Arrays.sort 2d array

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SO,

I am looknig to sort the following array based on the values of [][0]

double[][] myArr = new double[mySize][2];

so for ex, myArr contents is:

1 5 13 1.55 12 100.6 12.1 .85

I want it to get to :

1 5 12 100.6 12.1 .85 13 1.55

I am looking to do this without have to implement my own sort. Any help is appreciated, thanks.

Use Overloaded **Arrays#Sort(T[] a, Comparator c)** which takes Comparator as the second argument.

double[][] array= { {1, 5}, {13, 1.55}, {12, 100.6}, {12.1, .85} }; java.util.Arrays.sort(array, new java.util.Comparator<double[]>() { public int compare(double[] a, double[] b) { return Double.compare(a[0], b[0]); } });

**Sorting a 2D Array according to values in any given column in Java ,** The Idea is to use Arrays.sort in Java. filter_none. edit close. play_arrow. link brightness_4 code java Arrays.sort 2d array. Ask Question Asked 7 years, 1 month ago. Active 7 days ago. Viewed 115k times 40. 16. SO, I am looknig to sort the following array based on

Welcome Java 8:

Arrays.sort(myArr, (a, b) -> Double.compare(a[0], b[0]));

**Row wise sorting in 2D array,** Java code to sort 2D matrix row-wise. import java.io.*;. import java.util.Arrays;. public class Sort2DMatrix {. static int sortRowWise( int m[][]). {. // One by one sort public static void sort(int[] arr, int from_Index, int to_Index) arr - the array to be sorted from_Index - the index of the first element, inclusive, to be sorted to_Index - the index of the last element, exclusive, to be sorted This method doesn't return any value. A Java program to sort an array of integers in ascending order.

You need to implement a `Comparator<Double[]>`

like so:

public static void main(String[] args) throws IOException { final Double[][] doubles = new Double[][]{{5.0, 4.0}, {1.0, 1.0}, {4.0, 6.0}}; final Comparator<Double[]> arrayComparator = new Comparator<Double[]>() { @Override public int compare(Double[] o1, Double[] o2) { return o1[0].compareTo(o2[0]); } }; Arrays.sort(doubles, arrayComparator); for (final Double[] arr : doubles) { System.out.println(Arrays.toString(arr)); } }

Output:

[1.0, 1.0] [4.0, 6.0] [5.0, 4.0]

**How to sort a two-dimensional array on column values in java / How ,** There is no direct method to sort a two dimensional array in java. array index you need to sort since a 2d array in java is an array of arrays. Use Arrays.sort() method to sort an array of objects. The objects must implement the Comparable interface which will decide their sorting order. All elements in the array must implement the Comparable interface. All elements in the array must be mutually comparable and must not throw a ClassCastException while comparing.

Although this is an old thread, here are two examples for solving the problem in Java8.

sorting by the first column ([][0]):

double[][] myArr = new double[mySize][2]; // ... java.util.Arrays.sort(myArr, java.util.Comparator.comparingDouble(a -> a[0]));

sorting by the first two columns ([][0], [][1]):

double[][] myArr = new double[mySize][2]; // ... java.util.Arrays.sort(myArr, java.util.Comparator.<double[]>comparingDouble(a -> a[0]).thenComparingDouble(a -> a[1]));

**How to sort two dimensional array in Java?,** There is an overloaded sort method in java.util.Arrays class which takes two arguments: the array to sort and a java.util.Comparator object. Arrays.sort(newEmployees, 0, 3, new EmployeeAgeComparator()); 6. Conclusion. So far we have gone through examples of sorting arrays using various variants of the java.util.Arrays.sort() method, including usages of the Comparable and Comparator interfaces. Key points to remember are:

import java.util.*; public class Arrays2 { public static void main(String[] args) { int small, row = 0, col = 0, z; int[][] array = new int[5][5]; Random rand = new Random(); for(int i = 0; i < array.length; i++) { for(int j = 0; j < array[i].length; j++) { array[i][j] = rand.nextInt(100); System.out.print(array[i][j] + " "); } System.out.println(); } System.out.println("\n"); for(int k = 0; k < array.length; k++) { for(int p = 0; p < array[k].length; p++) { small = array[k][p]; for(int i = k; i < array.length; i++) { if(i == k) z = p + 1; else z = 0; for(;z < array[i].length; z++) { if(array[i][z] <= small) { small = array[i][z]; row = i; col = z; } } } array[row][col] = array[k][p]; array[k][p] = small; System.out.print(array[k][p] + " "); } System.out.println(); } } }

Good Luck

**How would one use Arrays.sort on a multidimensional array of ints ,** Well, in Java a multidimensional array is an array of arrays and there is no direct method of sorting a multi dimensional array such as Arrays.sort for 1 d array. The following article 2D Arrays in Java provides an outline for the creation of 2D arrays in java. An array is one of the data types in java. Array is a group of homogeneous data items which has a common name. Array consists of data of any data type. 2-dimensional array structured as a matrix. Matrix is a combination of rows and columns.

**7 Examples to Sort An Array in Java,** In order to sort different types of arrays in Java, you can use any of the array in Java, you can use any this method to sort multidimensional array in Java also. The java.util.Arrays.sort(int[]) method sorts the specified array of ints into ascending numerical order. Declaration. Following is the declaration for java.util.Arrays.sort() method. public static void sort(int[] a) Parameters. a − This is the array to be sorted. Return Value. This method does not return any value. Exception. NA. Example

**Sort 2D Array VI - LabVIEW 2018 Help,** Rearranges the rows or columns of a 2D array by sorting the elements in the specified column or row in ascending order. This VI rearranges the elements in the For any two non-null int arrays a and b such that Arrays.equals(a, b), it is also the case that Arrays.hashCode(a) == Arrays.hashCode(b). The value returned by this method is the same value that would be obtained by invoking the hashCode method on a List containing a sequence of Integer instances representing the elements of a in the same order.

**Java Solutions (Greedy and Sort 2d Array),** Java Solutions (Greedy and Sort 2d Array). 1 end[i] = intervals[i][1]; } Arrays.sort(start); Arrays.sort(end); int[] Last = new Sort 2d Array: 6 ms When the sub-array length reaches a minimum granularity, the sub-array is sorted using the appropriate Arrays.sort method. If the length of the specified array is less than the minimum granularity, then it is sorted using the appropriate Arrays.sort method. The algorithm requires a working space no greater than the size of the specified range of the original array.

##### Comments

- That subtraction probably won't work; you should use
`Double.compare(b[0], a[0])`

instead. - How can you pass 2D array as the argument when sort expects a 1D array? This didn't work for me.
- @LouisWasserman I'm assuming they were using something like
`a[0] - b[0]`

before you said that. Why wouldn't it work? It's actually a common sorting idiom for numbers. - Because a) it only even sort of works for ints, b) if you try it on big enough ints you get overflow and it explodes on you. Never use that idiom when the values you're comparing might be negative.
- Not if they're big enough, is the point. If your numbers are always nonnegative, it's okay, but if you compare
`Integer.MAX_VALUE`

to`-1`

you'll get overflow. It's just better to do the right thing from the start.