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I don't understand some example in Java.

public class Pair {
  private int a;
  private int b;
  public Pair(){


  public Pair(int x, int y) {
    a = x;
    b = y;


Second class

   public class First extends Pair {
     public First(int x, int y) {

     public static void main(String[] args) {
       Pair pair = new Pair(10,11);
       String s = "It is equal " + pair;


Because it's used concatenation of strings, automatically it will be called method toString() from class Pair, so the result should be: "It is equal (10,11)". It prints me location in memory why? Maybe I should call method like:

public void show(){
System.out.println(a + "" + b);

However in example there isn't method show(), there is only String s like above.

This is right as jvm is calling default implementation of toString from object class which prints the identity hashcode. if you want the output like this then you can override toString() method inside Pair class like below:

protected String toString{
    return "("+a+","+b+")";

After implementing this you will get the expected result as you have overriden the toString() method.

It's recommended approach to override the toString method as it helps in debugging and provide the meaningful logs.

How to print out an object array that has parameters?, Put toString() in class Employee, perhaps with @Override tag above it. @​Override public String toString() { return name + ", " + age + ", " +  The New-Object cmdlet creates an instance of a .NET Framework or COM object. You can specify either the type of a .NET Framework class or a ProgID of a COM object. By default, you type the fully qualified name of a .NET Framework class and the cmdlet returns a reference to an instance of that class.

Since you didnt override ToString() method of class, it will be calling the Object class toString() which itself gives you the meomory location of Object.

So the solution is you have to override the toString() in your class and put your required snippet there, so that at time of printing the object ref. your overridden toString() will be called and expected outcome will be displayed.


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Overide toString with your expected result in your Pair class. Like

    public String toString() {
        int c=a+b;
        return "Pair =" + c;

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